Chapter 1: Problem 3
Show that \(z \bar{z}\) is always a real number.
Short Answer
Expert verified
\( z \bar{z} = a^2 + b^2 \) is a real number.
Step by step solution
01
Define a Complex Number
A complex number \( z \) can be expressed in the form \( z = a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit with the property \( i^2 = -1 \).
02
Identify the Conjugate
The conjugate of a complex number \( z = a + bi \) is \( \bar{z} = a - bi \). It changes the sign of the imaginary part of the complex number.
03
Multiply the Complex Number and Its Conjugate
Compute \( z \bar{z} \) using the previously defined \( z \) and \( \bar{z} \): \[ z \bar{z} = (a + bi)(a - bi). \]
04
Use Algebraic Expansion
Expand the expression \((a + bi)(a - bi)\) using the formula \((x + y)(x - y) = x^2 - y^2\):\[ z \bar{z} = a^2 - (bi)^2. \]
05
Simplify the Expression
Since \( (bi)^2 = b^2i^2 \), and \( i^2 = -1 \), we have \( (bi)^2 = -b^2 \). Substitute back into the expression: \[ z \bar{z} = a^2 + b^2. \]
06
Conclude with Real Number Property
The expression \( a^2 + b^2 \) is the sum of squares of real numbers \( a \) and \( b \), which is always a non-negative real number.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conjugate of a Complex Number
In the fascinating world of complex numbers, every complex number has a mirror version called its conjugate. For a complex number expressed as \( z = a + bi \), where \( a \) and \( b \) are real numbers and \( i \) is the imaginary unit, the conjugate \( \bar{z} \) is simply \( a - bi \). This operation involves flipping the sign of the imaginary part, leaving the real part unchanged.
- Complex number example: \( z = 3 + 4i \) with conjugate \( \bar{z} = 3 - 4i \)
- More broadly, for any complex number \( z = a + bi \), conjugate \( \bar{z} \) is \( a - bi \).
Multiplication of Complex Numbers
Multiplying complex numbers might seem tricky at first, but it's a lot like expanding expressions when we first learned about real numbers. When we multiply a complex number by its conjugate, we use a special algebraic formula:
- If \( z = a + bi \) and \( \bar{z} = a - bi \), then the product is \( z\bar{z} = (a + bi)(a - bi) \).
Real Numbers
Real numbers are the numbers we use every day - from counting apples to measuring distances. They include all the numbers along the number line: integers, fractions, and even pi or square roots.
This expression results in a real number because it's simply a sum of squares, which can never be negative. Whether we have \( a^2 \) or \( b^2 \), both are inherently non-negative, so their addition remains non-negative.
By observing the multiplication result of \( z\bar{z} \), we notice it confirms the magnitude or modulus of the complex number and is always a real number.
- Real numbers make up the set of all rational and irrational numbers.
This expression results in a real number because it's simply a sum of squares, which can never be negative. Whether we have \( a^2 \) or \( b^2 \), both are inherently non-negative, so their addition remains non-negative.
By observing the multiplication result of \( z\bar{z} \), we notice it confirms the magnitude or modulus of the complex number and is always a real number.
Imaginary Unit
The imaginary unit, denoted as \( i \), is a mathematical concept that enables us to extend the real number system. Its defining property is that when it is squared, it equals -1: \( i^2 = -1 \). This simple property allows mathematicians to expand the number system to include solutions to equations that don't have real-number solutions, such as the square root of a negative number.
When multiplying complex numbers, understanding \( i^2 = -1 \) is crucial for simplifying products like \( (bi)^2 \), since it turns into \( -b^2 \). This transformation is a cornerstone for proving that \( z\bar{z} \) results in a real number when complex numbers are involved.
- Key property: \( i^2 = -1 \)
- Example: \( \sqrt{-1} = i \)
When multiplying complex numbers, understanding \( i^2 = -1 \) is crucial for simplifying products like \( (bi)^2 \), since it turns into \( -b^2 \). This transformation is a cornerstone for proving that \( z\bar{z} \) results in a real number when complex numbers are involved.