/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Evaluate each function at the gi... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate each function at the given values of the independent variable and simplify. $$ f(x)=\frac{|x+3|}{x+3} $$ a. \(f(5)\) b. \(f(-5)\) c. \(f(-9-x)\)

Short Answer

Expert verified
The solutions are: a. \(f(5) = 1\) b. \(f(-5) = -1\) c. When \(x < -6\), \(f(x) = 1\) and when \(x > -6\), \(f(x) = -1\).

Step by step solution

01

Substitute given values into the function

For each subpart (a, b, c), substitute the given value into the function \(f(x)\) and simplify the equation accordingly.
02

Step 1a: Evaluate \(f(5)\)

For part 'a', \(f(5)\) substitute \(x = 5\) into the function to get \(f(5) = \frac{|5 + 3|}{5 + 3}\). Calculate to get \(f(5) = 1\).
03

Step 1b: Evaluate \(f(-5)\)

For part 'b', \(f(-5)\), substitute \(x = -5\) into the function to get \(f(-5) = \frac{|-5 + 3|}{-5 + 3}\). Calculate to get \(f(-5) = -1\).
04

Step 1c: Evaluate \(f(-9-x)\)

For part 'c', \(f(-9-x)\), substitute \(x = -9 - x\) into the function to get \(f(-9-x) = \frac{|-9 - x + 3|}{-9 - x + 3}\). Simplify the absolute value part \(-9 - x + 3\) to get \(-6 - x\). Consider the two cases for the absolute value: When \(-6 - x\) is positive, which occurs when \(x < -6\), the value inside the absolute value signs is positive, and we get \(f(x) = 1\). When \(-6 - x\) is negative, which occurs when \(x > -6\), the value inside the absolute value signs is negative, and we have to change the sign to get \(f(x) = -1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Value
Understanding absolute value is essential when evaluating certain types of functions. The absolute value of a number is its distance from zero on the number line, regardless of the direction. It is always a positive number or zero. Absolute value is represented by two vertical bars, for example, \( |x+3| \). This means 'regardless of whether \( x+3 \) is positive or negative, take its positive value.'

In the given function \( f(x) = \frac{|x+3|}{x+3} \), the absolute value affects the numerator. Depending on the value of \( x \), the expression inside the absolute value can be negative or positive. The purpose of the absolute value is to ensure that the numerator is always non-negative.
  • If \( x+3 > 0 \), then \( |x+3| = x+3 \).
  • If \( x+3 < 0 \), then \( |x+3| = -(x+3) \).
Piecewise Functions
Piecewise functions are defined by multiple sub-functions, each applying to different parts of the function's domain. For example, \( f(x) = \frac{|x+3|}{x+3} \) can act like a piecewise function based on the value of \( x \). This means the function can take on different expressions depending on the input value.

This specific function has two cases because of the absolute value in the numerator:
  • When \( x+3 > 0 \), the function simplifies to \( f(x) = 1 \), as the numerator and the denominator are equal and positive.
  • When \( x+3 < 0 \), the function simplifies to \( f(x) = -1 \), because the numerator \( |x+3| \) is positive and the denominator \( x+3 \) is negative, making the overall fraction negative.
Understanding piecewise functions helps you anticipate and verify the behavior of complex functions.
Independent Variable Evaluation
Evaluating a function means substituting specific values for the independent variable, commonly \( x \), to find the corresponding function's output. In the exercise, you are given specific values to substitute into the function \( f(x) = \frac{|x+3|}{x+3} \).

Here's how you evaluate:
  • Identify the given value for the independent variable \( x \).
  • Substitute this value into the function, replacing all instances of \( x \) with the given number.
  • Perform arithmetic operations as needed, following the order of operations: absolute values, multiplication and division, etc.

For example:
  • To find \( f(5) \), replace \( x \) with \( 5 \), resulting in \( f(5) = \frac{|5+3|}{5+3} = \frac{8}{8} = 1 \).
  • For \( f(-5) \), replace \( x \) with \( -5 \), giving \( f(-5) = \frac{|-5+3|}{-5+3} = \frac{2}{-2} = -1 \).
  • The result may be affected by the structure of the function, like absolute values or potential piecewise definitions, as seen in \( f(-9-x) \).
Correctly following these steps ensures that you accurately compute the function for any given value of \( x \).

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Most popular questions from this chapter

Furry Finances A pet insurance policy has a monthly rate that is a function of the age of the insured dog or cat. For pets whose age does not exceed \(4,\) the monthly cost is \(\$ 20\). The cost then increases by \(\$ 2\) for each successive year of the pet's age. $$ \begin{array}{cc} \text { Age Not Exceeding } & \text { Monthly Cost } \\ \hline 4 & \$ 20 \\ 5 & \$ 22 \\ 6 & \$ 24 \end{array} $$ The cost schedule continues in this manner for ages not exceeding \(10 .\) The cost for pets whose ages exceed 10 is S40. Use this information to create a graph that shows the monthly cost of the insurance, \(f(x)\), for a pet of age \(x,\) where the function's domain is \([0,14]\)

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