Chapter 3: Problem 19
Exercises \(1-28:\) Solve the quadratic equation. Check your answers for Exercises \(1-12\). $$ \frac{1}{2} x^{2}-3 x+\frac{1}{2}=0 $$
Short Answer
Expert verified
The solutions are \(x = 3 + 2\sqrt{2}\) and \(x = 3 - 2\sqrt{2}\).
Step by step solution
01
Identify the Coefficients
The given quadratic equation is \(\frac{1}{2}x^2 - 3x + \frac{1}{2} = 0\). Here, we identify the coefficients: \(a = \frac{1}{2}\), \(b = -3\), and \(c = \frac{1}{2}\).
02
Use the Quadratic Formula
The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute the identified coefficients into the formula.
03
Calculate the Discriminant
Calculate the discriminant using the formula \(b^2 - 4ac\). Here, the discriminant is \((-3)^2 - 4 \times \frac{1}{2} \times \frac{1}{2}\). Simplifying gives \(9 - 1 = 8\).
04
Substitute into the Quadratic Formula
Now substitute \(b = -3\), \(\sqrt{8}\), and \(a = \frac{1}{2}\) into the quadratic formula: \(x = \frac{3 \pm \sqrt{8}}{1}\).
05
Simplify the Solutions
Simplify \(\sqrt{8}\) as \(2\sqrt{2}\) and solve: \(x = 3 \pm 2\sqrt{2}\). This results in two solutions \(x = 3 + 2\sqrt{2}\) and \(x = 3 - 2\sqrt{2}\).
06
Check the Solutions
Substitute \(x = 3 + 2\sqrt{2}\) back into the original equation and verify it equals zero. Repeat for \(x = 3 - 2\sqrt{2}\). Both should satisfy the original equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
In algebra, solving quadratic equations is a fundamental skill that you often use. These equations are typically written in the form
To use the formula:
- ax² + bx + c = 0
- x = \(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
To use the formula:
- First, identify the coefficients in your quadratic equation, just as we did in the original exercise.
- Plug these coefficients into the formula.
Discriminant
The discriminant is a special term in the quadratic formula located under the square root:
The value of the discriminant tells us:
- \(b^2 - 4ac\)
The value of the discriminant tells us:
- If it’s positive, the equation has two distinct real roots.
- If it’s zero, the equation has exactly one real root, or a repeated root.
- If it’s negative, there are no real solutions but two complex solutions.
- \(8\)
Simplifying Expressions
Once you have plugged values into the quadratic formula and evaluated the expression, you're left with a solution that often needs simplifying. Simplifying expressions helps in making the solutions more understandable and neat.
In the original exercise, we simplified:
Remember to always check your work by plugging the simplified solutions back into the original equation. This ensures that no errors were made during the simplification process. It might be a bit tedious but it’s a great way to confirm the solution.
In the original exercise, we simplified:
- \(\sqrt{8}\)
- \(2\sqrt{2}\)
Remember to always check your work by plugging the simplified solutions back into the original equation. This ensures that no errors were made during the simplification process. It might be a bit tedious but it’s a great way to confirm the solution.