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Show that \(u(x, y)=x y\) is harmonic in \(\mathbb{R}^{2}\). Find the conjugate harmonic function \(v(x, y)\) in \(\mathbb{R}^{2}\). Write \(u+i v\) in terms of \(z\).

Short Answer

Expert verified
The given function \(u(x, y) = xy\) is harmonic. Its conjugate harmonic function is \(v(x, y) = xy - \frac{1}{2}x^2\). Expressing \(u + iv\) in terms of \(z\) yields \(\frac{1}{2}r^2e^{i\theta} - \frac{ir^2}{2}e^{2i\theta}\).

Step by step solution

01

Prove that \(u(x, y) = xy\) is a harmonic function

For a function to be harmonic, it must satisfy the Laplace's equation, which is \( \nabla^2u = 0\). First, find the second order partial derivatives of \(u(x, y) = xy\), i.e., \(u_{xx}\) and \(u_{yy}\). Here, \(u_{xx} = 0\) and \(u_{yy} = 0\). Adding these values, \(u_{xx} + u_{yy} = 0 + 0 = 0\). Hence, \(u(x, y) = xy\) is a harmonic function.
02

Find the conjugate harmonic function \(v(x, y)\)

To find the conjugate function, known also as the harmonic conjugate, use the Cauchy-Riemann equations which are as follows: \(u_x = v_y\) and \(u_y = -v_x\). The partial derivatives of \(u(x, y) = xy\) are \(u_x = y\) and \(u_y = x\). So by integrating \(v_y = u_x = y\), we get \(v(x, y) = xy + g(x)\), where \(g(x)\) is an arbitrary function of \(x\). Next integrate \(-u_y = -x = v_x\) to get \(v(x, y) = -\frac{1}{2}x^2 + h(y)\), where \(h(y)\) is an arbitrary function of \(y\). Comparing these two expressions for \(v(x, y)\), we can see that \(v(x, y) = xy - \frac{1}{2}x^2\)
03

Express \(u + iv\) in terms of \(z\)

If we substitute \(x = r\cos\theta\) and \(y = r\sin\theta\) (which are the expressions for \(x\) and \(y\) in terms of polar coordinates), and \(z = x + iy = r(\cos\theta + i\sin\theta) = re^{i\theta}\), then we can write \(u + iv = x y - i\frac{1}{2}x^2 = r^2\cos\theta\sin\theta - \frac{ir^2}{2}\cos^2\theta = \frac{1}{2}r^2e^{i\theta} - \frac{ir^2}{2}e^{2i\theta}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplace's equation
Understanding the concept of a harmonic function begins with Laplace's equation, which in two-dimensional Cartesian coordinates is expressed as \( abla^2u = \frac{\partial^2u}{\partial x^2} + \frac{\partial^2u}{\partial y^2} = 0 \). A function \( u(x, y) \) that satisfies this condition is said to be harmonic. This means that at any point on the function, the average value of \( u \) over any circle centered at that point is equal to the value of \( u \) at the center.

For our exercise, the function \( u(x, y) = xy \) is shown to be harmonic because both second order partial derivatives \( u_{xx} \) and \( u_{yy} \) equal to zero when calculated. As a result, their sum, \( u_{xx} + u_{yy} \) equals zero, fulfilling the condition of the Laplace's equation. Harmonic functions have a variety of applications including physics and engineering, particularly in potential theory and electrostatics.
Harmonic Conjugate
Once we establish a function is harmonic, like \( u(x, y) = xy \) in our example, we can then find its harmonic conjugate. A harmonic conjugate \( v(x, y) \) is a function that, when paired with \( u \) forms an analytic function \( f(z) = u(x, y) + iv(x, y) \). This analytic function represents a complex potential where the real part is the original harmonic function and the imaginary part is the conjugate.

The determination of \( v \) from \( u \) is guided by the Cauchy-Riemann equations. In solving the exercise, integration of partial derivatives of \( u \) leads to \( v(x, y) \) that satisfies both the Cauchy-Riemann equations and compatibility with the harmonic condition. Therefore, the conjugate function \( v(x, y) = xy - \frac{1}{2}x^2 \) provides a complex function together with \( u \) where both are harmonic, having real and imaginary parts that are mutually exclusive.
Cauchy-Riemann equations
The Cauchy-Riemann equations are at the heart of complex analysis, serving as a fundamental set of conditions for differentiability of a complex function. These equations are expressed as \( u_x = v_y \) and \( u_y = -v_x \) for a function \( f(z) = u(x, y) + iv(x, y) \).

In the given problem, application of the Cauchy-Riemann equations allows us to find the harmonic conjugate \( v \) corresponding to \( u \). The process involves integrating the partial derivatives of \( u \) with respect to \( x \) and \( y \) in order to find expressions for \( v \). Through this, we ensure both \( u \) and \( v \) are in harmony, satisfying Laplace's equation independently. The Cauchy-Riemann equations not only prove the differentiability of complex functions but also provide a link between harmonic functions and the intriguing field of complex analysis.

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