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Write an inequality to represent the given statement. The value of \(y\) is at least 10 , but less than 20 .

Short Answer

Expert verified
The inequality is \(10 \leq y < 20 \).

Step by step solution

01

Understand the Problem

The problem requires writing an inequality that describes the value of a variable, y, which is at least 10 but less than 20.
02

Identify Key Terms

The term 'at least 10' means that the smallest value y can take is 10, inclusive. The term 'less than 20' means that the largest value y can take is 19.99..., exclusive of 20.
03

Write the Inequality

Combine the information from the previous step to write the inequality. Since y must be at least 10, we write it as \( y \geq 10 \). Since y must be less than 20, we write it as \( y < 20 \). Combining these results, the inequality is: \(10 \leq y < 20 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

inequality notation
Inequalities are mathematical expressions that show the relative size of values. Unlike equations, which show equality, inequalities express relationships where one value is greater or less than another. To notate inequalities, we use special symbols:
  • \(< >\) - Greater than
  • \(< <\) - Less than
  • \( \geq \) - Greater than or equal to
  • \( \leq \) - Less than or equal to
When writing inequalities, it's crucial to understand whether the boundaries are inclusive or exclusive. If they are inclusive (i.e., the value is included in the range), we use the \( \leq \) or \( \geq \) symbols. If they are exclusive, we use \(<\) or \(>\) symbols. For example, in the inequality \(10 \leq y < 20\), 10 is included in the range as indicated by the \(\leq\) symbol, while 20 is not included, as shown by the \(<\) symbol.
solving inequalities
Solving inequalities is similar to solving equations, with a few extra rules. The goal is to find the range of values for the variable that makes the inequality true. Here's the process broken down:
  • Isolate the variable: Use algebraic operations to get the variable on one side of the inequality.
  • Perform operations carefully: You can add, subtract, multiply, or divide both sides of an inequality by the same positive number without changing the inequality's direction. However, if you multiply or divide by a negative number, you must flip the inequality sign.
  • Combine inequalities carefully: If you have multiple inequalities, consider them together to determine the overlapping range that satisfies all conditions.
For example, to solve \(2x + 3 < 15\), you would first subtract 3 from both sides to get \(2x < 12\). Then, divide by 2, yielding \(x < 6\). So, any value less than 6 satisfies the inequality.
compound inequalities
Compound inequalities involve more than one inequality statement connected by the words 'and' or 'or'. These are often used to describe a range of values.

'And' Compound Inequalities: This means both conditions should be true simultaneously. For example, \( 1 < x \leq 4 \) means that \( x \) must be greater than 1 and less than or equal to 4. To solve, find the values that satisfy both conditions.

'Or' Compound Inequalities: This means either condition can be true. For instance, \( x < -2 \) or \( x > 3 \) indicates that \( x \) can be any value less than -2 or any value greater than 3. To solve, find the values that satisfy either condition.
An example from our exercise is the compound inequality \( 10 \leq y < 20 \). This particular inequality tells us that \( y \) must be at least 10 (inclusive) and less than 20 (exclusive). When solving such inequalities, it's critical to consider both parts to determine where they overlap.

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Most popular questions from this chapter

A sporting goods store sells two types of exercise bikes. The deluxe model costs the store $$\$ 540$$ from the manufacturer and the standard model costs the store $$\$ 420$$ from the manufacturer. The profit that the store makes on the deluxe model is $$\$ 180$$ and the profit on the standard model is $$\$ 120$$. The monthly demand for exercise bikes is at most \(30 .\) Furthermore, the store manager does not want to spend more than $$\$ 14,040$$ on inventory for exercise bikes. a. Determine the number of deluxe models and the number of standard models that the store should have in its inventory each month to maximize profit. (Assume that all exercise bikes in inventory are sold.) b. What is the maximum profit? c. If the profit on the deluxe bikes were $$\$ 150$$ and the profit on the standard bikes remained the same, how many of each should the store have to maximize profit?

A manufacturer produces two models of a gas grill. Grill A requires 1 hr for assembly and \(0.4 \mathrm{hr}\) for packaging. Grill \(B\) requires 1.2 hr for assembly and 0.6 hr for packaging. The production information and profit for each grill are given in the table. (See Example 4\()\) $$ \begin{array}{|l|c|c|c|} \hline & \text { Assembly } & \text { Packaging } & \text { Profit } \\ \hline \text { Grill A } & 1 \mathrm{hr} & 0.4 \mathrm{hr} & \$ 90 \\ \hline \text { Grill B } & 1.2 \mathrm{hr} & 0.6 \mathrm{hr} & \$ 120 \\ \hline \end{array} $$ The manufacturer has \(1200 \mathrm{hr}\) of labor available for assembly and \(540 \mathrm{hr}\) of labor available for packaging. a. Determine the number of grill A units and the number of grill B units that should be produced to maximize profit assuming that all grills will be sold. b. What is the maximum profit under these constraints? c. If the profit on grill A units is $$\$ 110$$ and the profit on grill \(\underline{B}\) units is unchanged, how many of each type of grill unit should the manufacturer produce to maximize profit?

Use a graphing utility to graph the solution set to the system of inequalities. \(y<\frac{4}{x^{2}+1}\) \(y>\frac{-2}{x^{2}+0.5}\)

Solve the system by using any method. If a system does not have one unique solution, state whether the system is inconsistent or whether the equations are dependent. (See Examples \(5-6\) ) $$ \begin{array}{r} 3 x+y=6 \\ x+\frac{1}{3} y=2 \end{array} $$

Solve the system using any method. $$ \begin{array}{l} y=-\frac{1}{4} x+7 \\ y=-\frac{3}{2} x+17 \end{array} $$

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