/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Find the coordinates of the vert... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the coordinates of the vertex for the parabola defined by the given quadratic function. $$f(x)=2 x^{2}-8 x+3$$

Short Answer

Expert verified
The coordinates of the vertex of the parabola defined by the quadratic function \( f(x) = 2x^2 - 8x + 3 \) are (2, -3).

Step by step solution

01

Identify coefficients of the equation

In the quadratic equation \( f(x) = 2x^{2} - 8x + 3 \), identify \( a = 2 \) and \( b = -8 \).
02

Find the x-coordinate of the vertex

Use the formula \( h = -\frac{b}{2a} \) to calculate the x-coordinate of the vertex. Substituting the values, we get \( h = -\frac{-8}{2 \cdot 2}\) which simplifies to \( h = 2 \).
03

Find the y-coordinate of the vertex

Substitute \( h = 2 \) back into the function to get the y-coordinate of the vertex. This gives \( f(2) = 2 \cdot {2}^{2} - 8 \cdot 2 + 3 \). This simplifies to \( f(2) = -3 \). Therefore the y-coordinate, \( k \), is -3.

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