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Divide using long division. State the quotient, q(x), and the remainder, r(x). $$\frac{x^{4}+2 x^{3}-4 x^{2}-5 x-6}{x^{2}+x-2}$$

Short Answer

Expert verified
The quotient, \(q(x)\), is \(x^{2} - x - 3\), and the remainder, \(r(x)\), is \(0\)

Step by step solution

01

Setup

Set up the problem as a long division problem with \(x^{4}+2 x^{3}-4 x^{2}-5 x-6\) as the dividend and \(x^{2}+x-2\) as the divisor.
02

Dividing Leading Terms

Divide the first term of the dividend \(x^{4}\) by the first term of the divisor \(x^{2}\) to get \(x^{2}\), write this as the first term of the quotient.
03

Multiplication and Subtraction

Multiply the divisor \(x^{2}+x-2\) by the first term of the quotient \(x^{2}\). Subtract this result from the original dividend and carry down any terms that have not been incorporated into the division.
04

Repeat Steps 2 and 3

Again, divide the leading term of remaining dividend by the leading term of the divisor, this result is the next term of the quotient, append it to the quotient. Multiply the divisor by that quotient, subtract from the remaining dividend, bring down the next term and continue this process until remainder degree is less than the divisor.
05

Identify Quotient and Remainder

At this point, the quotient and remainder are identified. The quotient, \(q(x)\), is the result of the division and the remainder, \(r(x)\), is the leftover polynomial that cannot be further divided by the divisor. It has degree less than the divisor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dividend and Divisor in Algebra
In algebra, especially when working with polynomials, we often come across the terms dividend and divisor. Understanding these terms is crucial for mastering polynomial long division. In the context of our exercise: \[\begin{equation}\frac{x^{4}+2 x^{3}-4 x^{2}-5 x-6}{x^{2}+x-2}\end{equation}\]the dividend is the polynomial that is being divided, which in our example is \(x^{4}+2 x^{3}-4 x^{2}-5 x-6\). Meanwhile, the divisor is the polynomial by which the dividend is being divided, represented as \(x^{2}+x-2\) in the exercise. The goal of polynomial division is to find how many times the divisor can be 'fit' into the dividend, much like how you might ask how many times 3 fits into 15 when dealing with integers.It's important to lay out the problem correctly as in step 1 of our solution: setting up the dividend and divisor in the proper format to apply long division. This creates a structure that will help you systematically break down the problem through subsequent steps.
The dividend is the 'inside' polynomial and the divisor is the 'outside' one in the long division symbol, much like placing a number inside the division box and the divisor outside when working with numbers. That's your starting point when tackling any polynomial division problem.
Finding Quotient and Remainder
When we divide polynomials using long division, our objective is to find two polynomials: the quotient and the remainder. The quotient is what we get when we successfully divide the dividend by the divisor as many times as possible without going over. The remainder is what is left that cannot be further divided by the divisor because its degree is smaller than the divisor's. The step by step solution to our exercise continues until reaching step 5, where both the quotient and remainder are identified.Let's break this down: when we divide \(x^{4}\) by \(x^{2}\), we obtain the first term of our quotient, \(x^{2}\). This is akin to asking how many times does \(x^{2}\) go into \(x^{4}\) without exceeding it; the answer, which is \(x^{2}\), becomes the first term of our quotient. This process is repeated, bringing down terms from the dividend and incorporating them into this division process to build up the quotient polynomial until there are no terms left to bring down.The remainder, on the other hand, is whatever is left once we can no longer divide. In our case, this will happen when the degree of what remains from the dividend (after all the subtracting and bringing down terms) has a lesser degree than the divisor, \(x^{2}+x-2\). The quotient and remainder together give us a complete picture of what the dividend is made up of in terms of the divisor.
Polynomial Division Steps
The process of long division with polynomials can be seen as a series of repetitive steps, which when followed correctly, reveal the quotient and remainder of the division. The key steps illustrated in our exercise solution provide a clear framework for tackling any polynomial long division:
  • Setup: Organize the dividend and divisor appropriately.
  • Dividing leading terms: Start with the leading term (the term with the highest power) of the dividend, dividing it by the leading term of the divisor to get the first term of the quotient.
  • Multiplication and subtraction: Multiply the entire divisor by the new term in the quotient and subtract this from the remaining dividend to redefine it.
  • Repeat: The process of dividing leading terms and then multiplying and subtracting continues, each time accumulating more terms in the quotient.
  • Identify Quotient and Remainder: Once the degree of the remaining dividend is less than the degree of the divisor, the process concludes, revealing the final quotient and remainder.
Each of these steps must be approached methodically to ensure all terms are accounted for and that there are no miscalculations. Multiplication should distribute across the entire divisor, and subtraction must be performed term-by-term, carrying down any leftover terms from the dividend. Repeat these steps, and the remaining polynomial that can't be divided further due to its smaller degree than the divisor’s becomes the remainder.

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Most popular questions from this chapter

Use the four-step procedure for solving variation problems given on page 424 to solve. \(y\) varies directly as \(x . y=45\) when \(x=5 .\) Find \(y\) when \(x=13 .\)

Whe lise a graphing utility to graph $$ f(x)=\frac{x^{2}-4 x+3}{x-2} \text { and } g(x)=\frac{x^{2}-5 x+6}{x-2} $$ What differences do you observe between the graph of \(f\) and the graph of \(g\) ? How do you account for these differences?

The functions $$f(x)=0.0875 x^{2}-0.4 x+66.6$$ and $$g(x)=0.0875 x^{2}+1.9 x+11.6$$ model a car's stopping distance, \(f(x)\) or \(g(x),\) in feet, traveling at \(x\) miles per hour. Function \(f\) models stopping distance on dry pavement and function g models stopping distance on wet pavement. The graphs of these functions are shown for \(\\{x | x \geq 30\\} .\) Notice that the figure does not specify which graph is the model for dry roads and which is the model for wet roads. Use this information to solve. (GRAPH CANNOT COPY). a. Use the given functions to find the stopping distance on dry pavement and the stopping distance on wet pavement for a car traveling at 55 miles per hour. Round to the nearest foot. b. Based on your answers to part (a), which rectangular coordinate graph shows stopping distances on dry pavement and which shows stopping distances on wet pavement? c. How well do your answers to part (a) model the actual stopping distances shown in Figure 3.43 on page \(411 ?\) d. Determine speeds on wet pavement requiring stopping distances that exceed the length of one and one-half football fields, or 540 feet. Round to the nearest mile per hour. How is this shown on the appropriate graph of the models?

Use the four-step procedure for solving variation problems given on page 424 to solve. \(y\) varies jointly as \(a\) and \(b\) and inversely as the square root of \(c . y=12\) when \(a=3, b=2,\) and \(c=25 .\) Find \(y\) when \(a=5, b=3,\) and \(c=9\).

Will help you prepare for the material covered in the next section. a. If \(y=k x^{2},\) find the value of \(k\) using \(x=2\) and \(y=64\) b. Substitute the value for \(k\) into \(y=k x^{2}\) and write the resulting equation. c. Use the equation from part (b) to find \(y\) when \(x=5\)

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