/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Solve each exponential equation.... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each exponential equation. Express the solution set in terms of natural logarithms or common logarithms. Then use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. $$2^{2 x}+2^{x}-12=0$$

Short Answer

Expert verified
The solution to the equation \(2^{2x} + 2^x - 12 = 0\) in terms of natural logarithms is \(x = ln(3) \over ln(2)\). The decimal approximation, correct to two decimal places, for \(x\) is 1.58.

Step by step solution

01

Rewrite the Equation

Rewrite the equation to identify it as an equivalent quadratic equation. Let \(u = 2^x\). So, the equation \(2^{2x} + 2^{x} - 12 = 0\) becomes \(u^2 + u - 12 = 0\).
02

Solve the Quadratic Equation

Solve the quadratic equation \(u^2 + u - 12 = 0\) by factoring or using the quadratic formula \(-b \pm sqrt{b^2 - 4ac} \over 2a\). Factoring the equation gives us \((u-3)(u+4)=0\). So, \(u = 3\) or \(u = -4\).
03

Substitute Back and Solve the Exponential Equations

Substitute back \(2^x\) for \(u\). This gives us \(2^x = 3\) and \(2^x = -4\). Solve these equations for \(x\). The equation \(2^x = -4\) has no solution because \(2^x\) is always greater than zero. As for the equation \(2^x = 3\), taking the natural logarithm of both sides gives us \(x = ln(3) \over ln(2)\).
04

Calculate Decimal Approximation

Finally, calculate the decimal approximation for the solution using a calculator. Make sure to round the answer off to two decimal places.

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Most popular questions from this chapter

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