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Evaluate the expression by hand. $$ \left(8^{-1 / 3}+27^{-1 / 3}\right)^{2} $$

Short Answer

Expert verified
The evaluated expression is \(\frac{25}{36}\).

Step by step solution

01

Simplify the fractional exponents

Begin by separately evaluating the terms with negative fractional exponents. The expression is \(8^{-1/3} + 27^{-1/3}\). To evaluate these, use the rule that \(a^{-1/b} = \frac{1}{a^{1/b}}\). For \(8^{-1/3}\), we have:\ \(\frac{1}{8^{1/3}} = \frac{1}{2}\) because \(8^{1/3} = 2\). Similarly, for \(27^{-1/3}\), we have:\ \(\frac{1}{27^{1/3}} = \frac{1}{3}\) because \(27^{1/3} = 3\). So, \(8^{-1/3} + 27^{-1/3} = \frac{1}{2} + \frac{1}{3}\).
02

Find the common denominator and add fractions

To add \(\frac{1}{2}\) and \(\frac{1}{3}\), first find a common denominator. The least common denominator of 2 and 3 is 6. Convert the fractions: \(\frac{1}{2} = \frac{3}{6}\) and \(\frac{1}{3} = \frac{2}{6}\). Now add them together: \(\frac{3}{6} + \frac{2}{6} = \frac{5}{6}\).
03

Square the result

Now, take the result from Step 2 and square it. We have \(\left(\frac{5}{6}\right)^2\). Use the formula for squaring a fraction: \(\left(\frac{a}{b}\right)^2 = \frac{a^2}{b^2}\).This gives us: \(\left(\frac{5}{6}\right)^2 = \frac{5^2}{6^2} = \frac{25}{36}\).
04

Final result

Combine everything together. From Step 3, we found that the evaluated expression \(\left(8^{-1/3} + 27^{-1/3}\right)^2\) simplifies to \(\frac{25}{36}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fractional Exponents
Fractional exponents, also known as rational exponents, are a way to express roots and powers using fractions. When you see an expression like \(a^{-1/b}\), this means you should take the \(b\)-th root of \(a\) and then take the reciprocal because of the negative sign.
For instance, with \(8^{-1/3}\), the expression is exploring the cube root of 8. The cube root of 8 is 2, which can be expressed as \(8^{1/3} = 2\). Given the negative exponent, we find the reciprocal: \(8^{-1/3} = \frac{1}{8^{1/3}} = \frac{1}{2}\).
Similarly, for \(27^{-1/3}\), the cube root is 3, resulting in \(27^{1/3} = 3\) and so \(27^{-1/3} = \frac{1}{3}\). Understanding this helps simplify expressions involving roots and reciprocals.
Common Denominator
A common denominator is essential when adding fractions. This is the shared multiple of the denominators of the fractions involved.
In the expression \(\frac{1}{2} + \frac{1}{3}\), the denominators are 2 and 3. To find their least common denominator, determine the smallest number that both denominations divide into evenly. For 2 and 3, that number is 6.
  • Convert \(\frac{1}{2}\) into \(\frac{3}{6}\)
  • Convert \(\frac{1}{3}\) into \(\frac{2}{6}\)
Using a common denominator simplifies the process of adding fractions, which is crucial for calculations like this.
Addition of Fractions
Adding fractions involves combining the numerators over a shared denominator. Once you have a common denominator, adding fractions is straightforward.
With fractions \(\frac{3}{6}\) and \(\frac{2}{6}\), it's simple because both are over the same denominator, 6. You only need to add the numerators:
  • \(3 + 2 = 5\)
Thus, \(\frac{3}{6} + \frac{2}{6} = \frac{5}{6}\).
This step of aligning fractions under a common denominator simplifies complex fractional arithmetic, paving the way for further operations like multiplication or squaring.
Squaring Fractions
Squaring a fraction involves both the numerator and the denominator being squared individually. This step converts the fraction to a power-of-two expression.
Taking \(\left(\frac{5}{6}\right)^2\) as an example, you square both components:
  • The numerator: \(5^2 = 25\)
  • The denominator: \(6^2 = 36\)
Thus, \(\left(\frac{5}{6}\right)^2 = \frac{25}{36}\). This shows how squaring is applied to fractions, maintaining their form but altering the values.

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