Chapter 6: Problem 18
( Refer to Examples 3-5.) LetA be the given matrix. Find \(A^{-1}\) without a calculator. $$ \left[\begin{array}{ll} 1 & 3 \\ 2 & 5 \end{array}\right] $$
Short Answer
Expert verified
The inverse of the matrix \( \begin{bmatrix} 1 & 3 \\ 2 & 5 \end{bmatrix} \) is \( \begin{bmatrix} -5 & 3 \\ 2 & -1 \end{bmatrix} \).
Step by step solution
01
Determine the matrix size
The given matrix \( A \) is a 2x2 matrix, which is necessary to find its inverse using the determinant method.
02
Find the determinant
Calculate the determinant of matrix \( A \) using the formula for a 2x2 matrix: \[ \text{det}(A) = ad - bc \] For \( A = \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \), \[ \text{det}(A) = (1)(5) - (3)(2) = 5 - 6 = -1 \]
03
Confirm if the matrix is invertible
Since the determinant is \(-1\) (non-zero), matrix \( A \) is invertible. We can proceed to find the inverse.
04
Apply the formula for the inverse of a 2x2 matrix
For a generic 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the inverse is given by \[ A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \] Substitute the values from matrix \( A \) to find \( A^{-1} \):\[ A^{-1} = \frac{1}{-1} \begin{bmatrix} 5 & -3 \ -2 & 1 \end{bmatrix} = \begin{bmatrix} -5 & 3 \ 2 & -1 \end{bmatrix} \]
05
Verify the inverse
Multiply \( A \) by its calculated inverse \( A^{-1} \) to verify if the result is the identity matrix \( I \): \[ A \cdot A^{-1} = \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \begin{bmatrix} -5 & 3 \ 2 & -1 \end{bmatrix} = \begin{bmatrix} (1)(-5) + (3)(2) & (1)(3) + (3)(-1) \ (2)(-5) + (5)(2) & (2)(3) + (5)(-1) \end{bmatrix} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \] The result is the identity matrix, confirming that the calculated inverse is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant of a Matrix
The determinant of a matrix is a special number that helps in understanding some properties of the matrix, such as if it is invertible. For a 2x2 matrix, the determinant can be easily calculated. It serves as a quick check to see whether we can find the inverse of a matrix or not.
In general, the determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is given by the formula:
In our example, the matrix \( \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \) has a determinant of \(-1\), meaning it is invertible. The negative and non-zero value here does not matter for invertibility, as any non-zero value indicates the matrix can be inverted.
In general, the determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is given by the formula:
- \( \text{det}(A) = ad - bc \)
In our example, the matrix \( \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \) has a determinant of \(-1\), meaning it is invertible. The negative and non-zero value here does not matter for invertibility, as any non-zero value indicates the matrix can be inverted.
2x2 Matrix
A 2x2 matrix is one that has two rows and two columns. This type of matrix is particularly nice to work with for a few reasons:
Dealing with a 2x2 matrix is essentially where many students start learning about the concept of matrices, making it a critical stepping stone in understanding more complex structures.
- It is simple and easy to handle because it has fewer numbers to work with compared to larger matrices.
- Both the determinant and the inverse have straightforward methods for computation.
Dealing with a 2x2 matrix is essentially where many students start learning about the concept of matrices, making it a critical stepping stone in understanding more complex structures.
Invertible Matrix
An invertible matrix, sometimes called a non-singular matrix, is one that has an inverse. Not all matrices are invertible, though. In general, for a matrix to be invertible, its determinant must not be zero.
For the 2x2 matrix \( A = \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \), its determinant is \(-1\). Since this value is non-zero, we confirm that \( A \) is invertible.
The inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) can be calculated with the formula:
For the 2x2 matrix \( A = \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \), its determinant is \(-1\). Since this value is non-zero, we confirm that \( A \) is invertible.
The inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) can be calculated with the formula:
- \( A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \)
Identity Matrix
The identity matrix acts as the number one in matrix mathematics. When you multiply any matrix by an identity matrix, the initial matrix remains unchanged.
For a 2x2 matrix, the identity matrix is:
In our example, when we multiplied \( A \) by its inverse, \( A^{-1} \), we got:
For a 2x2 matrix, the identity matrix is:
- \( I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \)
In our example, when we multiplied \( A \) by its inverse, \( A^{-1} \), we got:
- \( A \cdot A^{-1} = \begin{bmatrix} 1 & 3 \ 2 & 5 \end{bmatrix} \cdot \begin{bmatrix} -5 & 3 \ 2 & -1 \end{bmatrix} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \)