/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 Solve the inequality. Approximat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the inequality. Approximate the endpoints to the nearest thousandth when appropriate. $$ 5<4 x-2.5 $$

Short Answer

Expert verified
The solution is \((1.875, \infty)\).

Step by step solution

01

Isolate the variable term

Add \(2.5\) to both sides of the inequality to eliminate the constant on the right side: \[5 + 2.5 < 4x \]Simplifying the left side will give us:\[7.5 < 4x\]
02

Solve for the variable

To isolate \(x\), divide both sides of the inequality by \(4\):\[\frac{7.5}{4} < x\]This simplifies to approximately:\[1.875 < x\]
03

Express the solution

The inequality solution can be expressed by saying \(x\) is greater than approximately \(1.875\). In interval notation, this can be written as: \((1.875, \infty)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebra and Inequality Solving
Solving inequalities involves algebraic techniques to find a range of possible values for a variable. When dealing with algebra, the goal is similar to solving equations, but instead of finding one solution, we're interested in a set of solutions.
For the inequality given, \(5 < 4x - 2.5\), we aim to find when this condition is true that the expression on one side is always less than the expression with the variable.
The key is to manipulate the inequality just like an equation, by doing the same operation on both sides.
Remember:
  • When adding or subtracting terms from both sides of an inequality, the inequality symbol remains the same.
  • When multiplying or dividing by a positive number, the inequality's direction stays the same.
  • If you multiply or divide by a negative number, the inequality's direction will flip.
This process ensures that the inequality remains true while adjusting the variable's position to make it easier to find its possible values.
Isolating the Variable
Isolating the variable is a foundational skill in algebra. It means getting the variable by itself on one side of the equation or inequality. This helps to determine its possible values.
In our exercise, we had initially \(5 < 4x - 2.5\).
To isolate \(x\), first, we wanted to remove the \(-2.5\) from the right side by adding \(2.5\) to both sides. This action balanced the inequality without changing its truth.
Then we have \(7.5 < 4x\).
The next step was to isolate \(x\) by dividing both sides by \(4\), giving us \(\frac{7.5}{4} < x\).
Remember: Always perform operations step by step, and check if you need to reverse the inequality sign if working with negative numbers.
Interval Notation
Interval notation is a concise way of describing a set of numbers along the number line. It's especially useful in expressing solutions to inequalities.
For the solution \(1.875 < x\), this means \(x\) is any number greater than \(1.875\).
In interval notation, this is written as \((1.875, \infty)\).
The round bracket "(" indicates that \(1.875\) is not included in the range. The infinity symbol \(\infty\) always has a parenthesis because it's not a specific number that can be reached.
Always:
  • Use round brackets \(()\) for non-inclusive ("open") endpoints.
  • Use square brackets \([]\) for inclusive ("closed") endpoints.
  • Use comma to separate the lower and upper bounds.
This method delivers clarity and precision, making it easier to see the range of acceptable values for the variable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Value of a Home In 1999 the value of a house was \(\$ 180,000,\) and in 2009 it was \(\$ 245,000\) (a) Find a linear function \(V\) that approximates the value of the house during year \(x .\) (b) What does the slope of the graph of \(V\) represent? (c) Use \(V\) to estimate the year when the house was worth \(\$ 219,000\)

Sales of CRT and LCD Screens In \(2002,75\) million CRT (cathode ray tabe) monitors were sold and 29 million flat LCD (liquid crystal display) monitors were sold. In 2006 the numbers were 45 million for CRT monitors and 88 million for LCD monitors. (Source: International Data Corporation.) (a) Find a linear function \(C\) that models these data for CRT monitors and another linear function \(L\) that models these data for LCD monitors. Let \(x\) be the year. (b) Interpret the slopes of the graphs of \(C\) and of \(L\) (c) Determine graphically the year when sales of these two types of monitors were equal. (d) Solve part (c) symbolically. (e) Solve part (c) numerically.

Hat Size The table lists hat size \(H\) for a head with circumference \(x\) in inches. $$ \begin{array}{ccccc} x \text { (in.) } & 21 \frac{1}{8} & 21 \frac{7}{8} & 22 \frac{5}{8} & 25 \\ \hline S \text { (size) } & 6_{4}^{3} & 7 & 7 \frac{1}{4} & 8 \end{array} $$ Source: Brentblack, (a) Find a linear function \(S\) that models the data. (b) Find the circumference of a head with a hat size of \(7 \frac{1}{2}\)

Solve the inequality. Write the solution in interval notation. $$|2.1 x-5| \leq 8$$

Motion A car went 372 miles in 6 hours, traveling part of the time at 55 miles per hour and part of the time at 70 miles per hour. How long did the car travel at each speed?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.