Chapter 0: Problem 101
Rationalize the denominator. $$ \sqrt{\frac{b}{12}} $$
Short Answer
Expert verified
\( \frac{\sqrt{3b}}{6} \)
Step by step solution
01
Identify the Problem
We need to rationalize the denominator in the expression \( \sqrt{\frac{b}{12}} \). This means transforming the expression so there is no square root in the denominator.
02
Rewrite as a Fraction Inside the Square Root
Start by expressing the square root of a fraction as the fraction of two square roots: \( \sqrt{\frac{b}{12}} = \frac{\sqrt{b}}{\sqrt{12}} \).
03
Simplify the Denominator
Recognize that \( \sqrt{12} \) can be simplified. \( 12 = 4 \times 3 \), so \( \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4}\sqrt{3} = 2\sqrt{3} \). Thus, our expression becomes \( \frac{\sqrt{b}}{2\sqrt{3}} \).
04
Rationalize the Denominator
Multiply both the numerator and the denominator by \( \sqrt{3} \) to eliminate the square root in the denominator: \[ \frac{\sqrt{b}}{2\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{b} \cdot \sqrt{3}}{2 \cdot 3} = \frac{\sqrt{3b}}{6}. \]
05
Final Expression
The expression \( \sqrt{\frac{b}{12}} \) rationalized is \( \frac{\sqrt{3b}}{6} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Roots
Square roots are a fundamental concept in mathematics often encountered in algebra and geometry. When we talk about the square root of a number, we refer to a value that, when multiplied by itself, gives the original number. For example, the square root of 9 is 3, since 3 \times 3 = 9. The square root symbol is denoted as \( \sqrt{\ } \).
It's important to know that not every number has a whole number as its square root. For instance, \( \sqrt{2} \) is an irrational number, meaning it cannot be expressed as a simple fraction.
It's important to know that not every number has a whole number as its square root. For instance, \( \sqrt{2} \) is an irrational number, meaning it cannot be expressed as a simple fraction.
- Square roots help in undoing the operation of squaring a number.
- If \( x^2 = y \), then \( x = \sqrt{y} \).
Simplifying Radicals
Simplifying radicals involves expressing a radical expression in its simplest form. This process often includes breaking down the number inside the square root into its prime factors. Consider the example from our problem, \( \sqrt{12} \).
Recognizing that 12 = 4 \times 3 allows us to separate it into \( \sqrt{4} \) and \( \sqrt{3} \). Since \( \sqrt{4} = 2 \), we can rewrite \( \sqrt{12} \) as \( 2\sqrt{3} \). The objective is to make calculations easier by reducing the numbers inside radicals.
Recognizing that 12 = 4 \times 3 allows us to separate it into \( \sqrt{4} \) and \( \sqrt{3} \). Since \( \sqrt{4} = 2 \), we can rewrite \( \sqrt{12} \) as \( 2\sqrt{3} \). The objective is to make calculations easier by reducing the numbers inside radicals.
- Simplification makes complex expressions manageable.
- Simplified radicals are clearer and less prone to error in calculations.
Fractions in Algebra
Fractions are a key component of algebra. They represent parts of a whole and are written as a division of one number by another. When fractions appear within square roots, as in the problem \( \sqrt{\frac{b}{12}} \), they present unique challenges.
Rationalizing the denominator involves removing any radicals from the bottom of the fraction. This is done by introducing a term that will eliminate the radical when multiplied. In our example, multiplying by \( \sqrt{3} \) helped in achieving this, simplifying the expression from \( \frac{\sqrt{b}}{2\sqrt{3}} \) to \( \frac{\sqrt{3b}}{6} \).
Rationalizing the denominator involves removing any radicals from the bottom of the fraction. This is done by introducing a term that will eliminate the radical when multiplied. In our example, multiplying by \( \sqrt{3} \) helped in achieving this, simplifying the expression from \( \frac{\sqrt{b}}{2\sqrt{3}} \) to \( \frac{\sqrt{3b}}{6} \).
- Fractions require understanding both numerators and denominators.
- Balancing both parts helps in simplifying algebraic expressions.