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Solve the linear inequality graphically. Write the solution set in set-builder notation. Approximate endpoints to the nearest hundredth whenever appropriate. $$ \sqrt{5}(x-1.2)-\sqrt{3} x<5(x+1.1) $$

Short Answer

Expert verified
\(x > a\) where \( a \) is calculated value, in set-builder notation: \{x | x > a \}.

Step by step solution

01

Simplify the Inequality

First, expand and simplify both sides of the inequality. \[ \sqrt{5}(x - 1.2) - \sqrt{3}x < 5(x + 1.1) \]Expanding both sides, we have: - Left side: \( \sqrt{5}x - \sqrt{5} \cdot 1.2 - \sqrt{3}x \)- Right side: \( 5x + 5 \cdot 1.1 \)Simplifying further:\[\sqrt{5}x - 1.2\sqrt{5} - \sqrt{3}x < 5x + 5.5\]
02

Combine Like Terms

Now, combine like terms on the left side of the equation:\[(\sqrt{5} - \sqrt{3})x - 1.2\sqrt{5} < 5x + 5.5\]
03

Rearrange Terms

Subtract all terms involving \(x\) from both sides to isolate terms not involving \(x\):\[(\sqrt{5} - \sqrt{3})x - 5x < 5.5 + 1.2\sqrt{5} \]This simplifies to: \[(\sqrt{5} - \sqrt{3} - 5)x < 5.5 + 1.2\sqrt{5} \]
04

Solve for x

Simplify and solve for \(x\): \[(-5 + \sqrt{5} - \sqrt{3})x < 5.5 + 1.2\sqrt{5}\]Notice that \(- (5 - \sqrt{5} + \sqrt{3})x < 5.5 + 1.2\sqrt{5}\). If we divide by this negative term, we must flip the inequality sign. Therefore:\[x > \frac{5.5 + 1.2\sqrt{5}}{5 - \sqrt{5} + \sqrt{3}}\]
05

Graph the Solution

Graphically, this inequality \(x > \frac{5.5 + 1.2\sqrt{5}}{5 - \sqrt{5} + \sqrt{3}}\) indicates a horizontal line where all values greater than this point are part of the solution set. The line will be dotted since the inequality is not inclusive \(<\). This line can be drawn using a graphing calculator or manually by calculating the approximate value of the expression.
06

Write the Solution Set in Set-Builder Notation

First, calculate the approximate value of the equation:\[x \, > \, \frac{5.5 + 1.2 \cdot \sqrt{5}}{5 - \sqrt{5} + \sqrt{3}} \]After evaluating numerically, approximate the result. The inequality's solution will be something like:\[x > a, \text{ where } a \, \text{is the calculated number rounded to the nearest hundredth}\]In set-builder notation, it can be written as:\[ \{ x \,|\, x > a \} \] where \(a\) is the value calculated in this step.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set-Builder Notation
Set-builder notation is a compact and useful way to describe sets, often used when dealing with inequalities. It specifies the properties that elements of the set must satisfy. In the case of linear inequalities, set-builder notation helps us express the range of solutions for the inequality.
To write an inequality in set-builder notation, you start by identifying the variable you're working with, such as 'x'. Then, you specify the conditions that 'x' has to meet. For example, in an inequality like \( x > a \), the solution set in set-builder notation would be expressed as:
\[ \{ x \,|\, x > a \} \]
This notation can be read as "the set of all x such that x is greater than a."
  • The '{' symbol begins the set definition.
  • The '|' symbol stands for "such that."
  • The conditions follow after the '|', defining constraints on the elements of the set.
By using this notation, you can concisely represent solutions to algebraic problems, which is especially helpful when sharing findings in mathematical discussions or writings.
Graphical Solution
Graphical solutions are a powerful method to visually interpret inequalities. By using a coordinate plane, you can depict regions that satisfy given conditions. For linear inequalities, this typically involves drawing lines and shading areas.
When graphing an inequality like \( x > a \), you are essentially drawing a vertical line at \(x = a\) and shading all the area to its right, indicating values greater than 'a'.
  • The line itself can be solid or dotted:
    • A dotted line means the boundary is not included (\(< \) or \(>\)).
    • A solid line signifies inclusion (\(\leq\) or \(\geq\)).
  • The shading represents all the potential solutions of the inequality.
Visualizing the inequality helps verify algebraic results, and provides an intuitive understanding of solution sets. In practical terms, drawing these graphs can be done manually or with digital tools, giving you flexibility in problem-solving.
Algebraic Manipulation
Algebraic manipulation refers to the techniques applied to modify or simplify expressions and equations, making them easier to solve. It's crucial in solving inequalities because it allows us to isolate variables and arrive at solutions that can be graphed or written in set-builder notation.
In the context of linear inequalities, manipulation involves steps such as distributing coefficients, combining like terms, and rearranging terms. For example, in an inequality like \( \sqrt{5}(x - 1.2) - \sqrt{3}x<5(x+1.1) \), you'll:
- Distribute multiplication across terms: transforming \( \sqrt{5}(x - 1.2) \) into \( \sqrt{5}x - 1.2\sqrt{5} \).
- Combine like terms across an inequality, such as bringing all 'x'-terms to one side.
- Simplify the expression: ensuring that all terms are as reduced as possible.
Remember, when dividing or multiplying both sides by a negative number, the inequality sign flips. This crucial rule ensures the inequality's truthful representation does not change.
  • Identify distributive opportunities.
  • Move terms strategically across the inequality sign.
  • Simplify to solve for the variable.
Mastering these techniques can significantly enhance your ability to tackle complex inequalities efficiently and correctly.

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Most popular questions from this chapter

Women in Politics The table lists the percentage \(P\) of women in state legislatures during year \(x .\) $$ \begin{array}{|c|ccccc} \hline x & 1993 & 1997 & 2001 & 2005 & 2007 \\ \hline P & 20.5 & 21.6 & 22.4 & 22.7 & 23.5 \\ \hline \end{array} $$ Source: National Women's Political Caucus. (a) Find a linear function \(P\) that models the data. (b) Estimate this percentage in 2003 and compare the estimate to the actual value of \(22.4 \% .\) Did your estimate involve interpolation or extrapolation? (c) Use \(P\) to predict the year when this percentage could reach \(25 \%\)

Let \(y\) be directly proportional to \(x\) Complete the following. Find \(y\) when \(x=1.3,\) if \(y=7.2\) when \(x=5.2\)

Vinyl and CD Sales During the 1980 s, sales of compact discs surpassed vinyl record sales. From 1985 to 1990 , sales of compact discs in millions can be modeled by the formula \(f(x)=51.6(x-1985)+9.1,\) whereas sales of vinyl LP records in millions can be modeled by \(g(x)=-31.9(x-1985)+167.7 .\) Approximate the year \(x\) when sales of LP records and compact discs were equal by using the intersection-of-graphs method. (Source: Recording Industry Association of America.)

Value of a Home In 1999 the value of a house was \(\$ 180,000,\) and in 2009 it was \(\$ 245,000\) (a) Find a linear function \(V\) that approximates the value of the house during year \(x .\) (b) What does the slope of the graph of \(V\) represent? (c) Use \(V\) to estimate the year when the house was worth \(\$ 219,000\)

Exercises \(59-66:\) Solve the linear equation with the intersection-of-graphs method. Approximate the solution to the nearest thousandth whenever appropriate. $$ 5 x-1.5=5 $$

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