/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 90 Beginning on January 1 , park ra... [FREE SOLUTION] | 91Ó°ÊÓ

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Beginning on January 1 , park rangers in Everglades National Park began recording the water level for one particularly dry area of the park. The water level was initially \(2.5 \mathrm{ft}\) and decreased by approximately \(0.015 \mathrm{ft} /\) day. a. Write a function representing the water level \(L(x)\) (in \(\mathrm{ft}\) ), \(x\) days after January \(1 .\) b. Write an equation for \(L^{-1}(x)\). c. What does the inverse function represent in the context of this problem? d. Evaluate \(L^{-1}(1.9)\) and interpret its meaning in context.

Short Answer

Expert verified
a. \(L(x) = 2.5 - 0.015x\) b. \(L^{-1}(x) = \frac{2.5 - x}{0.015}\) c. Days to reach a certain water level. d. 40 days.

Step by step solution

01

Define the initial condition and rate of change

The initial water level is given as 2.5 ft. The rate at which the water level decreases each day is 0.015 ft/day. These values will be used to form the function representing the water level.
02

Write the function for water level L(x)

The water level decreases linearly, so the function can be written as: \[L(x) = 2.5 - 0.015x\]where \(L(x)\) represents the water level in feet, and \(x\) represents the number of days after January 1.
03

Solve for the inverse function

To find the inverse function, \(L^{-1}(x)\), switch \(x\) and \(L(x)\) and solve for \(x\):1. Start with the original function: \[L(x) = 2.5 - 0.015x\]2. Replace \(L(x)\) with \(y\): \[y = 2.5 - 0.015x\]3. Swap \(x\) and \(y\): \[x = 2.5 - 0.015y\]4. Solve for \(y\):\[0.015y = 2.5 - x\]\[y = \frac{2.5 - x}{0.015}\]So, the inverse function is:\[L^{-1}(x) = \frac{2.5 - x}{0.015}\]
04

Interpret the inverse function

The inverse function \(L^{-1}(x)\) represents the number of days after January 1 required for the water level to reach \(x\) feet.
05

Evaluate the inverse function at a specific value

To evaluate \(L^{-1}(1.9)\), substitute 1.9 for \(x\) in the inverse function:\[L^{-1}(1.9) = \frac{2.5 - 1.9}{0.015} = \frac{0.6}{0.015} = 40\]This means it takes 40 days for the water level to decrease to 1.9 feet.
06

Interpret the meaning of the evaluation

The value \(L^{-1}(1.9) = 40\) indicates that on the 40th day after January 1, the water level in the park will be 1.9 feet.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
Inverse functions are a way to reverse the effects of a given function. If you know the output of a function, you can use its inverse to find the corresponding input.
For the given problem, the water level function is linear: \(L(x) = 2.5 - 0.015x\). This means the water level decreases by 0.015 feet each day, starting from an initial level of 2.5 feet.
To find the inverse function, we start by swapping the dependent and independent variables and solving for the original variable. For \(L(x) = 2.5 - 0.015x\), the steps are:
1. Replace \(L(x)\) with \(y\): \(y = 2.5 - 0.015x\)
2. Swap the variables: \(x = 2.5 - 0.015y\)
3. Solve for \(y\): \(y = \frac{2.5 - x}{0.015}\)
The resulting inverse function, \(L^{-1}(x) = \frac{2.5 - x}{0.015}\), tells us the number of days it takes for the water level to reach a specific height. This inverse function is valuable in real-world problems where you might need to know when a certain condition will be met.
Rate of Change
The rate of change explains how one quantity changes in relation to another. In our problem, the rate of change is the daily decrease in water level, given as 0.015 feet per day.
Mathematically, it's represented by the coefficient of the variable in the linear function \(L(x) = 2.5 - 0.015x\). This negative rate indicates a decline in water level over time.
Understanding the rate of change is crucial when working with linear functions:
  • It provides a direct measure of how quickly something changes.
  • It helps in forming the linear equation that models the scenario.
  • It allows you to predict future values.
For example, after 10 days, the water level is \(L(10) = 2.5 - 0.015 \times 10 = 2.35\) feet. This method applies to various real-world problems beyond just water levels, like finance (e.g., interest rates), physics (e.g., speed), and even biology (e.g., population decline).
Real-World Problems
Linear functions are extremely useful in solving real-world problems. They help model situations where there is a constant rate of change.
Let's consider our water level problem in context:
1. **Initial Condition**: The starting water level is 2.5 feet.
2. **Constant Rate**: Each day, the water level decreases by 0.015 feet.
3. **Function Formation**: Using these, we form the linear equation \(L(x) = 2.5 - 0.015x\).
4. **Inverse Application**: The inverse function \(L^{-1}(x) = \frac{2.5 - x}{0.015}\) allows us to determine how many days it will take to reach a specific water level.
These steps apply to various scenarios:
  • Predicting how long it takes for a reservoir to reach a certain water level.
  • Projecting the depletion of resources over time.
  • Analyzing financial investments or savings over a period.
By understanding these linear and inverse relationships, students are better equipped to apply mathematical concepts to everyday life, making them far more intuitive and practical.

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