Chapter 8: Problem 22
Use the binomial theorem to expand each expression. $$ \left(x+y^{2}\right)^{3} $$
Short Answer
Expert verified
The expanded form is \(x^3 + 3x^2y^2 + 3xy^4 + y^6\).
Step by step solution
01
Understand the Binomial Theorem
The binomial theorem states that \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\), where \(\binom{n}{k}\) is the binomial coefficient. In this expression, \(a = x\), \(b = y^2\), and \(n = 3\).
02
Determine the Binomial Coefficients
The binomial coefficients for \(n = 3\) are \(\binom{3}{0} = 1\), \(\binom{3}{1} = 3\), \(\binom{3}{2} = 3\), and \(\binom{3}{3} = 1\). You can find these using Pascal's triangle or the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
03
Expand the Expression
Substitute the values of \(a\), \(b\), and the binomial coefficients into the theorem.\[(x+y^2)^3 = \binom{3}{0}x^3(y^2)^0 + \binom{3}{1}x^2(y^2)^1 + \binom{3}{2}x^1(y^2)^2 + \binom{3}{3}x^0(y^2)^3\]Simplify each term using the coefficients calculated earlier.
04
Simplify Each Term
Compute each term individually:- \(\binom{3}{0}x^3(y^2)^0 = 1 \cdot x^3 \cdot 1 = x^3\)- \(\binom{3}{1}x^2(y^2)^1 = 3 \cdot x^2 \cdot y^2 = 3x^2y^2\)- \(\binom{3}{2}x^1(y^2)^2 = 3 \cdot x \cdot (y^2)^2 = 3xy^4\)- \(\binom{3}{3}x^0(y^2)^3 = 1 \cdot 1 \cdot y^6 = y^6\)
05
Write the Final Expanded Form
Combine all simplified terms to write the final expanded expression:\[x^3 + 3x^2y^2 + 3xy^4 + y^6\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
Binomial coefficients are the numbers that arise in the expansion of a binomial expression. These coefficients can be found using the formula \(inom{n}{k} = \frac{n!}{k!(n-k)!}\), where \(n\) is the power the binomial is raised to, and \(k\) is the term number in the expansion.
- The factorial symbol \(!\) means to multiply a series of descending natural numbers. For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).
- In the expression \((x + y^2)^3\), the coefficients for each term were found as \(1, 3, 3, 1\), using this formula.
- These coefficients can also be visualized using Pascal's Triangle for a quick look-up.
Polynomial Expansion
Polynomial expansion involves expressing a power of a binomial \((a + b)^n\) as a sum of terms using the binomial theorem. This helps when you need to simplify expressions and work with powers of binomials.
- The binomial theorem formula \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\) provides a systematic method to obtain the expanded form.
- For \((x + y^2)^3\), substituting \(a = x\), \(b = y^2\), and \(n = 3\) into the formula gives four terms in the expanded polynomial.
- Each term is found by calculating powers of \(a\) and \(b\), then multiplying by the corresponding binomial coefficient.
Pascal's Triangle
Pascal's Triangle is a triangular array where each row represents the coefficients of the expanded form of a binomial power. This is named after the French mathematician Blaise Pascal.
- Each number in the triangle is the sum of the two numbers directly above it from the previous row.
- For example, the third row of Pascal's Triangle is \(1, 3, 3, 1\), which matches the coefficients found for \((x + y^2)^3\).
- It provides an easy way to discover binomial coefficients without the need for calculations.