/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Graph one cycle of the given fun... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph one cycle of the given function. State the period of the function. $$ y=\frac{1}{3} \tan (-2 x-\pi)+1 $$

Short Answer

Expert verified
The period of the function is \( \frac{\pi}{2} \).

Step by step solution

01

Identify the Tangent Function

The given function is \( y = \frac{1}{3} \tan(-2 x - \pi) + 1 \). It is a transformation of the tangent function \( y = \tan(x) \). The tangent function has a period of \( \pi \).
02

Determine the Period

The general form for the period of \( y = \tan(bx) \) is \( \frac{\pi}{|b|} \). Here, \( b = -2 \), so the period is \( \frac{\pi}{|-2|} = \frac{\pi}{2} \). This means one full cycle of the tangent function repeats every \( \frac{\pi}{2} \) units.
03

Account for Horizontal and Vertical Shifts

The function \( y = \frac{1}{3} \tan(-2 x - \pi) + 1 \) includes a horizontal phase shift and a vertical shift. The phase shift is determined by solving \( -2x - \pi = 0 \). Solving gives \( x = -\frac{\pi}{2} \), indicating a phase shift to the left by \( \frac{\pi}{2} \) units. The vertical shift is \(+1\), moving the entire graph up by 1 unit.
04

Graph the Function

To graph, start by plotting the phase-shift point \((x = -\frac{\pi}{2}, y = 1)\). From there, since the period is \( \frac{\pi}{2} \), plot asymptotes at \( x = -\frac{\pi}{2} \) and \( x = 0 \), and symmetric points around them based on the tangent shape. Use \( y = 1 \) as the new center line, so peaks and troughs will occur \( \frac{1}{3} \) unit above and below this line.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Tangent Function
The tangent function, represented by the equation \( y = \tan(x) \), is a fundamental trigonometric function renowned for its periodic oscillating behavior. Unlike the sine and cosine functions which are known for their smooth and continuous wave-like patterns, the tangent function exhibits a different pattern, characterized by intersecting the x-axis at regular intervals and having vertical asymptotes where the function is undefined.

Some unique characteristics of the tangent function include:
  • Intersects the x-axis at integer multiples of \( \pi \).
  • The function has no maximum or minimum points, as its values extend to positive and negative infinity near its vertical asymptotes.
  • Unlike sine and cosine, it is an odd function, meaning it is symmetrical about the origin.
In the context of transformations, when you have a function like \( y = \tan(bx + c ) + d \), each parameter (b, c, and d) can modify its graph: b affects the period, c causes horizontal shifts, and d results in vertical shifts.
Determining the Period of a Function
The period of a trigonometric function is the interval over which the function's pattern repeats. For the basic tangent function \( y = \tan(x) \), this period is \( \pi \), reflecting how it repeats its vertical cycloid path every \( \pi \) units along the x-axis.

To find the period of a transformed tangent function of the form \( y = \tan(bx) \), use the formula:
  • Period = \( \frac{\pi}{|b|} \), where b is the coefficient of x.
For \( y = \frac{1}{3}\tan(-2x - \pi) + 1 \), the coefficient \( b = -2 \) and thus, the period becomes \( \frac{\pi}{|-2|} = \frac{\pi}{2} \).

This reduced period signifies that the rapid oscillating cycle of the tangent occurs twice as often compared to the standard function, completing a full cycle every \( \frac{\pi}{2} \) units.
Graph Transformations and Their Effects
Graph transformations involve modifying the basic graph of a function to produce shifts, stretches, shrinks, or reflections. When examining \( y = \frac{1}{3} \tan(-2x - \pi) + 1 \), we see multiple transformations applied to the standard tangent function.
  • Amplitude Modification: The coefficient \( \frac{1}{3} \) scales the tangent values, decreasing the steepness of rise and fall.
  • Horizontal Phase Shift: Determined by solving the equation \( -2x - \pi =0 \), results in a shift to the left by \( \frac{\pi}{2} \) units.
  • Vertical Shift: Occurs by adding \(+1\), lifting the entire graph up by 1 unit, thereby adjusting the centerline of the oscillation.
These transformations interplay to create a modified graph where patterns repeat more frequently, the centerline is shifted upwards, and the graph is less steep due to the coefficient \( \frac{1}{3} \). Visualizing these changes requires considering both the original function shape and the effect of each transformation layer applied.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.