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Chapter 0: Problem 90

Simplify each algebraic expression. $$4(2 y-6)+3(5 y+10)$$

Short Answer

Expert verified
The simplified version of the expression \(4(2 y-6) + 3(5 y+10)\) is \(23y + 6\)

Step by step solution

01

Apply the distributive property

Begin by applying the distributive property. Multiply each term inside the parentheses by the factor outside the parentheses. For the first term, this gives \(4 * 2y = 8y\) and \(4 * -6 = -24\). For the second term, we get \(3 * 5y = 15y\) and \(3 * 10 = 30\). So the expression now becomes \(8y - 24 + 15y + 30\)
02

Combine like terms

Next, combine the similar terms i.e. \(8y + 15y = 23y\) and \(-24 + 30 = 6\). The simplified expression thus becomes \(23y + 6\)

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Most popular questions from this chapter

Determine whether each statement in Exercises 43鈥�50 is true or false. $$-13 \leq-2$$

Evaluate each algebraic expression for the given value or values of the variable(s). $$x^{2}+3 x, \text { for } x=8$$

This will help you prepare for the material covered in the next section. a. Use a calculator to approximate \(\sqrt{300}\) to two decimal places. b. Use a calculator to approximate \(10 \sqrt{3}\) to two decimal places. c. Based on your answers to parts (a) and (b), what can you conclude?

Find all integers \(b\) so that the trinomial can be factored. $$x^{2}+b x+15$$

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Although \(20 x^{3}\) appears in both \(20 x^{3}+8 x^{2}\) and \(20 x^{3}+10 x\) I'll need to factor \(20 x^{3}\) in different ways to obtain each polynomial's factorization
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