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Use properties of logarithms to expand logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \(\log _{b}\left(\frac{x^{2} y}{z^{2}}\right)\)

Short Answer

Expert verified
The expanded form of the given logarithm expression \(\log _{b}\left(\frac{x^{2} y}{z^{2}}\right)\) without using a calculator is: \(2\log_{b}x + \log_{b}y - 2\log_{b}z\).

Step by step solution

01

Apply the quotient rule of logarithm

To begin with, the quotient in the log can be separated into subtraction of two logs based on the rule. So, \(\log _{b}\left(\frac{x^{2} y}{z^{2}}\right)\) becomes \(\log_{b}(x^2y) - \log_{b}(z^2)\).
02

Apply the product rule of logarithms in the first term

\(\log_{b}(x^2y)\) can be split into the sum of two logs, \(\log_{b}{x^2} + \log_{b}{y}\), so the expression now becomes \(\log_{b}{x^2} + \log_{b}{y} - \log_{b}{z^2}\).
03

Apply power rule of logarithms

Both \(\log_{b}{x^2}\) and \(\log_{b}{z^2}\) can be simplified using the power rule of logarithms, so the expression simplifies further to \(2\log_{b}x + \log_{b}y - 2\log_{b}z\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule of Logarithm
Understanding the quotient rule of logarithms is essential when dealing with division within a logarithmic expression. This rule states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator. In mathematical terms, this is expressed as
\[ \log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y) \].
The core benefit of this rule is its ability to simplify complex logarithmic expressions by breaking them down into more manageable parts. For example, given the expression \( \log _{b}\left(\frac{x^{2} y}{z^{2}}\right) \), you can apply the quotient rule to obtain \( \log_{b}(x^2y) - \log_{b}(z^2) \). This simplification process facilitates easier computation and further manipulation of the logarithmic terms, as seen in the exercise provided.
Product Rule of Logarithms
Moving forward with the product rule of logarithms, this rule empowers you to dissect logarithms of products into sums of logarithms. Formally, it states that
\[ \log_b(xy) = \log_b(x) + \log_b(y) \].
Applying the product rule simplifies multiplication within a logarithm, breaking it down into additive components. Taking the intermediate step from the exercise, \( \log_{b}(x^2y) \), by employing the product rule, we end up with \( \log_{b}{x^2} + \log_{b}{y} \). This division into individual logarithms of the factors makes the expression more straightforward, allowing for the application of additional properties, such as the power rule, which further refines the complexity of the expression. The utilization of the product rule is a keystone in expanding logarithmic expressions to a form that can be easily interpreted or computed.
Power Rule of Logarithms
The power rule of logarithms is a swift way to handle exponents within logarithmic expressions. This powerful rule declares that the logarithm of a number raised to an exponent is equal to the exponent multiplied by the logarithm of the base number. Mathematically, it's presented as
\[ \log_b(x^k) = k \cdot \log_b(x) \].
In the context of our exercise, applying the power rule transforms \( \log_{b}{x^2} \) and \( \log_{b}{z^2} \) into \( 2\log_{b}x \) and \( -2\log_{b}z \) respectively. By doing so, the exponents become coefficients, significantly simplifying the original logarithmic expression. The rule is particularly useful when inversing the process of exponentiation in a logarithm, offering a direct path to reducing complex expressions into more elementary terms. Embracing this rule enhances understanding and solving exercises involving logarithms with precision and ease.

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Most popular questions from this chapter

Evaluate the indicated logarithmic expressions without using a calculator. a. Evaluate: \(\log _{2} 16\) b. Evaluate: \(\log _{2} 32-\log _{2} 2\) c. What can you conclude about $$\log _{2} 16, \text { or } \log _{2}\left(\frac{32}{2}\right) ?$$

Without using a calculator, find the exact value of \(\log _{4}\left[\log _{3}\left(\log _{2} 8\right)\right]\).

The data can be modeled by the function \(f(x)=1.2 \ln x+15.7\) where \(f(x)\) is the percentage of the U.S. gross domestic product going toward health care \(x\) years after \(2006 .\) a. Use the function to determine the percentage of the U.S. gross domestic product that went toward health care in \(2009 .\) Round to the nearest tenth of a percent. Does this underestimate or overestimate the percent displayed by the graph? By how much? b. According to the model, when will \(18.5 \%\) of the U.S. gross domestic product go toward health care? Round to the nearest year.

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. \(\log _{b} x\) is the exponent to which \(b\) must be raised to obtain \(x\).

The percentage of adult height attained by a girl who is \(x\) years old can be modeled by $$f(x)=62+35 \log (x-4)$$ where \(x\) represents the girl's age (from 5 to 15 ) and \(f(x)\) represents the percentage of her adult height. Round answers to the nearest tenth of a percent. Approximately what percentage of her adult height has a girl attained at age ten?

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