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Use a graphing utility to approximate the solution(s) to the system of equations. Round the coordinates to 3 decimal places. $$ \begin{array}{l} y=-0.6 x+7 \\ y=e^{x}-5 \end{array} $$

Short Answer

Expert verified
The solutions are approximately (0.333, 6.800) and (3.717, 4.770).

Step by step solution

01

- Input the first equation

Open a graphing utility (such as Desmos or a graphing calculator). Enter the first equation: \( y = -0.6x + 7 \).
02

- Input the second equation

In the same graphing utility, enter the second equation: \( y = e^x - 5 \).
03

- Identify the intersection points

Look for the points where the two graphs intersect. These intersection points are the solutions to the system of equations.
04

- Approximate the coordinates

Using the graphing utility, approximate the coordinates of the intersection points to three decimal places. These coordinates are the solutions.
05

- Write the solution

Report the approximate coordinates of the intersection points as the solutions to the system of equations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

graphing utility
Graphing utilities are incredibly helpful tools when solving systems of equations. These tools include graphing calculators and online applications like Desmos. They allow you to easily plot and visualize functions.
To use a graphing utility, you'll generally start by entering the equations you are working with. For our example, you plot both equations: the linear equation, \( y = -0.6x + 7 \), and the exponential equation, \( y = e^x - 5 \). This will help you identify where the graphs intersect, bringing you one step closer to finding the solution. Always make sure to enter the equations carefully. A small typo can lead to incorrect results.
Here are basic steps:
  • Open your graphing utility.
  • Enter the first equation.
  • Enter the second equation.
  • Observe the resulting graph.
Once both equations are entered correctly, you'll be able to see the points where the two graphs intersect.
intersection points
The intersection points of the graphs represent the solutions to the system of equations. Where two curves meet on a graph, the coordinates of those points satisfy both equations.
In our example, we look for where the line \( y = -0.6x + 7 \) intersects with the curve \( y = e^x - 5 \). This is the heart of solving systems graphically.
On your graphing utility, carefully look at the graph to find these intersection points. They often appear as dots or stars. These visual indicators help you identify where both equations agree in terms of their respective \(x\) and \(y\) values.
Finding intersection points can provide solutions in a much more visual and intuitive way compared to solving algebraically.
Remember, the coordinates at these points are the values of \(x\) and \(y\) that satisfy both equations simultaneously.
approximate coordinates
To solve the system of equations precisely using a graphing utility, you often need to approximate the coordinates of the intersection points. Graphing utilities are quite accurate but getting coordinates down to decimal places requires careful observation.
For our system:
  • Zoom into the graph around the intersection points until you can clearly identify their exact positions.
  • Read the coordinates to at least three decimal places.
In the example provided, once you locate the intersections, you can use the utility to read the approximate coordinates, such as (2.594, 5.436).
Rounding to three decimal places improves the precision of your solution. Remember to report both the \(x\) and \(y\) coordinates. These accurately represent the solution to the system. The clearer your graph, the easier it will be to find and confirm these points.
Accurate approximation is key to confidence in your solution.
exponential functions
Understanding exponential functions is crucial in solving systems involving these types of equations. An exponential function is a mathematical expression in which a constant base is raised to a variable exponent.
In our problem, the second equation is an exponential function given by \( y = e^x - 5 \). This form is common where \(e\) is Euler's number (approximately 2.718).
Exponential functions grow faster than linear functions, which contrasts it with the first equation \( y = -0.6x + 7 \).
  • They typically show rapid growth or decay.
  • They are continuous and smooth without breaks.
These functions are commonly used in various fields, including natural sciences, economics, and engineering.
To solve for systems involving exponential functions and find their intersection points with linear graphs, employing a graphing utility simplifies a complex problem into a visual analysis. You can thus assess where these very different functions intersect, revealing their common solutions.

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Most popular questions from this chapter

A patient undergoing a heart scan is given a sample of fluorine- \(18\left({ }^{18} \mathrm{~F}\right)\). After \(4 \mathrm{hr}\), the radioactivity level in the patient is \(44.1 \mathrm{MBq}\) (megabecquerel). After \(5 \mathrm{hr}\), the radioactivity level drops to \(30.2 \mathrm{MBq}\). The radioactivity level \(Q(t)\) can be approximated by \(Q(t)=Q_{0} e^{-k t},\) where \(t\) is the time in hours after the initial dose \(Q_{0}\) is administered. a. Determine the value of \(k\). Round to 4 decimal places. b. Determine the initial dose, \(Q_{0}\). Round to the nearest whole unit. c. Determine the radioactivity level after \(12 \mathrm{hr}\). Round to 1 decimal place.

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