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What is the basic principle in multiplication of complex numbers?

Short Answer

Expert verified
The basic principle is to use the distributive property and the identity \(i^2 = -1\) to simplify.

Step by step solution

01

Understand the Components

Complex numbers are expressed in the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. When multiplying two complex numbers, \((a + bi)\) and \((c + di)\), our goal is to derive a new complex number \(e + fi\).
02

Apply the Distributive Property

The multiplication of two complex numbers involves using the distributive property. Distribute each term in the first complex number by each term in the second complex number. This means calculating: \((a + bi)(c + di) = ac + adi + bci + bdi^2\).
03

Simplify Using \(i^2 = -1\)

Recall that \(i^2\) is defined as \(-1\). Use this to simplify the product. The expression becomes: \(ac + adi + bci - bd\).
04

Combine Like Terms

Combine the real parts and the imaginary parts to express the result in the form \(e + fi\). This gives us: \((ac - bd) + (ad + bc)i\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are a fundamental concept in mathematics that extend the idea of the usual number line into a two-dimensional plane. These numbers are written in the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. The letter \(i\) is used to denote the square root of \(-1\), which is not possible to achieve with real numbers alone.
This new component, \(bi\), allows for broader mathematical operations and solutions to previously intractable problems. Complex numbers can be visualized on a plane called the complex plane, where the horizontal axis represents the real part, and the vertical axis is for the imaginary part.
Real Part
The real part of a complex number is the \(a\) in the expression \(a + bi\). It determines the position on the horizontal axis of the complex plane. This part behaves just like a regular real number. When dealing with complex number operations, the real parts combine separately from the imaginary parts.
For example, if you have two complex numbers, \(3 + 4i\) and \(5 + 6i\), the real parts are \(3\) and \(5\). In multiplication or addition, it is crucial to treat these components separately, combining them according to arithmetic operations.
Imaginary Part
The imaginary part of a complex number is the \(bi\) portion, with \(b\) being the coefficient of \(i\). This part indicates the position along the vertical axis of the complex plane. Imaginary numbers extend our number system by incorporating the square root of negative numbers.
In the context of multiplication, terms that involve imaginary parts produce results that are key to obtaining the final product. Specifically, remember that \(i^2 = -1\), making it essential when simplifying expressions in multiplication. The imaginary parts interact with real parts during operations to provide a complete solution.
Distributive Property
The distributive property is a key concept in algebra that allows you to multiply sums efficiently. When multiplying complex numbers, this property ensures each term in one complex number meets each term in another. For example, consider the multiplication of \((a + bi)\) and \((c + di)\).
You must apply the distributive property by expanding as follows: \((a + bi)(c + di) = ac + adi + bci + bdi^2\). Then simplify using \(i^2 = -1\), transforming the expression to \(ac + adi + bci - bd\). Finally, combine like terms: the real parts \(ac - bd\), and the imaginary parts \((ad + bc)i\), arriving at the result \((ac - bd) + (ad + bc)i\). This process underlies the multiplication of complex numbers.

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Most popular questions from this chapter

For the following exercises, use the model for the period of a pendulum, \(T\), such that \(T=2 \pi \sqrt{\frac{L}{g}}\), where the length of the pendulum is \(L\) and the acceleration due to gravity is g. If the gravity is \(32 \mathrm{ft} / \mathrm{s}^{2}\) and the period equals \(1 \mathrm{~s}\), find the length to the nearest in. (12 in. = \(1 \mathrm{ft}\) ). Round your answer to the nearest in.

For the following exercises, input the left-hand side of the inequality as a \(Y 1\) graph in your graphing utility. Enter \(y 2=\) the right-hand side. Entering the absolute value of an expression is found in the MATH menu, Num, \(1: a b s(.\) Find the points of intersection, recall \(\left(2^{\text {nd }}\right.\) CALC 5 :intersection, \(1^{\text {st }}\) curve, enter, \(2^{\text {nd }}\) curve, enter, guess, enter). Copy a sketch of the graph and shade the \(x\) -axis for your solution set to the inequality. Write final answers in interval notation. $$ |x+2| \geq 5 $$

For the following exercises, use the model for the period of a pendulum, \(T\), such that \(T=2 \pi \sqrt{\frac{L}{g}}\), where the length of the pendulum is \(L\) and the acceleration due to gravity is g. If the acceleration due to gravity is \(9.8 \mathrm{~m} / \mathrm{s}^{2}\) and the period equals \(1 \mathrm{~s}\), find the length to the nearest \(\mathrm{cm}(100 \mathrm{~cm}=1 \mathrm{~m})\).

For the following exercises, solve the equation involving absolute value. $$ |2 x-1|-7=-2 $$

For the following exercises, solve the compound inequality. Express your answer using inequality signs, and then write your answer using interval notation. $$ y<5-2 y<7+y $$

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