/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Solve each exponential equation ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$3^{2 x+1}=27$$

Short Answer

Expert verified
The solution to the equation is \(x = 1\).

Step by step solution

01

Express both sides as powers of the same base

The given equation is \(3^{2 x+1}=27\). Since 27 can be written as \(3^3\), the equation can be rewritten as \(3^{2x+1} = 3^3\).
02

Equate Exponents

Since the bases on both sides of the equation are same (base 3), the exponents can be equated. Therefore, the equation becomes: \(2x + 1 = 3\).
03

Solve for x

Finally, solve the equation for x. Subtract 1 from both sides of the equation to get \(2x = 3 - 1 = 2\). Then divide both sides by 2 to isolate x: \(x = 2/2 = 1\).

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