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Suppose that the density of female insects during the first year is 500 per acre with \(r=0.8\). (a) Write a recursive sequence that describes these data, where \(a_{n}\) denotes the female insect density during year \(n\). (b) Find the six terms \(a_{1}, a_{2}, a_{3}, \ldots, a_{6}\). Interpret the results. (c) Find a formula for \(a_{n}\).

Short Answer

Expert verified
(a) Recursive formula: \(a_{n+1} = a_n(1 + 0.8)\), starting with \(a_1 = 500\). (b) Terms: 500, 900, 1620, 2916, 5249, 9448. (c) Formula: \(a_n = 500 \times (1.8)^{n-1}\).

Step by step solution

01

Define the Recursive Formula

To define the recursive sequence for the density of female insects, we note that the population in year \(n+1\) depends on the population in year \(n\). Given the growth rate \(r = 0.8\), the recursive formula can be expressed as:\[a_{n+1} = a_n (1 + r)\]Using the initial condition \(a_1 = 500\), the sequence begins.
02

Calculate the Second Term

We will use the recursive formula to find \(a_2\):\[a_2 = a_1 (1 + r) = 500(1 + 0.8) = 500 imes 1.8 = 900\]So, the second year's female insect density is 900 per acre.
03

Calculate the Third Term

Continuing the sequence to find \(a_3\):\[a_3 = a_2 (1 + r) = 900(1 + 0.8) = 900 imes 1.8 = 1620\]The third year density is 1620 per acre.
04

Calculate the Fourth Term

Now find \(a_4\):\[a_4 = a_3 (1 + r) = 1620(1 + 0.8) = 1620 imes 1.8 = 2916\]The fourth year density is 2916 per acre.
05

Calculate the Fifth Term

Next, calculate \(a_5\):\[a_5 = a_4 (1 + r) = 2916(1 + 0.8) = 2916 imes 1.8 = 5248.8\]The fifth year density is approximately 5249 per acre.
06

Calculate the Sixth Term

Finally, find \(a_6\):\[a_6 = a_5 (1 + r) = 5248.8(1 + 0.8) = 5248.8 imes 1.8 = 9447.84\]The sixth year density is approximately 9448 per acre.
07

Interpret the Results

The density of female insects per acre grows rapidly due to the constant growth rate of 0.8. This shows exponential growth, where each year's population multiplies by a factor of 1.8, showing significant increase over the six years.
08

Derive the Closed Formula

To find a closed formula, recognize this as a geometric sequence where each term is a multiple of the previous term by \(1.8\):\[a_n = a_1 imes (1.8)^{n-1}\]Using the given initial condition \(a_1 = 500\):\[a_n = 500 imes (1.8)^{n-1}\]This formula can calculate the density for any given year \(n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Sequences
Geometric sequences are a fascinating type of sequence where each term is a constant multiple of the previous one. This makes them very predictable, which is useful in many real-world scenarios, including finance and natural phenomena. A geometric sequence is defined by its first term and a common ratio, which tells us how much each term should be multiplied by to get the next one. For instance, if the first term is 500 and the ratio is 1.8, then the sequence would develop by continually multiplying each term by 1.8. This is why the formula for the nth term in a geometric sequence looks like this: \[a_n = a_1 \times r^{n-1}\] Where \(a_1\) is the initial value and \(r\) is the common ratio. In the context of our problem with the female insects, this predictable pattern allows us to quickly calculate the insect density for any given year. Geometric sequences are foundational in expressing patterns of growth, such as compound interest in finance or biological growth where conditions remain constant.
Population Growth Model
A population growth model helps us understand how populations change over time. It models how living things multiply by taking into account birth rates, death rates, and other factors affecting growth. In the simplest form, populations grow when the birth rate exceeds the death rate. For predictable increases, we often use an exponential model. In our insect problem, the model uses a recursive relation to describe the population changes. This means that each year’s population depends only on the previous year’s value and a growth factor, which in this case is consistent (a ratio of 1.8). The recursive formula \(a_{n+1} = a_n \times (1 + r)\) describes this scenario. If initial population counts are accurate, such models can effectively predict future population sizes, barring any changes in the growth factors like environment or resources. Using such models is key in fields like ecology, agriculture, and conservation, where understanding population changes is crucial.
Exponential Growth
Exponential growth can be seen in situations where the growth rate of a quantity is proportional to its current value, leading to growth that accelerates as the quantity increases. It’s characterized by the fact that the increase each time period is always a constant multiple of the previous amount. For our insect population, an exponential growth pattern is evident because the growth rate, stated as a decimal, remains constant at 0.8. When expressed in terms of the growth factor, which is \(1.8\) in our sequence, it shows how much each term of our sequence multiplies by to get the next. Unlike linear growth, which adds the same amount each time period, exponential growth compounds the growth, resulting in much faster increases. This rapid growth can be beneficial, such as in investments or detrimental if referring to invasive species or diseases. Understanding exponential growth is crucial in planning, forecasting, and managing resources or populations effectively.

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