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Solve the system using any method. $$ \begin{array}{l} \frac{x-2}{8}+\frac{y+1}{2}=-6 \\ \frac{x-2}{2}-\frac{y+1}{4}=12 \end{array} $$

Short Answer

Expert verified
The solution is \( x = 18 \) and \( y = -17 \).

Step by step solution

01

Simplify the First Equation

Rewrite the first equation: \( \frac{x-2}{8} + \frac{y+1}{2} = -6 \). To simplify, find a common denominator (8) and rewrite: \[ \frac{x-2}{8} + \frac{4(y+1)}{8} = -6 \] Combine the terms: \[ \frac{x - 2 + 4y + 4}{8} = -6 \] Multiply everything by 8 to clear the fraction: \[ x + 4y + 2 = -48 \] Simplify to: \[ x + 4y = -50 \]
02

Simplify the Second Equation

Rewrite the second equation: \( \frac{x-2}{2} - \frac{y+1}{4} = 12 \). To simplify, find a common denominator (4) and rewrite: \[ \frac{2(x-2)}{4} - \frac{y+1}{4} = 12 \] Combine the terms: \[ \frac{2x - 4 - y - 1}{4} = 12 \] Multiply everything by 4 to clear the fraction: \[ 2x - y - 5 = 48 \] Simplify to: \[ 2x - y = 53 \]
03

Solve the Simplified System

Now, solve the system of simplified equations: 1) \( x + 4y = -50 \) 2) \( 2x - y = 53 \) First, multiply the first equation by 2 to align the coefficients of \( x \): \[ 2(x + 4y) = 2(-50) \] Which simplifies to: \[ 2x + 8y = -100 \] Now use the elimination method. Subtract the second equation from this new equation: \[ 2x + 8y - (2x - y) = -100 - 53 \] This results in: \[ 9y = -153 \] Divide by 9: \[ y = -17 \]
04

Substitute y back into One Equation

Now substitute \( y = -17 \) back into the first simplified equation, \( x + 4y = -50 \): \[ x + 4(-17) = -50 \] This simplifies to: \[ x - 68 = -50 \] Add 68 to both sides: \[ x = 18 \]
05

Verify the Solution

Substitute \( x = 18 \) and \( y = -17 \) back into the original equations to verify. First equation: \[ \frac{18-2}{8} + \frac{-17+1}{2} = -6 \rightarrow \frac{16}{8} + \frac{-16}{2} = -6 \rightarrow 2 - 8 = -6 \quad True \] Second equation: \[ \frac{18-2}{2} - \frac{-17+1}{4} = 12 \rightarrow \frac{16}{2} - \frac{-16}{4} = 12 \rightarrow 8 + 4 = 12 \quad True \] Both equations hold true, confirming the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

fraction elimination
When solving systems of equations, fractions can make the process more complicated. Thus, eliminating fractions makes equations easier to manage. To do this, you can multiply every term by the least common denominator (LCD). This step transforms fractions into whole numbers.

For instance, in the equation \( \frac{x-2}{8} + \frac{y+1}{2} = -6 \), notice the LCD is 8. By multiplying each term by 8, the equation becomes fraction-free: \ \( 8 \times \frac{x-2}{8} + 8 \times \frac{y+1}{2} = -6 \times 8 \ x-2 + 4(y+1) = -48 \ x + 4y + 2 = -48 \ x + 4y = -50 \ \).

Similarly, apply the same technique to the second equation. The objective is to rewrite equations in simpler formats to make onward steps, like substitution or elimination, more manageable.
variable substitution
Variable substitution involves replacing one variable with an equivalent expression involving the other variable. This method is effective after simplifying the equations.

First, solve one equation for one variable. Let's take \( x + 4y = -50 \) and rearrange it for \( x \): \ \( x = -50 - 4y \ \).

Next, substitute this expression into the other equation. Substituting \( x = -50 - 4y \) into \( 2x - y = 53 \) gives: \ \( 2(-50-4y) - y = 53 \ -100 - 8y - y = 53 \ -9y = 153 \ y = -17 \ \).

Substitution simplifies the remaining efforts to solve the system by reducing the number of variables.
verification of solutions
Verification ensures that your solutions satisfy the original equations. This step is crucial because errors can occur during arithmetic manipulations.

To verify, substitute the found values back into the original equations. Our solutions are \( x = 18 \) and \( y = -17 \).

First Equation: \( \frac{18-2}{8} + \frac{-17+1}{2} = -6 \ \frac{16}{8} + \frac{-16}{2} = -6 \ 2 - 8 = -6 \ -6 = -6 \ \), which is true.

Second Equation: \( \frac{18-2}{2} - \frac{-17+1}{4} = 12 \ \frac{16}{2} - \frac{-16}{4} = 12 \ 8 + 4 = 12 \ 12 = 12 \ \), which also holds true.

Both verifications confirm that our solutions are correct.
common denominators
Finding common denominators is essential for combining fractions effectively. The first step involves identifying the Least Common Denominator (LCD), the smallest number both denominators can divide.

For instance, in \( \frac{x-2}{8} + \frac{y+1}{2} \ \), 8 is the LCD between 8 and 2. Rewriting \( \frac{y+1}{2} \ \) as \( \frac{4(y+1)}{8} \ \) makes combining fractions straightforward: \ \( \frac{x-2 + 4(y+1)}{8} = -6 \ \).

The same method simplifies equations by dealing with one denominator.

In the second equation, \( \frac{x-2}{2} - \frac{y+1}{4} \ \), the LCD is 4. By rewriting and using the common denominator, we get: \ \( \frac{2(x-2)}{4} - \frac{y+1}{4} \ \), further simplifying helps to combine and solve easily. This makes managing equations systematically easier.

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Most popular questions from this chapter

A fishing boat travels along the east coast of the United States and encounters the Gulf Stream current. It travels \(44 \mathrm{mi}\) north with the current in \(2 \mathrm{hr}\). It travels \(56 \mathrm{mi}\) south against the current in \(4 \mathrm{hr}\). Find the speed of the current and the speed of the boat in still water.

The minimum and maximum distances from a point \(P\) to a circle are found using the line determined by the given point and the center of the circle. Given the circle defined by \(x^{2}+y^{2}=9\) and the point \(P(4,5)\), a. Find the point on the circle closest to the point (4,5) . b. Find the point on the circle furthest from the point (4,5) .

Josh makes \(\$ 24 /\) hr tutoring chemistry and \(\$ 20 / \mathrm{hr}\) tutoring math. Let \(x\) represent the number of hours per week he spends tutoring chemistry. Let \(y\) represent the number of hours per week he spends tutoring math. a. Write an objective function representing his weekly income for tutoring \(x\) hours of chemistry and \(y\) hours of math. b. The time that Josh devotes to tutoring is limited by the following constraints. Write a system of inequalities representing the constraints. \- The number of hours spent tutoring each subject cannot be negative. \- Due to the academic demands of his own classes he tutors at most \(18 \mathrm{hr}\) per week. \- The tutoring center requires that he tutors math at least 4 hr per week. \- The demand for math tutors is greater than the demand for chemistry tutors. Therefore, the number of hours he spends tutoring math must be at least twice the number of hours he spends tutoring chemistry. c. Graph the system of inequalities represented by the constraints. d. Find the vertices of the feasible region. e. Test the objective function at each vertex. f. How many hours tutoring math and how many hours tutoring chemistry should Josh work to maximize his income? g. What is the maximum income? h. Explain why Josh's maximum income is found at a point on the line \(x+y=18\).

Solve the system. $$ \begin{array}{l} (x-1)^{2}+(y+1)^{2}=5 \\ x^{2}+(y+4)^{2}=29 \end{array} $$

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