Chapter 8: Problem 58
For the following exercises, find the area of the ellipse. The area of an ellipse is given by the formula Area \(=a \cdot b \cdot \pi\). \(\frac{(x+6)^{2}}{16}+\frac{(y-6)^{2}}{36}=1\)
Short Answer
Expert verified
The area of the ellipse is \(24\pi\).
Step by step solution
01
Identify the Semi-Axes
The equation of the ellipse is given as \( \frac{(x+6)^2}{16} + \frac{(y-6)^2}{36} = 1 \). This is in the form \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \). From here, you can identify \( a^2 = 16 \) and \( b^2 = 36 \), which means \( a = 4 \) and \( b = 6 \).
02
Apply the Area Formula
The formula for the area of an ellipse is given by \( \text{Area} = a \cdot b \cdot \pi \). Substitute the values \( a = 4 \) and \( b = 6 \) into the formula: \( \text{Area} = 4 \cdot 6 \cdot \pi \).
03
Calculate the Area
Multiply the values as per the formula: \( 4 \cdot 6 = 24 \). Then, multiply by \( \pi \) to find the area: \( \text{Area} = 24\pi \). Therefore, the area of the ellipse is \( 24\pi \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ellipse Equation
An ellipse is a smooth, symmetrical shape much like a stretched-out circle. You can describe it with an equation, a mathematical expression showing its characteristics. An ellipse's equation in standard form looks like this:
- \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \)
- \( \frac{(x+6)^2}{16} + \frac{(y-6)^2}{36} = 1 \)
Semi-Major Axis
The semi-major axis is one of the critical dimensions of an ellipse, representing half of the longest length from one end of the ellipse to the other. In our ellipse equation:
- \( \frac{(x+6)^2}{16} + \frac{(y-6)^2}{36} = 1 \)
Semi-Minor Axis
On the other hand, the semi-minor axis is half of the shortest length from one end of an ellipse to the other. In our standard form ellipse equation:
- \( \frac{(x+6)^2}{16} + \frac{(y-6)^2}{36} = 1 \)
Area Formula
To find the area of an ellipse, we use a specific formula, which combines the lengths of both the semi-major and semi-minor axes:
- \( \text{Area} = a \cdot b \cdot \pi \)
- \( \text{Area} = 4 \cdot 6 \cdot \pi = 24\pi \)