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Chapter 0: Problem 15

Evaluate each algebraic expression for the given value or values of the variable(s). $$\frac{2 x+3 y}{x+1}, \text { for } x=-2 \text { and } y=4$$

Short Answer

Expert verified
-8

Step by step solution

01

Substitute

Replace \(x\) with \(-2\) and \(y\) with \(4\) in the given expression. So, the expression becomes \(\frac{2(-2)+3(4)}{(-2)+1}\).
02

Simplify the Numerator and Denominator

Now perform the multiplication and addition in the numerator and denominator. After simplifying the expression becomes \(\frac{-4+12}{-1}\).
03

Further Simplification

Perform addition in the numerator and simplify the fraction to get the final result. This gives \(\frac{8}{-1} = -8\).

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Most popular questions from this chapter

Using an example, explain how to factor out the greatest common factor of a polynomial.

$$\text { Factor completely.}$$ $$(x-y)^{4}-4(x-y)^{2}$$

$$\text { Factor completely.}$$ $$10 x^{2}(x+1)-7 x(x+1)-6(x+1)$$

Factor and simplify each algebraic expression. $$\left(x^{2}+3\right)^{-\frac{2}{3}}+\left(x^{2}+3\right)^{-\frac{5}{3}}$$

Factor the numerator and the denominator. Then simplify by dividing out the common factor in the numerator and the denominator. $$\frac{x^{2}+6 x+5}{x^{2}-25}$$
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