Chapter 4: Problem 71
Solve the equation. Check your answers. $$ n^{-2}+3 n^{-1}+2=0 $$
Short Answer
Expert verified
The solutions are \( n = -1 \) and \( n = -\frac{1}{2} \). Both checked out successfully.
Step by step solution
01
Substitute Variables
Let's make a substitution to simplify the equation. Let \( x = n^{-1} \). Then \( n^{-2} = (n^{-1})^2 = x^2 \). Substitute into the equation: \( x^2 + 3x + 2 = 0 \).
02
Solve the Quadratic Equation
Now solve the quadratic equation \( x^2 + 3x + 2 = 0 \). This factors as \( (x + 1)(x + 2) = 0 \). Thus, \( x + 1 = 0 \) or \( x + 2 = 0 \). This gives the solutions \( x = -1 \) or \( x = -2 \).
03
Reverse the Substitution
Recall that \( x = n^{-1} \). Therefore, \( n = x^{-1} \). So if \( x = -1 \), then \( n = -1^{-1} = -1 \). And if \( x = -2 \), then \( n = -2^{-1} = -\frac{1}{2} \).
04
Verify the Solutions in the Original Equation
Substitute \( n = -1 \) back into the original equation: \( (-1)^{-2} + 3(-1)^{-1} + 2 = 1 - 3 + 2 = 0 \). Substitute \( n = -\frac{1}{2} \) into the original equation: \( (-\frac{1}{2})^{-2} + 3(-\frac{1}{2})^{-1} + 2 = 4 - 6 + 2 = 0 \). Both solutions satisfy the original equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a type of polynomial equation that take the general form: \[ ax^2 + bx + c = 0 \], where \( a \), \( b \), and \( c \) are constants and \( a eq 0 \). These equations are called 'quadratic' because they involve the square of the variable, usually written as \( x^2 \). They can be solved using various methods such as factoring, the quadratic formula, or completing the square.
The key feature of a quadratic equation is its degree of 2, which typically means it has two solutions. These solutions are the values of \( x \) that make the equation true, and they can be real or complex numbers. Real solutions can be further categorized into distinct or repeated values.
The key feature of a quadratic equation is its degree of 2, which typically means it has two solutions. These solutions are the values of \( x \) that make the equation true, and they can be real or complex numbers. Real solutions can be further categorized into distinct or repeated values.
- If the solutions are real and distinct, the graph of the quadratic equation will intersect the x-axis at two points.
- If they are repeated, the graph will touch the x-axis at just one point.
- If the solutions are complex, the graph does not intersect the x-axis.
Substitution Method
The substitution method is a technique often used to simplify complex equations, making them easier to solve. The main idea is to replace a complicated expression with a symbol or different expression, reducing the complexity of the original equation. In practice, this involves identifying a part of the equation that can be isolated and solved separately.
In our particular exercise, we used substitution to change variables from \( n^{-1} \) to \( x \). This transformed the given equation \( n^{-2} + 3n^{-1} + 2 = 0 \) into the simpler quadratic form \( x^2 + 3x + 2 = 0 \). By substituting \( x = n^{-1} \), where \( n^{-2} = (n^{-1})^2 = x^2 \), we effectively recast the problem into a more manageable form.
In our particular exercise, we used substitution to change variables from \( n^{-1} \) to \( x \). This transformed the given equation \( n^{-2} + 3n^{-1} + 2 = 0 \) into the simpler quadratic form \( x^2 + 3x + 2 = 0 \). By substituting \( x = n^{-1} \), where \( n^{-2} = (n^{-1})^2 = x^2 \), we effectively recast the problem into a more manageable form.
- This technique is particularly useful when dealing with exponents or when different variable forms need to be unified.
- After solving the simplified equation, the substitution is reversed to solve for the original variable.
- This ensures the solutions obtained are relevant to the initial problem context.
Factoring
Factoring is a method used to solve quadratic equations by expressing them as a product of linear factors. This approach is effective when dealing with equations that can be neatly factored into pairs of binomials. Factoring involves rewriting the original equation in a way that reveals the solutions, where we set each factor equal to zero and solve for the variable.
For the equation \( x^2 + 3x + 2 = 0 \), we factored it as \( (x + 1)(x + 2) = 0 \). This factorization tells us that the equation has solutions where each factor equals zero: \( x + 1 = 0 \) or \( x + 2 = 0 \). Solving these gives \( x = -1 \) or \( x = -2 \).
For the equation \( x^2 + 3x + 2 = 0 \), we factored it as \( (x + 1)(x + 2) = 0 \). This factorization tells us that the equation has solutions where each factor equals zero: \( x + 1 = 0 \) or \( x + 2 = 0 \). Solving these gives \( x = -1 \) or \( x = -2 \).
- Factoring works best when the equation's roots are rational numbers.
- If the quadratic isn't easily factorable, other methods such as the quadratic formula might be required.
- Ensuring that the product and sum of the terms match the original quadratic terms is key to verifying correct factorization.