Chapter 5: Problem 108
Graph \(f\) and state its domain. $$f(x)=\ln \left(x^{2}+1\right)$$
Short Answer
Expert verified
The domain of \(f(x) = \ln(x^2 + 1)\) is all real numbers \((-\infty, \infty)\). The graph is smooth, continuous, and increases with increasing \(|x|\).
Step by step solution
01
Understand the Nature of the Function
The function given is \( f(x) = \ln(x^2 + 1) \). This is a natural logarithmic function, where \( \ln \) denotes the natural logarithm, which is defined for positive arguments. However, the expression \( x^2 + 1 \) in the function ensures that the argument of the logarithm is always positive regardless of the value of \( x \).
02
Determine the Domain
Since the expression inside the logarithm, \( x^2 + 1 \), is always positive for any real number \( x \) (as \( x^2 \) is always non-negative and adding 1 makes it strictly positive), the domain of \( f(x) \) is all real numbers. Therefore, the domain is \( (-\infty, \infty) \).
03
Graph the Function
To graph \( f(x) = \ln(x^2 + 1) \), note that as \( x \) approaches 0, \( f(x) \) approaches \( \ln(1) = 0 \). As \( |x| \) becomes very large, \( x^2 + 1 \) becomes large, and thus \( f(x) \) increases but at a decreasing rate. The curve has a smooth gradient increasing from left to right passing through the y-axis at \( (0, 0) \).
04
Conclude with Domain and Graph Behavior
The graph of \( f(x) \) will show a smooth, continuous curve that approaches 0 at \( x = 0 \) and gently increases as \( |x| \) increases. The curve does not have any breaks, asymptotes, or undefined points within the real number domain.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of Functions
When we talk about the domain of a function, we are essentially asking: "What values can we input into this function?" For the natural logarithmic function presented, namely \( f(x) = \ln(x^2 + 1) \), we need to ensure that anything under the logarithm sign is positive.
Here's the good news: the expression inside the logarithm, \( x^2 + 1 \), is always positive no matter what real number you choose for \( x \). This is because squaring any real number, \( x^2 \), yields a non-negative result, and adding 1 makes it strictly positive.
Thus, there are no restrictions on \( x \) and it can take any real value. The domain is therefore all real numbers, expressed in interval notation as \( (-\infty, \infty) \). Here’s a summary of the key points:
Here's the good news: the expression inside the logarithm, \( x^2 + 1 \), is always positive no matter what real number you choose for \( x \). This is because squaring any real number, \( x^2 \), yields a non-negative result, and adding 1 makes it strictly positive.
Thus, there are no restrictions on \( x \) and it can take any real value. The domain is therefore all real numbers, expressed in interval notation as \( (-\infty, \infty) \). Here’s a summary of the key points:
- For the function \( f(x) = \ln(x^2 + 1) \), the argument \( x^2 + 1 \) is positive for every real \( x \).
- This means \( x \) has no restrictions, leading to a domain of all real numbers.
- In interval notation, we express this as \((-\infty, \infty)\).
Graphing Functions
Graphing a function helps us visually comprehend how the function behaves across its domain. For the natural logarithmic function \( f(x) = \ln(x^2 + 1) \), there are some key aspects to consider when sketching its graph.
Firstly, as \( x \) approaches 0, the expression\( x^2 + 1 \) equals 1, thus \( f(x) \) approaches \( \ln(1) \) which is 0. This means the graph touches the y-axis at the point\((0, 0)\). Secondly, as the absolute value of \( x \) becomes large, \( x^2 + 1 \) increases, resulting in \( f(x) \) rising slowly.
The graph is smooth and continuous, increasing without bound as \( |x| \) becomes very large. Key takeaways for graphing this function:
Firstly, as \( x \) approaches 0, the expression\( x^2 + 1 \) equals 1, thus \( f(x) \) approaches \( \ln(1) \) which is 0. This means the graph touches the y-axis at the point\((0, 0)\). Secondly, as the absolute value of \( x \) becomes large, \( x^2 + 1 \) increases, resulting in \( f(x) \) rising slowly.
The graph is smooth and continuous, increasing without bound as \( |x| \) becomes very large. Key takeaways for graphing this function:
- The graph passes through the origin at \((0, 0)\).
- As \( x \) moves away from zero in either direction, \( x^2 + 1 \) grows, causing \( f(x) \) to slowly rise.
- The increase is gradual, reflecting the logarithmic nature of the function.
Mathematical Continuity
Mathematical continuity describes a function's unbroken, smooth curve without gaps, jumps, or visible interruptions. For the function \( f(x) = \ln(x^2 + 1) \), understanding its continuity gives us insights into its behavior.
Since the expression \( x^2 + 1 \) is positive for all real \( x \), this ensures that the function \( \ln(x^2 + 1) \) is defined everywhere in its domain. Consequently, there are no points of discontinuity or breaks, meaning that the graph is a continuous curve. The smooth and gradual increase of the graph further emphasizes its continuity. Here's what to note about this function's continuity:
Since the expression \( x^2 + 1 \) is positive for all real \( x \), this ensures that the function \( \ln(x^2 + 1) \) is defined everywhere in its domain. Consequently, there are no points of discontinuity or breaks, meaning that the graph is a continuous curve. The smooth and gradual increase of the graph further emphasizes its continuity. Here's what to note about this function's continuity:
- The function is continuous over all real numbers, thanks to \( x^2 + 1 > 0 \) for all real \( x \).
- There are no jumps, gaps, or asymptotes in the graph; it flows naturally.
- As a natural logarithmic function with a positive argument, it remains well-behaved.