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In Exercises \(41-48\), assume that the range of arcsecant is \(\left[0, \frac{\pi}{2}\right) \cup\left[\pi, \frac{3 \pi}{2}\right)\) and that the range of arccosecant is \(\left(0, \frac{\pi}{2}\right] \cup\left(\pi, \frac{3 \pi}{2}\right]\) when finding the exact value. $$ \operatorname{arccsc}(-1) $$

Short Answer

Expert verified
The exact value of \( \operatorname{arccsc}(-1) \) is \( \frac{3\pi}{2} \).

Step by step solution

01

Identify the Function

The function we are dealing with is the arccosecant, denoted as \( \operatorname{arccsc} \). We are asked to find the value of \( \operatorname{arccsc}(-1) \).
02

Understand the Definition of Arccosecant

The \( \operatorname{arccsc}(x) \) is the inverse of the cosecant function. The cosecant function is the reciprocal of the sine function, so if \( y = \operatorname{arccsc}(x) \), then \( \csc(y) = x \). This implies that \( \sin(y) = \frac{1}{x} \).
03

Consider the Domain and Range

The range of \( \operatorname{arccsc} \) is given as \( \left(0, \frac{\pi}{2}\right] \cup \left(\pi, \frac{3\pi}{2}\right] \). We need to find a value of \( y \) within this range such that \( \csc(y) = -1 \).
04

Find the Value within the Range

Knowing \( \csc(y) = -1 \), we have \( \sin(y) = \frac{1}{-1} = -1 \). The sine function equals -1 at \( y = \frac{3\pi}{2} \), which lies within the given range \( \left(\pi, \frac{3\pi}{2}\right] \).
05

Conclusion with the Exact Value

Since \( \sin\left(\frac{3\pi}{2}\right) = -1 \), the angle \( y = \frac{3\pi}{2} \) satisfies the requirement for \( \operatorname{arccsc}(-1) \). Thus, \( \operatorname{arccsc}(-1) = \frac{3\pi}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

arccosecant
The term "arccosecant" refers to the inverse of the cosecant function. This inverse function is denoted as \( \operatorname{arccsc} \). The purpose of an inverse trig function like arccosecant is to determine the angle whose cosecant is a given number. For instance, if you have \( y = \operatorname{arccsc}(x) \), it means \( \csc(y) = x \).
One must understand that \( \csc(y) \) is the reciprocal of \( \sin(y) \). So, \( \operatorname{arccsc}(x) = y \) is equivalent to saying that the sine of \( y \) is \( \frac{1}{x} \). In handling problems involving the arccosecant function, understanding this relationship is crucial.
When solving \( \operatorname{arccsc}(-1) \), it boils down to asking for an angle where the reciprocal of sine equals \(-1\). Finding that specific angle within the correct range is the goal of these exercises.
range of functions
The range of a function refers to the set of all possible output values. In trigonometry, the range is particularly important because we need to know where specific functions can produce a valid result.
For inverse trigonometric functions like \( \operatorname{arccsc} \), the range is carefully defined. In this case, the exercise specifies the range for \( \operatorname{arccsc} \) as \( \left(0, \frac{\pi}{2}\right] \cup \left(\pi, \frac{3\pi}{2}\right] \). This range ensures that for every value plugged in, there is a unique result.
For \( \operatorname{arccsc} \), it is important to note that values are not just any angle but specifically those within the mentioned intervals. By enforcing this constraint, we avoid ambiguity in solutions, which is crucial for precision in mathematical reasoning.
sine function
The sine function, \( \sin(x) \), is one of the fundamental functions in trigonometry. It represents the y-coordinate of a point on the unit circle as the angle \( x \) varies.In relation to the arccosecant function, recall that \( \csc(x) = \frac{1}{\sin(x)} \). Therefore, finding values for the arccosecant involves manipulating the sine function, specifically by taking its reciprocal.
For example, when solving \( \operatorname{arccsc}(-1) \), one actually searches for an angle \( y \) where \( \sin(y) = -1 \). In the unit circle, this condition holds true precisely at certain strategic angles like \( \frac{3\pi}{2} \), falling exactly within our pre-defined valid range for \( \, \operatorname{arccsc} \, \).
Understanding sine is fundamental because it connects to how each angle within a circle translates into a value based on height — either positive, negative, or zero — on the unit circle.
exact values
When working with inverse trigonometric functions, finding exact values instead of decimal approximations is often necessary. Exact values help in achieving greater accuracy and understanding of the problem at hand.
In the given problem, finding \( \operatorname{arccsc}(-1) \) means finding an angle that fits this exact reciprocal sine condition. The answer, \( \frac{3\pi}{2} \), is an exact value derived from known properties of the unit circle, which provides deterministic precision.
Exploring exact values requires familiarity with common angles and their sine counterparts on the unit circle. Once you establish which angles work, especially within the given range, you attain certainty about the accuracy of the result.
Using exact values not only streamlines the process but reinforces the core trigonometric principles students need to grasp for solving these kinds of problems consistently.

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Most popular questions from this chapter

In Exercises \(165-184\), rewrite the quantity as algebraic expressions of \(x\) and state the domain on which the equivalence is valid. $$ \tan (2 \arcsin (x)) $$

In Exercises \(107-118\), assume that the range of arcsecant is \(\left[0, \frac{\pi}{2}\right) \cup\left[\pi, \frac{3 \pi}{2}\right)\) and that the range of arccosecant is \(\left(0, \frac{\pi}{2}\right] \cup\left(\pi, \frac{3 \pi}{2}\right]\) when finding the exact value. $$ \operatorname{arcsec}\left(\sec \left(\frac{5 \pi}{6}\right)\right) $$

In Exercises \(131-154\), find the exact value or state that it is undefined. $$ \csc \left(\arcsin \left(\frac{3}{5}\right)\right) $$

In Exercises \(119-130\), assume that the range of arcsecant is \(\left[0, \frac{\pi}{2}\right) \cup\left(\frac{\pi}{2}, \pi\right]\) and that the range of arccosecant is \(\left[-\frac{\pi}{2}, 0\right) \cup\left(0, \frac{\pi}{2}\right]\) when finding the exact value. $$ \operatorname{arccsc}\left(\csc \left(\frac{5 \pi}{4}\right)\right) $$

A tag-and-release program to study the Sasquatch population of the eponymous Sasquatch National Park is begun. From a 200 foot tall tower, a ranger spots a Sasquatch lumbering through the wilderness directly towards the tower. Let \(\theta\) denote the angle of depression from the top of the tower to a point on the ground. If the range of the rifle with a tranquilizer dart is 300 feet, find the smallest value of \(\theta\) for which the corresponding point on the ground is in range of the rifle. Round your answer to the nearest hundreth of a degree.

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