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Describe how to find a parabola's vertex if its equation is expressed in standard form. Give an example.

Short Answer

Expert verified
The vertex of a parabola represented in standard form \(y = ax^2 + bx + c\) is given by \((h, k)\) where \(h = -b/2a\) and \(k\) is the result of substituting \(h\) back into the original equation. For example, for the equation \(y = 2x^2 - 4x + 2\), the vertex is (1, 0).

Step by step solution

01

Understanding Standard Form

A standard form of a quadratic equation is given as \(y = ax^2 + bx + c\). Here, 'a' is the coefficient of \(x^2\), 'b' is the coefficient of 'x', and 'c' is a constant.
02

Vertex Formula

The vertex formula \((h, k)\) for a parabola given by the equation \(y = ax^2 + bx + c\) is derived from completing the square. The x-coordinate of the vertex 'h' can be found using \(-b/2a\). Substituting 'h' in the original equation results in 'k', the y-coordinate of the vertex.
03

Application of the Vertex Formula

For example, let's take a quadratic equation \(y = 2x^2 - 4x + 2\). Here, 'a' is 2 and 'b' is -4. By applying the vertex formula, the 'h' value is given by \(-(-4)/(2*2)\) which is 1. Substitute 'h' (which is 1) into the quadratic equation to find 'k'. Thus, \(y = 2*1^2 - 4*1 + 2 = 0\). So, the vertex of the parabola is (1, 0).
04

Conclusion

Therefore, by using the vertex formula \(-b/2a\) and substituting it back into the quadratic equation, the vertex of the parabola can be found.

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