/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Solve each exponential equation ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$9^{x}=\frac{1}{\sqrt[3]{3}}$$

Short Answer

Expert verified
The solution to the equation is \(x = -1/6\)

Step by step solution

01

Expressing the base

First, rewrite both sides of the equation using the same base. The number 9 is actually \(3^2\) and the number 1 over cube root of 3 is \((3^{-1/3})\). So, we rewrite the equation as \((3^2)^x = 3^{-1/3}\). This simplifies to \(3^{2x} = 3^{-1/3}\).
02

Equating Exponents

Since the bases are the same on both sides of the equation, we can set the exponents equal to each other. Thus, \(2x = -1/3\).
03

Solving for x

Next, solve the equation for x by dividing both sides by 2. Therefore, \(x = -1/6\).

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