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Chapter 1: Problem 15

Solve each equation in Exercises \(15-34\) by the square root property. $$ 3 x^{2}=27 $$

Short Answer

Expert verified
The solution is \(x = \pm3\).

Step by step solution

01

Isolate x-squared

First we must isolate \(x^2\) on one side of the equation. To do this, divide both sides of the equation by 3: \[x^2 = 27/3\] simplifies to \[x^2 = 9\].
02

Take the square root of both sides

Taking the square root of both sides gives the solutions for x. Remember that when taking square root, it could be positive or negative. Like so: \[\sqrt{x^2} = \pm{\sqrt{9}}\]. This simplifies to \(x = \pm3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are expressions where the highest power of the variable is two. They often appear in the form \(ax^2 + bx + c = 0\). However, in this exercise, the equation has been simplified to a form that you can tackle using the square root property. Understanding quadratic equations helps you see why isolating terms and finding their roots is so powerful.
  • Quadratic equations can have up to two solutions because of the squared variable.
  • These solutions are known as the roots of the equation.
  • By recognizing these equations, you can apply specific strategies like the square root property to solve them.
Quadratics are prevalent in many areas of algebra and real-world applications, from physics to engineering. Recognizing them and knowing how to solve them allows for solving more complex problems effectively.
Isolating Variables
The first step in solving an equation by the square root property involves isolating the variable that is squared. This means getting the squared term, \(x^2\), by itself on one side of the equation. In our example, the equation begins as \(3x^2 = 27\).
  • You perform isolation by dividing both sides of the equation by 3, resulting in \(x^2 = 9\).
  • Isolating variables makes further operations, like taking square roots, straightforward.
  • Sticking to this initial step helps you maintain clarity and prevents mistakes.
When you isolate the squared variable, you set the stage for easily determining the solutions of the equation using the square root property.
Positive and Negative Solutions
After isolating the squared variable, the next step involves dealing with the square root. It's crucial to remember that squaring involves both positive and negative numbers. For example, both \(3^2\) and \((-3)^2\) equal 9, which points to two solutions.
  • When taking the square root, always consider both positive and negative possibilities.
  • This is represented by the symbol \(\pm\), meaning "+ or -".
  • In this exercise, \(x = \pm 3\) provides two solutions: \(x = 3\) and \(x = -3\).
Being aware of the dual nature of square roots ensures that you capture all potential solutions and correctly interpret the results.
Solving Equations
Solving an equation using the square root property simplifies the process of finding the variable's values. Once the squared variable is isolated and you take its square root, you arrive at the solutions. In this exercise, solving \(x^2 = 9\) led to \(x = \pm 3\).
  • This method is quick because it directly finds solutions without additional factoring or completing the square.
  • Remember to verify your solutions by substituting them back into the original equation.
  • This verification ensures that the solutions satisfy the initial problem.
Learning to solve equations using different methods enriches your mathematical toolkit, allowing you to choose an efficient strategy depending on the problem you face.

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Most popular questions from this chapter

A thief steals a number of rare plants from a nursery. On the way out, the thief meets three security guards, one after another. To each security guard, the thief is forced to give one-half the plants that he still has, plus 2 more. Finally, the thief leaves the nursery with 1 lone palm. How many plants were originally stolen?

Exercises \(177-179\) will help you prepare for the material covered in the next section. If \(-8\) is substituted for \(x\) in the equation \(5 x^{\frac{2}{3}}+11 x^{\frac{1}{3}}+2=0\) is the resulting statement true or false?

Each side of a square is lengthened by 3 inches. The area of this new, larger square is 64 square inches. Find the length of a side of the original square.

A piece of wire is 8 inches long. The wire is cut into two pieces and then each piece is bent into a square. Find the length of each piece if the sum of the areas of these squares is to be 2 square inches.

Solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? $$S=\frac{C}{1-r} \text { for } r$$
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