/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Find an nth-degree polynomial fu... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value. \(n=4 ; i\) and \(3 i\) are zeros; \(f(-1)=20\)

Short Answer

Expert verified
The resulting polynomial is: \(f(x) = x^4 + 10x^2 + 9\).

Step by step solution

01

Find the Conjugate pairs

Given the 4th-degree polynomials with zeros i and 3i. Because the coefficients of the polynomial are real numbers, the conjugate of each complex zero is also a zero of the function. Hence, the zeros should include both i, -i and 3i, -3i.
02

Formulate Polynomial

Our polynomial can be given in the factored form with these zeros as: \(f(x) = a(x-i)(x+i)(x-3i)(x+3i)\). This simplifies to \(f(x) = a[(x^2+1)(x^2+9)] = a(x^4 + 10x^2 + 9)\). Now, we need to determine the value of a.
03

Determine the Leading Coefficient

We know that \(f(-1)=20\). Substitute these values into the equation: \(20 = a((-1)^4 + 10(-1)^2 + 9)\) which simplifies to \(20 = 20a\). Solving this equation yields \(a = 1\).
04

Write Out the Final Polynomial

Now we have obtained the value of a, substitute it back into the polynomial. The final polynomial becomes: \(f(x) = x^4 + 10x^2 + 9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Zeros
When dealing with polynomials, the term 'zero' refers to the values of 'x' where the polynomial equals zero, also known as 'roots'. When a polynomial has real coefficients, zeros can be real or complex numbers. Complex zeros come in pairs that are unique in that they have both a real part and an imaginary part. For example, in the given exercise, the zeros 'i' and '3i' reflect pure imaginary numbers, as they are multiples of the imaginary unit 'i'.

Complex zeros are critical to understanding the nature of polynomial solutions, as they help determine the polynomial's behavior and factorization. They indicate that somewhere in the polynomial, factors exist that will yield these values when set equal to zero. This understanding is essential for students trying to graph these functions or apply them in real-world scenarios where complex numbers are a factor.
Conjugate Pairs
The concept of conjugate pairs is an extension of the complex zeros discussion and revolves around a fundamental theorem in algebra: the Complex Conjugate Root Theorem. This theorem states that for any polynomial with real coefficients, the non-real roots, or complex zeros, must come in conjugate pairs. A conjugate pair consists of two complex numbers of the form 'a + bi' and 'a - bi'.

In practical terms, for the polynomial provided, we started with two given zeros 'i' and '3i', which are pure imaginary. Their conjugates are '-i' and '-3i', respectively. These pairs satisfy the polynomial equation when its coefficients are real. The conjugates' role is crucial as they ensure the polynomial function can retain real coefficients and model real-valued situations.
Leading Coefficient
The leading coefficient of a polynomial is the coefficient of the term with the highest power, which determines the polynomial's end behavior and scaling. It is essentially the multiplier of the highest degree term, and in a standard form polynomial, it is found in front of the variable raised to the nth degree.

In our exercise, determining the leading coefficient was necessary to finalize the polynomial function. Once we established that the coefficient 'a' must be 1 to satisfy the condition '\(f(-1)=20\)', we identified the leading coefficient for our nth-degree polynomial. A leading coefficient that differs from 1 would either stretch or compress the graph of the polynomial and possibly flip it across the x-axis if negative.
Polynomial Function with Real Coefficients
A polynomial function with real coefficients is one where each term is a real number multiplied by a variable raised to a non-negative integer exponent. One important attribute of such functions is that any complex zeros must appear as conjugate pairs. This condition ensures that when the polynomial is simplified, the imaginary parts of these zeros will cancel out, resulting in real coefficients for all terms in the polynomial equation.

The polynomial solution from the exercise demonstrates this perfectly, starting with complex zeros and their conjugates, and combining them into a form '\(f(x) = a(x^4 + 10x^2 + 9)\)' - a polynomial function expressed solely with real coefficients. This adherence ensures the polynomial function is well-defined within the real number system and makes it applicable for a variety of purposes that are grounded in real-world phenomena.

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