/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 $$\text { Factor the difference ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

$$\text { Factor the difference of two squares.}$$ $$x^{2}-100$$

Short Answer

Expert verified
The factorization of \(x^2 - 100\) is \((x - 10)(x + 10)\).

Step by step solution

01

Recognize the Difference of Squares

The given expression is \(x^2 - 100\). This is a difference of squares where \(x^2\) is the first square and \(100\) is the second square.
02

Identify a and b

To factorize this difference of squares, you have to identify \(a\) and \(b\) such that the expression is in the form of \(a^2 - b^2\). In this case, \(a = x\) and \(b = 10\) because \(10^2 = 100\).
03

Apply the Difference of Squares Formula

Substitute \(a = x\) and \(b = 10\) into the formula for factoring a difference of squares, which is \(a^2 - b^2 = (a - b)(a + b)\). This gives \((x - 10)(x + 10)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring polynomials is like finding the ingredients of a mathematical recipe. It involves breaking down an expression into simpler components, or 'factors', that, when multiplied together, give the original polynomial. This is crucial for solving equations and understanding the underlying structure of algebraic expressions. With polynomials, there are different techniques for factoring:
  • Factoring out the Greatest Common Factor (GCF)
  • Using special formulas for specific polynomial forms
  • Factoring by grouping

When you see an expression like \(x^2 - 100\), it can be factored using the special formula for the difference of squares. This is a handy shortcut if you recognize that both parts of the expression are perfect squares. By identifying these key features, you can often simplify complex problems into more manageable steps.
Algebra
Algebra is the language of mathematics. It uses symbols like \(x\) and \(y\) to represent numbers and allows you to write general rules that apply to many situations. It's an essential tool for expressing relationships and solving problems.
One important concept in algebra is understanding expressions and equations. An expression is a combination of numbers and symbols while an equation states that two expressions are equal. Factoring helps you solve equations by simplifying expressions so they can be more easily manipulated.
  • Expressions can often be rearranged or rewritten using factoring.
  • Equations can be solved once they are factored and simplified into a form that makes the solution more straightforward.

When factoring a difference of squares, you turn a polynomial which might feel complex into a product of binomials which makes it easier for equation solving.
Quadratic Expressions
Quadratic expressions are polynomial expressions of degree two, typically written in the form \(ax^2 + bx + c\). These expressions are common in algebra and appear in various applications like physics, engineering, and finance. Understanding how to manipulate and solve them is a critical skill.
One specific type of quadratic expression is a difference of squares, which looks like \(a^2 - b^2\). This type of expression can be factored quickly and easily using the formula
  • \(a^2 - b^2 = (a - b)(a + b)\)

In our example, \(x^2 - 100\) is a quadratic expression that fits the difference of squares pattern. This is because both \(x^2\) and \(100\) (which is \(10^2\)) are perfect squares. By recognizing this pattern, you can use the formula, simplifying the expression to \((x - 10)(x + 10)\). This technique makes it easier to handle and apply these expressions in various problem-solving scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Your computer store is having an incredible sale. The price on one model is reduced by \(40 \% .\) Then the sale price is reduced by another \(40 \% .\) If \(x\) is the computer's original price, the sale price can be modeled by $$(x-0.4 x)-0.4(x-0.4 x)$$ a. Factor out \((x-0.4 x)\) from each term. Then simplify the resulting expression. b. Use the simplified expression from part (a) to answer these questions. With a \(40 \%\) reduction followed by a \(40 \%\) reduction, is the computer selling at \(20 \%\) of its original price? If not, at what percentage of the original price is it selling?

A football was kicked vertically upward from a height of 4 feet with an initial speed of 60 feet per second. The formula $$h=4+60 t-16 t^{2}$$ describes the ball's height above the ground, \(h,\) in feet, \(t\) seconds after it was kicked. Use this formula to solve Exercises \(19-20 .\) What was the ball’s height 2 seconds after it was kicked?

Evaluate each algebraic expression for the given value or values of the variable(s). $$x^{2}+5 x, \text { for } x=6$$

A football was kicked vertically upward from a height of 4 feet with an initial speed of 60 feet per second. The formula $$h=4+60 t-16 t^{2}$$ describes the ball's height above the ground, \(h,\) in feet, \(t\) seconds after it was kicked. Use this formula to solve Exercises \(19-20 .\) What was the ball’s height 3 seconds after it was kicked?

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$8^{-\frac{1}{3}}=-2$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.