Chapter 3: Problem 12
Show (a) $$ \int_{-\infty}^{\infty} \frac{x^{2}}{\left(x^{2}+a^{2}\right)^{2}} d x=\frac{\pi}{2 a}, \quad(a>0) $$ (b) $$ \int_{-\infty}^{\infty} \frac{d x}{\left(x^{2}+4 x+5\right)^{2}}=\frac{\pi}{2} $$ (c) \(\int_{0}^{\infty} \frac{d x}{\left(x^{2}+a^{2}\right)\left(x^{2}+b^{2}\right)}=\frac{\pi}{2 a b(a+b)}, \quad(a, b>0)\).
Short Answer
Step by step solution
Problem (a) – Identify the integral and use substitution
Problem (a) – Evaluate the new integral
Problem (b) – Complete the square and identify integral form
Problem (b) – Use known integral result
Problem (c) – Decompose into partial fractions
Problem (c) – Evaluate each partial fraction integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integral Calculus
- A definite integral computes the net area between a function and the x-axis over an interval.
- In our context, the goal is to evaluate integrals with infinite limits, extending from negative to positive infinity.
- Integration techniques like substitution help simplify the process.
Contour Integration
- A contour is any path or curve in the complex plane. These might include straight lines, circles, or combinations of different types of paths.
- The method uses path integrals where the function is integrated along these contours.
- In the exercise, a semicircular contour in the upper half-plane is employed to evaluate the integral from negative to positive infinity.
Residue Theorem
- The residue of a function at a pole is essentially the coefficient of \( (z - a)^{-1} \) in its Laurent series expansion around that point.
- The contour integral of a function over a closed path equals \( 2\pi i \) times the sum of the residues inside the contour.
- In our example, the integral is solved by focusing on the pole at \( z = i \), within the chosen contour.
Partial Fraction Decomposition
- It’s especially useful when dealing with integrands consisting of polynomial ratios.
- The method involves breaking down the function into a sum of terms whose integrals are easier to manage.
- In exercise part (c), the decomposition separates \( \frac{1}{(x^2+a^2)(x^2+b^2)} \) into simpler fractions.