/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Add or subtract as indicated. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Add or subtract as indicated. $$\frac{3}{x+1}-\frac{3}{x}$$

Short Answer

Expert verified
The simplified expression is \(\frac{-3}{x(x+1)}\).

Step by step solution

01

Identifying the common denominator

The common denominator needs to be a multiple of both \(x+1\) and \(x\). Since these two expressions are relatively prime (i.e., they don't share factors), their product, \(x(x+1)\), is a common denominator.
02

Adjusting the fractions to have a common denominator

You can rewrite \(\frac{3}{x+1}\) as \(\frac{3x}{x(x+1)}\) and \(\frac{3}{x}\) as \(\frac{3(x+1)}{x(x+1)}\), each time multiplying the numerator and denominator of the fraction by the missing expression from the common denominator. So \(\frac{3}{x+1}-\frac{3}{x}\) becomes \(\frac{3x}{x(x+1)} - \frac{3(x+1)}{x(x+1)}\).
03

Subtraction

Subtract the new expressions. \[\frac{3x}{x(x+1)} - \frac{3(x+1)}{x(x+1)} = \frac{3x - 3(x+1)}{x(x+1)}\] This simplifies to \(\frac{3x - 3x - 3}{x(x+1)}\) or \(\frac{-3}{x(x+1)}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.