/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Solve each polynomial inequality... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each polynomial inequality and graph the solution set on a real number line. Express each solution set in interval notation. $$ 6 x^{2}+x>1 $$

Short Answer

Expert verified
The solution set for the inequality \(6x^2 + x > 1\) in interval notation is \(x \in (-\infty,x_1) \cup (x_2,+\infty)\).

Step by step solution

01

Rewrite the inequality as a quadratic equation

The given inequality is \(6x^2 + x > 1\). The first step is to subtract 1 from both sides of the equation to bring it into a standard quadratic format: \(6x^2 + x - 1 > 0\)
02

Find the roots

To solve for \(x\), use the quadratic formula, \(-b \pm \sqrt{b^2 - 4ac} / 2a\). Here, \(a = 6\), \(b = 1\), and \(c = -1\). Applying these values in the formula, we get the roots \(x_1\) and \(x_2\) as \(x_1=(-1+\sqrt{1+24})/12\) and \(x_2=(-1-\sqrt{1+24})/12\).
03

Check the inequality sign

The inequality is 'greater than', so we look for the values that make the inequality true outside the roots, i.e, \(xx_2\)
04

Express result in interval notation

The interval notation for the inequality is \(x \in (-\infty,x_1) \cup (x_2,+\infty)\)
05

Graph the solution set

On a number line, we pick points that lie in the intervals defined by the roots \(x_1\) and \(x_2\), and shade the region where the inequality holds true. \(-\infty\) to \(x_1\) and \(x_2\) to \(+\infty\) are shaded to denote the solution set.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equation
At the heart of many algebraic problems lies the quadratic equation, which is a polynomial equation of the second degree. The general form is given by \( ax^2 + bx + c = 0 \) where \( a \) is not zero. Solving these equations can be critical to various math and science problems. It's a U-shaped curve on a graph known as a parabola, and it always has two solutions or roots, which could be real or complex. The exercise \( 6x^2 + x > 1 \) is actually an inequality based on a quadratic equation when rearranged to \( 6x^2 + x - 1 > 0 \) and provides a base for finding a range of values for \( x \) that satisfies the inequality.
Quadratic Formula
When faced with a quadratic equation, the quadratic formula \( -b \pm \sqrt{b^2 - 4ac} / (2a) \) is a reliable tool to find the equation's roots or solutions. This formula derives from the process of completing the square and offers a straightforward method to solve any quadratic equation. For the inequality \( 6x^2 + x - 1 > 0 \) from the textbook, \( a = 6 \) , \( b = 1 \) , and \( c = -1 \) when plugged into the formula, yields the solutions for \( x \) as \( x_1 \) and \( x_2 \) which are essentially the points where the graph of the quadratic equation crosses the \( x \) -axis.
Interval Notation
Interval notation provides a concise way to express the range of values that include the solutions to inequalities. It's like describing a stretch of numbers on the number line where a particular condition holds true. When we write \( x \in (-\infty,x_1) \cup (x_2,+\infty) \) , it signifies that \( x \) can be any number less than \( x_1 \) or greater than \( x_2 \) , thereby representing the solutions to the given inequality. This kind of notation is key for communicating solutions in a precise and clear manner, which is particularly helpful during assessments or when conveying mathematical ideas.
Number Line Graphing
Graphing on a number line is an invaluable visual tool that helps to illustrate the solutions to inequalities. When we graph the inequality \( 6x^2 + x - 1 > 0 \) , we mark the roots found by the quadratic formula and shade the regions representing the solution set. For 'greater than' inequalities, the areas outside the roots are shaded. This helps to visually confirm the solution and provides a meaningful connection between algebraic expressions and their graphical representations which can be particularly valuable for visual learners.
Roots of a Polynomial
The roots of a polynomial are the solutions to the equation when set to zero. They're the x-intercepts of the polynomial's graph and represent the values of \( x \) for which the polynomial equals zero. In our exercise \( 6x^2 + x - 1 > 0 \) , we are particularly interested in identifying these roots because they act as critical boundary points that separate the intervals on the number line where the inequality's solutions reside. Analyzing the roots helps in understanding the behavior of the polynomial's graph and thereby the nature of solutions to inequalities involving the polynomial.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The perimeter of a rectangle is 180 feet. Describe the possible lengths of a side if the area of the rectangle is not to exceed 800 square feet.

Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs. Find the kinetic energy for a mass of 4 grams and velocity of 6 centimeters per second.

If you are given the equation of a rational function, explain how to find the horizontal asymptote, if any, of the function's graph.

In this exercise, we lead you through the steps involved in the proof of the Rational Zero Theorem. Consider the polynomial equation $$a_{n} x^{n}+a_{n-1} x^{n-1}+a_{n-2} x^{n-2}+\cdots+a_{1} x+a_{0}=0$$ and let \(\frac{P}{q}\) be a rational root reduced to lowest terms. a. Substitute \(\frac{p}{q}\) for \(x\) in the equation and show that the equation can be written as $$a_{n} p^{n}+a_{n-1} p^{n-1} q+a_{n-2} p^{n-2} q^{2}+\cdots+a_{1} p q^{n-1}=-a_{0} q^{n}$$ b. Why is \(p\) a factor of the left side of the equation? c. Because \(p\) divides the left side, it must also divide the right side. However, because \(\frac{P}{q}\) is reduced to lowest terms, \(p\) and \(q\) have no common factors other than \(-1\) and 1 Because \(p\) does divide the right side and has no factors in common with \(q^{n},\) what can you conclude? d. Rewrite the equation from part (a) with all terms containing \(q\) on the left and the term that does not have a factor of \(q\) on the right. Use an argument that parallels parts (b) and (c) to conclude that \(q\) is a factor of \(a_{n}\).

Use the four-step procedure for solving variation problems given on page 424 to solve. \(a\) varies directly as \(b\) and inversely as the square of \(c . a=7\) when \(b=9\) and \(c=6 .\) Find \(a\) when \(b=4\) and \(c=8\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.