Chapter 4: Problem 68
Simplify the expression. $$ \log _{\pi} 1 $$
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Chapter 4: Problem 68
Simplify the expression. $$ \log _{\pi} 1 $$
These are the key concepts you need to understand to accurately answer the question.
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Refer to the model \(Q(t)=Q_{0} e^{-0.000121 t}\) used in Example 5 for radiocarbon dating. At the "Marmes Man" archeological site in southeastern Washington State, scientist uncovered the oldest human remains yet to be found in Washington State. A sample from a human bone taken from the site showed that \(29.4 \%\) of the carbon-14 still remained. How old is the sample? Round to the nearest year.
A function of the form \(P(t)=a b^{t}\) represents the population of the given country \(t\) years after January 1,2000 . a. Write an equivalent function using base \(e\); that is, write a function of the form \(P(t)=P_{0} e^{k t} .\) Also, determine the population of each country for the year 2000 . $$\begin{array}{|l|c|c|c|} \hline \text { Country } & P(t)=a b^{t} & P(t)=P_{0} e^{k t} & \begin{array}{c} \text { Population } \\ \text { in } 2000 \end{array} \\ \hline \text { Haiti } & P(t)=8.5(1.0158)^{t} & & \\ \hline \text { Sweden } & P(t)=9.0(1.0048)^{t} & & \\ \hline \end{array}$$ b. The population of the two given countries is very close for the year 2000 , but their growth rates are different. Determine the year during which the population of each country will reach 10.5 million. c. Haiti had fewer people in the year 2000 than Sweden. Why did Haiti reach a population of 10.5 million sooner?
Graph the following functions on the window [-3,3,1] by [-1,8,1] and comment on the behavior of the graphs near $$ \begin{array}{l} x=0 \\ \mathrm{Y}_{1}=e^{x} \\ \mathrm{Y}_{2}=1+x+\frac{x^{2}}{2} \\ \mathrm{Y}_{3}=1+x+\frac{x^{2}}{2}+\frac{x^{3}}{6} \end{array} $$
(See Example 8 ) a. Estimate the value of the logarithm between two consecutive integers. For example, \(\log _{2} 7\) is between 2 and 3 because \(2^{2}<7<2^{3}\). b. Use the change-of-base formula and a calculator to approximate the logarithm to 4 decimal places. c. Check the result by using the related exponential form. $$ \log _{5} 3 $$
If \(k>0,\) the equation \(y=y_{0} e^{k t}\) is a model for exponential (growth/decay), whereas if \(k<0,\) the equation is a model for exponential (growth/decay).
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