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Solve the equation by any method. $$3 t^{2}-11 t-20=0$$

Short Answer

Expert verified
Question: Solve the quadratic equation \(3t^2 - 11t - 20 = 0\) using the quadratic formula. Answer: The solutions for the given equation are \(t_1 = 5\) and \(t_2 = -\frac{4}{3}\).

Step by step solution

01

Calculate the discriminant \(\Delta\)

We need to find the discriminant for the given quadratic equation. Given $$a = 3, b = -11, c = -20$$, we have: $$\Delta = b^2 - 4ac$$ $$\Delta = (-11)^2 - 4(3)(-20)$$ $$\Delta = 121 + 240$$ $$\Delta = 361$$
02

Find the square root of the discriminant

Now, we need to find the square root of the discriminant: $$\sqrt{\Delta} = \sqrt{361} = 19$$
03

Calculate the two possible values for t using the quadratic formula

In this step, we'll use the quadratic formula with the values we found: $$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$ Insert the values for a, b, and \(\Delta\): $$t = \frac{-(-11) \pm 19}{2(3)}$$ Now, solve for the two possible values of t: $$t_1 = \frac{11 + 19}{6} = \frac{30}{6} = 5$$ $$t_2 = \frac{11 - 19}{6} = \frac{-8}{6} = -\frac{4}{3}$$
04

State the solution

The solutions for the given equation are: $$t_1 = 5$$$$t_2 = -\frac{4}{3}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discriminant
The discriminant is a valuable part of solving quadratic equations. It is represented by the Greek letter \( \Delta \) and is found using the formula \( \Delta = b^2 - 4ac \). This formula uses the coefficients from the standard form of a quadratic equation \( ax^2 + bx + c = 0 \).

The discriminant helps us determine the nature of the roots without actually solving the equation. Here's what different values of the discriminant tell us:
  • If \( \Delta > 0 \): There are two distinct real roots. The equation touches the x-axis at two points.
  • If \( \Delta = 0 \): There is one real root. The equation touches the x-axis at exactly one point, meaning the parabola is tangent to the axis.
  • If \( \Delta < 0 \): There are no real roots, but two complex roots. In this case, the parabola does not intersect the x-axis at all.


In our problem, the discriminant was calculated as 361, which is positive, indicating that there are two distinct real roots for the quadratic equation \( 3t^2 - 11t - 20 = 0 \).
Quadratic Formula
The quadratic formula is a universal method that allows us to find the roots of any quadratic equation. This powerful formula is expressed as:
  • \( x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \)
This formula arises from the process of completing the square, but it conveniently provides a quick path to the solution.

The "\( \pm \)" symbol in the formula indicates that there are often two solutions to a quadratic equation - one from adding the square root of the discriminant and another from subtracting it. This aligns with the fact that quadratic graphs, or parabolas, can intersect the x-axis at two points.

In our exercise, with coefficients \( a = 3 \), \( b = -11 \), and \( \Delta = 361 \), we substitute these values into the quadratic formula to find:
  • \( t_1 = \frac{-(-11) + \sqrt{361}}{6} \)
  • \( t_2 = \frac{-(-11) - \sqrt{361}}{6} \)
After calculating, these give us the roots \( t_1 = 5 \) and \( t_2 = -\frac{4}{3} \).
Roots of a Quadratic Equation
The roots of a quadratic equation are the solutions where the equation equals zero. These roots indicate the points at which the parabola intersects the x-axis.

There are generally two roots for a quadratic equation since it's a second-degree polynomial. They can be categorized based on the discriminant:
  • Real and distinct roots: These occur when \( \Delta > 0 \). The graph intersects the x-axis at two points.
  • Real and equal roots: These occur when \( \Delta = 0 \). The graph just touches the x-axis at one point.
  • Complex roots: These happen when \( \Delta < 0 \). There is no real intersection with the x-axis, but complex numbers allow for solutions.


In our specific problem, since the discriminant was 361, we determined the equation \( 3t^2 - 11t - 20 = 0 \) has two real and distinct roots. After applying the quadratic formula, we identified these roots as \( t_1 = 5 \) and \( t_2 = -\frac{4}{3} \). These roots are the solutions that solve the original quadratic equation.

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