Chapter 0: Problem 85
Simplify. $$ \frac{x}{x^{2}-9}+\frac{5 x}{x-3} $$
Short Answer
Expert verified
\(\frac{x(5x + 16)}{(x-3)(x+3)}\)
Step by step solution
01
Find the Common Denominator
To simplify the expression \( \frac{x}{x^{2}-9} + \frac{5x}{x-3} \), we first need to find a common denominator. The first denominator \( x^2 - 9 \) can be factored as \((x-3)(x+3)\). The second denominator is already \(x-3\). The common denominator of both fractions is \((x-3)(x+3)\).
02
Rewrite Each Fraction with the Common Denominator
Rewrite each fraction so they both have the common denominator \((x-3)(x+3)\). The first fraction is already \( \frac{x}{(x-3)(x+3)} \). For the second fraction, multiply both the numerator and the denominator by \((x+3)\): \( \frac{5x(x+3)}{(x-3)(x+3)} \).
03
Combine the Fractions
With both fractions having the common denominator, you can combine them: \( \frac{x + 5x(x+3)}{(x-3)(x+3)} \).
04
Simplify the Numerator
Simplify the numerator \(x + 5x(x+3)\). Distribute the \(5x\) in the term \(5x(x+3)\): \(5x^2 + 15x\). The expression becomes \(x + 5x^2 + 15x\) which simplifies to \(5x^2 + 16x\).
05
Factor the Numerator
To factor the numerator \(5x^2 + 16x\), factor out \(x\): \(x(5x + 16)\).
06
Final Expression
The expression is now \(\frac{x(5x + 16)}{(x-3)(x+3)}\). This is the simplified form of the given expression since there are no common factors to cancel out between the numerator and the denominator.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Denominator
When simplifying fractions, finding a common denominator is crucial. It ensures both fractions can be combined seamlessly. In algebra, variables and expressions form our denominators. Let's use the expression \( \frac{x}{x^{2}-9} + \frac{5x}{x-3} \).
We first determine a denominator that both fractions share. The denominator \( x^2 - 9 \) is a difference of squares. It factors into \((x-3)(x+3)\).
Assess the second denominator, \(x-3\). Here, it already appears in the first denominator's factored form, leaving us to include the additional factor \((x+3)\) to match. That's how a common denominator of \((x-3)(x+3)\) is determined.
When fractions share a common denominator, algebraic operations like addition, subtraction, and simplification become possible. This step is foundational in successful algebraic simplification.
We first determine a denominator that both fractions share. The denominator \( x^2 - 9 \) is a difference of squares. It factors into \((x-3)(x+3)\).
Assess the second denominator, \(x-3\). Here, it already appears in the first denominator's factored form, leaving us to include the additional factor \((x+3)\) to match. That's how a common denominator of \((x-3)(x+3)\) is determined.
When fractions share a common denominator, algebraic operations like addition, subtraction, and simplification become possible. This step is foundational in successful algebraic simplification.
Factoring
Factoring plays a big role in algebraic simplification. It allows us to break down complex expressions into simpler parts. Let’s consider the expression with denominators \(x^2 - 9\) and \(x-3\). The first task is factoring \(x^2 - 9\), a difference of squares.
A difference of squares is an expression like \(a^2 - b^2\), which factors into \((a+b)(a-b)\).
A difference of squares is an expression like \(a^2 - b^2\), which factors into \((a+b)(a-b)\).
- Here, \(x^2 - 9\) represents \(a^2 - b^2\) with \(a = x\) and \(b = 3\).
- So, it becomes \((x+3)(x-3)\).
- We can factor out \(x\), giving \(x(5x + 16)\).
Combining Fractions
Once each fraction has a common denominator, the path to combining them opens up. Consider \(\frac{x}{(x-3)(x+3)} + \frac{5x(x+3)}{(x-3)(x+3)}\). Both share the common denominator \((x-3)(x+3)\).
Combine the fractions by adding or subtracting the numerators.
Combine the fractions by adding or subtracting the numerators.
- Add the numerators to create \(x + 5x(x+3)\).
- Simplifying this involves expanding \(5x(x+3)\) to \(5x^2 + 15x\).
- Combine like terms: \(x + 5x^2 + 15x\) becomes \(5x^2 + 16x\).