/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 If \(a>0\) and \(b>0,\) th... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(a>0\) and \(b>0,\) then the eccentricity of the hyperbola $$\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1 \quad \text { or } \quad \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1$$ is the number \(\frac{\sqrt{a^{2}+b^{2}}}{a} .\) Find the eccentricity of the hyperbola whose equation is given. $$6(y-2)^{2}=18+3(x+2)^{2}$$

Short Answer

Expert verified
Answer: \(\frac{\sqrt{5}}{\sqrt{3}}\)

Step by step solution

01

Rewrite the given equation in the standard form

We are given the hyperbola equation as \(6(y-2)^2=18+3(x+2)^2\). Our task is to rewrite it in the standard form of a hyperbola centered at \((h, k)\). To do this, we need to divide both sides of the equation by the constant on the left side \((6)\). This will isolate the subtraction between the two squared terms. $$\frac{(y-2)^2}{3} = 3+\frac{(x+2)^2}{2}$$ Now, subtract 3 from both sides of the equation: $$\frac{(y-2)^2}{3} - 3 - \frac{(x+2)^2}{2} = 0$$ Finally, add \(\frac{(x+2)^2}{2}\) to both sides to get the desired form: $$\frac{(y-2)^2}{3} - \frac{(x+2)^2}{2} = 1$$
02

Identify the values of a and b

Now that we have the equation in the standard form, we can identify the values of a and b. The equation can be written as: $$\frac{(y-2)^{2}}{\frac{3}{1}}-\frac{(x+2)^{2}}{\frac{2}{1}}=1$$ Comparing it to the standard hyperbola form, we can determine that \(a^2 = 3\) and \(b^2 = 2\). Therefore, \(a = \sqrt{3}\) and \(b = \sqrt{2}\).
03

Find the eccentricity of the hyperbola

Using the formula for eccentricity \(\frac{\sqrt{a^2 + b^2}}{a}\), substitute the values of a and b: $$\frac{\sqrt{(\sqrt{3})^2 + (\sqrt{2})^2}}{\sqrt{3}}$$ Simplify the expression: $$\frac{\sqrt{3 + 2}}{\sqrt{3}}=\frac{\sqrt{5}}{\sqrt{3}}$$ The eccentricity of the hyperbola is \(\frac{\sqrt{5}}{\sqrt{3}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are curves obtained by intersecting a cone with a plane. These shapes include circles, ellipses, parabolas, and hyperbolas, each defined by the angle of the intersecting plane relative to the cone's angle. A hyperbola arises when the plane cuts through both halves of the double cone, at an angle parallel to the cone's side.

Mathematically, conic sections are represented by quadratic equations in two variables, and each type has a unique standard form equation that simplifies analysis and solution of related problems. Understanding the properties of each conic allows us to explore their many applications in physics, engineering, astronomy, and many other fields.
Hyperbola Standard Form
The standard form of a hyperbola is a way to write its equation so that we can easily identify its key features, such as the center, vertices, co-vertices, and asymptotes. For a hyperbola centered at the point \(h, k\), the standard forms are:
\[ \frac{(x-h)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1 \] for a horizontal hyperbola, and
\[ \frac{(y-k)^{2}}{a^{2}} - \frac{(x-h)^{2}}{b^{2}} = 1 \] for a vertical hyperbola.

In these equations, \(a\) represents the distance from the center to a vertex along the 'transverse axis', and \(b\) is the distance from the center to a co-vertex on the 'conjugate axis'. The ability to rewrite a hyperbola's equation into standard form is essential for analyzing its geometry and behavior.
Eccentricity Formula
Eccentricity is a measure of how much a conic section deviates from being circular. It is a dimensionless number that uniquely characterizes each conic. For hyperbolas, eccentricity \(e\) is always greater than 1 and is given by the formula: \[ e = \frac{\sqrt{a^{2} + b^{2}}}{a} \]

Where \(a\) and \(b\) are the same values used in the standard form of the hyperbola's equation. For our exercise, once the equation has been transformed into the standard form and \(a\) and \(b\) have been identified, the formula is applied to find the eccentricity. The eccentricity value helps in determining how 'stretched' the hyperbola is along its transverse axis.
Hyperbola Equation Transformation
Transforming a hyperbola's equation into its standard form may involve several steps, such as dividing by constants, completing the square, and rearranging terms. This transformation is crucial for extracting useful information and simplifying further calculations.
For instance, in the provided exercise, the hyperbola's equation is first divided by the constant on the left side to facilitate a comparison with the standard form. Then, it's a matter of adjusting the terms so we can easily read off the values for \(a\) and \(b\).

Through equation transformation, we can also easily identify the hyperbola's center and direction (horizontal or vertical), which helps in sketching its graph and understanding its properties.

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Most popular questions from this chapter

The given curve is part of the graph of an equation in \(x\) and \(y .\) Find the equation by eliminating the parameter. $$x=3 \cos t, \quad y=3 \sin t, \quad 0 \leq t \leq 2 \pi$$

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