/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Graph the solution set. If there... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph the solution set. If there is no solution, indicate that the solution set is the empty set. \(y \geq \frac{1}{3} x-2\) \(y \leq x-4\)

Short Answer

Expert verified
The solution set is the area where the shaded regions overlap.

Step by step solution

01

Graph the first inequality

Start by converting the inequality into an equation: \(y = \frac{1}{3}x - 2\). This is the boundary line. Next, plot the boundary line on a coordinate plane. Since the inequality is \(y \geq \frac{1}{3}x - 2\), shade the area above the line.
02

Graph the second inequality

Convert the second inequality into an equation: \(y = x - 4\). Plot this line on the same coordinate plane. Since the inequality is \(y \leq x - 4\), shade the area below the line.
03

Find the intersection of the shaded areas

Identify where the shaded regions from Step 1 and Step 2 overlap. This common area represents the solution set.
04

Check for solutions

Verify if there is any overlap. If the shaded areas do overlap, the intersection is the solution set. Otherwise, declare the solution set as the empty set.
05

Conclude the solution

Since the shaded regions from \( y \geq \frac{1}{3}x - 2 \) and \( y \leq x - 4 \) do overlap, the solution set includes all points in the overlapping region.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

inequalities in two variables
Understanding inequalities in two variables is important in algebra. An **inequality** shows the relation between two expressions using inequality symbols like <, >, ≤, or ≥. When we talk about **inequalities in two variables**, it means we're dealing with expressions involving both x and y, such as in the exercise where we had the inequalities:
- \(y \, \geq \, \frac{1}{3} \ x - 2\)
- \(y \, \leq \, x - 4\)
These inequalities don't just define a single line **(as in linear equations)** but a whole region on the coordinate plane. The solutions to these inequalities form a set of points (x, y) that can be plotted on a coordinate plane.
The key steps to graphing inequalities involve first converting the inequalities to equations, plotting the boundary line, and then shading the appropriate side of the line that represents the inequality.
linear inequalities
A linear inequality looks much like a linear equation but with an inequality sign instead of an equals sign. Linear inequalities can be written in forms such as \(ax + by > c\), \(ax + by < c\), \(ax + by \leq c\), or \(ax + by \geq c\). For our example:
- The first inequality is \(y \, \geq \, \frac{1}{3} \ x - 2\). This is equivalent to \(y = \frac{1}{3} \ x - 2\) which can be plotted as a boundary line.
- The second inequality is \(y \, \leq \, x - 4\), similarly, we plot this as \(y = x - 4\) for the boundary.
The boundary line helps us visualize the limits beyond which the inequality does not hold. The inequality symbol will dictate which direction we should shade:
  • Greater than (≥ or >): Shade above the line.
  • Less than (≤ or <): Shade below the line.
By shading, we represent all the possible (x, y) values that satisfy the inequality.
solution set
The **solution set** for inequalities includes all the points that satisfy both inequalities in a system. To find this:
1. Plot the boundary lines for both inequalities on the same coordinate plane.
2. Shade the area that satisfies each inequality.
For our exercise, shading the area above \(y = \frac{1}{3} \ x - 2\) and below \(y = x - 4\) helps us visualize the solution set. The overlap of these regions represents the common solutions.
If these shaded regions overlap, this overlap is our solution set. If they do not overlap, the solution set is empty, indicating there are no common solutions that meet both inequalities.
graphing on the coordinate plane
Graphing on the coordinate plane allows us to visually represent our inequalities and easily identify the solution set. Here are the basic steps:
1. **Plot the boundary lines: Convert each inequality to an equation and plot it.** For \( y \, \geq \, \frac{1}{3} \ x - 2\) and \(y \, \leq \, x - 4\), plot the lines \( y = \, \frac{1}{3} \ x - 2\) and \( y = \, x - 4\).
2. **Decide on line style: Use a solid line for ≤ or ≥ and a dashed line for < or >.** Both our inequalities use solid lines.
3. **Shade the appropriate region:** To determine which side to shade, pick a test point (0,0) and see if it satisfies the inequality. Then shade accordingly.
  • For \( y \, \geq \, \frac{1}{3} \ x - 2\), shade above the line.
  • For \( y \, \leq \, x - 4\), shade below the line.

The region where both shades overlap is the solution set. In our example, this is the intersection of the two shaded areas. With practice, this method of graphing becomes intuitive and allows for quick visual representation of solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The average of an electrician's hourly wage and a plumber's hourly wage is \(\$ 33 .\) One day a contractor hires the electrician for \(8 \mathrm{hr}\) of work and the plumber for \(5 \mathrm{hr}\) of work and pays a total of \(\$ 438\) in wages. Find the hourly wage for the electrician and for the plumber.

To protect soil from erosion, some farmers plant winter cover crops such as winter wheat and rye. In addition to conserving soil, cover crops often increase crop yields in the row crops that follow in spring and summer. Suppose that a farmer has 800 acres of land and plans to plant winter wheat and rye. The input cost for 1 acre for each crop is given in the table along with the cost for machinery and labor. The profit for 1 acre of each crop is given in the last column. $$ \begin{array}{|l|c|c|c|} \hline & \begin{array}{c} \text { Input Cost } \\ \text { per Acre } \end{array} & \begin{array}{c} \text { Labor/Machinery } \\ \text { Cost per Acre } \end{array} & \begin{array}{c} \text { Profit } \\ \text { per Acre } \end{array} \\ \hline \text { Wheat } & \$ 90 & \$ 50 & \$ 42 \\ \hline \text { Rye } & \$ 120 & \$ 40 & \$ 35 \\ \hline \end{array} $$ Suppose the farmer has budgeted a maximum of $$\$ 90,000$$ for input costs and a maximum of $$\$ 36,000$$ for labor and machinery. a. Determine the number of acres of each crop that the farmer should plant to maximize profit. (Assume that all crops will be sold.) b. What is the maximum profit? c. If the profit per acre for wheat were $$\$ 40$$ and the profit per acre for rye were $$\$ 45$$, how many acres of each crop should be planted to maximize profit?

Write a system of inequalities that represents the points inside the triangle with vertices \((-3,-4),(3,2),\) and (-5,4).

Solve the system of equations by using the substitution method. (See Example 2\()\) $$ \begin{array}{rr} x+3 y= & 5 \\ 3 x-2 y= & -18 \end{array} $$

A paving company delivers gravel for a road construction project. The company has a large truck and a small truck. The large truck has a greater capacity, but costs more for fuel to operate. The load capacity and cost to operate each truck per load are given in the table. $$ \begin{array}{|l|c|c|} \hline & \text { Load Capacity } & \text { Cost per Load } \\ \hline \text { Small truck } & 18 \mathrm{yd}^{3} & \$ 120 \\ \hline \text { Large truck } & 24 \mathrm{yd}^{3} & \$ 150 \\ \hline \end{array} $$ The company must deliver at least 288 yd \(^{3}\) of gravel to stay on schedule. Furthermore, the large truck takes longer to load and cannot make as many trips as the small truck. As a result, the number of trips made by the large truck is at most \(\frac{3}{4}\) times the number of trips made by the small truck. a. Determine the number of trips that should be made by the large truck and the number of trips that should be made by the small truck to minimize cost. b. What is the minimum cost to deliver gravel under these constraints?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.