Chapter 5: Problem 22
For the following exercises, find the \(x\) - and \(y\) -intercepts for the functions. $$ f(x)=\frac{x^{2}+8 x+7}{x^{2}+11 x+30} $$
Short Answer
Expert verified
The x-intercepts are (-1, 0) and (-7, 0); the y-intercept is (0, 7/30).
Step by step solution
01
Understand the Problem
We need to find the intercepts of the given rational function: \( f(x) = \frac{x^2 + 8x + 7}{x^2 + 11x + 30} \). An intercept is a point where the graph of the function crosses the axes.
02
Find the y-intercept
To find the \( y \)-intercept, set \( x = 0 \) and solve for \( f(x) \). This is because the \( y \)-intercept is where the graph crosses the \( y \)-axis, which occurs when \( x = 0 \): \[ f(0) = \frac{0^2 + 8 \cdot 0 + 7}{0^2 + 11 \cdot 0 + 30} = \frac{7}{30} \]Therefore, the \( y \)-intercept is \( (0, \frac{7}{30}) \).
03
Find the x-intercepts
To find the \( x \)-intercepts, set \( f(x) = 0 \). The function equals zero when the numerator is zero and the denominator is not zero. Set the numerator equal to zero:\[ x^2 + 8x + 7 = 0 \]Factor the quadratic:\[ (x + 1)(x + 7) = 0 \]Solve for \( x \):\[ x + 1 = 0 \quad \text{or} \quad x + 7 = 0 \]\[ x = -1 \quad \text{or} \quad x = -7 \]The \( x \)-intercepts are \( (-1, 0) \) and \( (-7, 0) \).
04
Validate the Denominator
For the \( x \)-intercepts found, ensure these values do not make the denominator zero. The denominator is zero when:\[ x^2 + 11x + 30 = 0 \]Factor the quadratic:\[ (x + 5)(x + 6) = 0 \]Solutions are \( x = -5 \) and \( x = -6 \). Since \(-1\) and \(-7\) do not equal \(-5\) or \(-6\), the found \( x \)-intercepts are valid.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
X-Intercepts
The concept of x-intercepts pertains to points where the graph of a function crosses the x-axis. To find these, you need to determine the x-values for which the function is equal to zero. In other words, solve the equation when the function's output (\( f(x)\) ) is zero.
In the case of rational functions, like\(f(x) = \frac{x^2 + 8x + 7}{x^2 + 11x + 30}\), x-intercepts occur when the numerator equals zero while the denominator is non-zero. This avoids undefined points.
Following the given solution:
In the case of rational functions, like\(f(x) = \frac{x^2 + 8x + 7}{x^2 + 11x + 30}\), x-intercepts occur when the numerator equals zero while the denominator is non-zero. This avoids undefined points.
Following the given solution:
- The numerator:\(x^2 + 8x + 7 = 0\) has to be solved. Factor this into:\((x + 1)(x + 7) = 0\)
- Solve each factor set to zero, giving solutions:\(x = -1\) and\(x = -7\)Thus, x-intercepts are at\((-1, 0)\) and\((-7, 0)\)
Y-Intercepts
Understanding y-intercepts is key. They represent where the graph crosses the y-axis, observed by setting\(x = 0\) in the function. This is because the y-axis is essentially the line where all x-values are zero.
Example:\(f(x) = \frac{x^2 + 8x + 7}{x^2 + 11x + 30}\) allows finding the y-intercept by substituting x with 0 in the function.
The calculation becomes:\[f(0) = \frac{0^2 + 8 \times 0 + 7}{0^2 + 11 \times 0 + 30} = \frac{7}{30}.\]Thus, the y-intercept is the point\( (0, \frac{7}{30})\).
Example:\(f(x) = \frac{x^2 + 8x + 7}{x^2 + 11x + 30}\) allows finding the y-intercept by substituting x with 0 in the function.
The calculation becomes:\[f(0) = \frac{0^2 + 8 \times 0 + 7}{0^2 + 11 \times 0 + 30} = \frac{7}{30}.\]Thus, the y-intercept is the point\( (0, \frac{7}{30})\).
- It provides a clear point on the graph to begin sketching.
- Only one y-intercept exists if the function is not piecewise.
Quadratic Equations
Quadratic equations arise when working with polynomials and are pivotal in finding intercepts. In standard form, a quadratic equation is:\(ax^2 + bx + c = 0\). Such an equation can often be solved by factoring, completing the square, or applying the quadratic formula.
In our rational function example, the numerator\(x^2 + 8x + 7\) and the denominator\(x^2 + 11x + 30\) are both quadratic equations.
For factoring,
In our rational function example, the numerator\(x^2 + 8x + 7\) and the denominator\(x^2 + 11x + 30\) are both quadratic equations.
For factoring,
- Identify two numbers that multiply to the constant term and add to the linear coefficient.
- For\(x^2 + 8x + 7\), the factors are:\((x + 1)(x + 7)\).
- This simple technique enables simplifying or solving quadratics effectively.
Rational Functions
Rational functions are expressions represented as the quotient of two polynomials, making them crucial in higher-level algebra. Formally, a rational function is:\(f(x) = \frac{P(x)}{Q(x)}\), where\(P(x)\) and\(Q(x)\) are polynomials.
Key aspects include:
Gain proficiency by practicing discerning such points and understanding their implications on graphs.
Key aspects include:
- Points where\(Q(x) = 0\) are crucial as they can indicate undefined points or vertical asymptotes in a graph.
- Finding intercepts involves examining both numerators and denominators of the rational function.
- Behavior near intercepts is essential for sketching graphs accurately.
Gain proficiency by practicing discerning such points and understanding their implications on graphs.