/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 99 Determine whether each equation ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether each equation is true or false. Where possible, show work to support your conclusion. If the statement is false, make the necessary change(s) to produce a true statement. \(\log _{6}\left(\frac{x-1}{x^{2}+4}\right)=\log _{6}(x-1)-\log _{6}\left(x^{2}+4\right)\)

Short Answer

Expert verified
The given equation \( \log _{6}\left(\frac{x-1}{x^{2}+4}\right)=\log _{6}(x-1)-\log _{6}\left(x^{2}+4\right) \) is true as it correctly applies the logarithmic law that the log of a division of two numbers is equal to the difference of their individual logs.

Step by step solution

01

Understand the log law

Logarithms have a property that the log of a division of two numbers is equal to the difference of their individual logs. This means that, generally, if you have \( \log_{b} \left( \frac{a}{c} \right) \), you can rewrite it as \( \log_{b}(a) - \log_{b}(c) \).
02

Apply the log law to the given equation

Looking at the equation \( \log _{6}\left(\frac{x-1}{x^{2}+4}\right)=\log _{6}(x-1)-\log _{6}\left(x^{2}+4\right) \), you see that the left side is a log of a division, which, according to the log law, can be taken as the difference of the individual logs. This is exactly what is seen on the right side of the equation.
03

Conclusion

Since both sides of the equation reflect the same operation and the logarithmic law was rightly implemented in the right hand side, we can conclude that the given equation is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Equations
Solving logarithmic equations is all about understanding how to manipulate expressions using logarithms. These equations contain unknowns within a logarithmic function. For instance, when you have an equation like \(\log_{b}(x) = y\), it implies that \(b^y = x\). But more complex examples involve properties of logarithms to simplify the equation, allowing us to isolate the variable and solve.

Consider an equation \( \log_{a}(x) + \log_{a}(y) = \log_{a}(z) \). This equation suggests that \(x \cdot y = z\), by using the property that \( \log_{a}(x \cdot y) \equiv \log_{a}(x) + \log_{a}(y) \). So one strategy in solving logarithmic equations is transforming them into an equivalent exponential form, simplifying, and then finding the values of the unknowns. It's essential to verify our solutions, as sometimes we might introduce extraneous solutions which don't satisfy the original equation.
Properties of Logarithms
Discovering the properties of logarithms can feel like unlocking new levels in a puzzle game. Each property provides a new tool for simplifying complex logarithmic expressions. Some basic properties include:

  • \textbf{Product Rule:} \( \log_{b}(xy) \equiv \log_{b}(x) + \log_{b}(y) \), which shows how to split a logarithm of a multiplication into a sum of logarithms.
  • \textbf{Quotient Rule:} \( \log_{b}(\frac{x}{y}) \equiv \log_{b}(x) - \log_{b}(y) \), as seen in the original exercise, allows us to express the log of a division as the difference of logs.
  • \textbf{Power Rule:} \( \log_{b}(x^{n}) \equiv n \cdot \log_{b}(x) \), this tells us how to handle a logarithm of a power of a number.
  • \textbf{Change of Base Formula:} For any positive numbers \(a\) and \(b\), neither of which equals \(1\), and any positive number \(x\), \( \log_{a}(x) \equiv \frac{\log_{b}(x)}{\log_{b}(a)} \).
Each property is a strategy to manage complexity - turning tough logarithmic expressions into a series of simpler operations.
Verifying Logarithmic Identities
Verifying logarithmic identities is akin to doing detective work - we scrutinize every part to confirm its truthfulness. An identity is a mathematical statement that is always true, regardless of the values we insert into it, given they are within the domain of the log functions.

For instance, one might encounter the challenge to prove that \( \log_{b}(x) + \log_{b}(y) = \log_{b}(xy) \). To verify, we can convert the logarithmic terms to their exponential forms and check if it holds true for all permissible values of \(x\) and \(y\).

If the identity is not true, as could be the case when dealing with more complex or incorrectly assumed identities, one would have to manipulate the equation using the properties of logarithms to either prove it as an identity or to find the necessary modifications to make it true. This methodological approach to confirming identities ensures not just mechanical practice but also a deeper understanding of logarithmic functions and their inherent truths.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the exponential decay model for carbon- \(14, A=A_{0} e^{-0.000121 t}\) to solve Exercises \(19-20\) Skeletons were found at a construction site in San Francisco in \(1989 .\) The skeletons contained \(88 \%\) of the expected amount of carbon-14 found in a living person. In \(1989,\) how old were the skeletons?

The \(p H\) scale is used to measure the acidity or alkalinity of a solution. The scale ranges from 0 to \(14 .\) A neutral solution, such as pure water, has a pH of 7. An acid solution has a pH less than 7 and an alkaline solution has a p \(H\) greater than \(7 .\) The lower the \(p H\) below \(7,\) the more acidic is the solution. Each whole-number decrease in \(p H\) represents a tenfold increase in acidity. The \(p H\) of a solution is given by $$\mathrm{pH}=-\log x$$ where \(x\) represents the concentration of the hydrogen ions in the solution, in moles per liter. Express answers as powers of $10. a. Normal, unpolluted rain has a pH of about 5.6. What is the hydrogen ion concentration? b. An environmental concern involves the destructive effects of acid rain. The most acidic rainfall ever had a of 2.4. What was the hydrogen ion concentration? c. How many times greater is the hydrogen ion concentration of the acidic rainfall in part (b) than the normal rainfall in part (a)? (pH SCALE CAN'T COPY)

Use the formula \(t=\frac{\ln 2}{k}\) that gives the time for a population with a growth rate \(k\) to double to solve Exercises \(35-36 .\) Express each answer to the nearest whole year. The growth model \(A=112.5 e^{0.012 y}\) describes Mexico's population, \(A,\) in millions, \(t\) years after 2010 . a. What is Mexico's growth rate? b. How long will it take Mexico to double its population?

Would you prefer that your salary be modeled exponentially or logarithmically? Explain your answer.

Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$5^{3 x-1}=125$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.