/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 A one-to-one function is given. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A one-to-one function is given. Write an equation for the inverse function. \(t(x)=\frac{x-4}{x+2}\)

Short Answer

Expert verified
t^{-1}(x) = \frac{-4 - 2x}{x - 1}

Step by step solution

01

Understand the function

The given function is \(t(x) = \frac{x - 4}{x + 2}\). The task is to find its inverse.
02

Replace function notation

Replace \(t(x)\) with \(y\):\[ y = \frac{x - 4}{x + 2}\]
03

Swap variables

Swap \(x\) and \(y\) to solve for the inverse: \[ x = \frac{y - 4}{y + 2} \]
04

Solve for y

To find \(y\), multiply both sides by \(y + 2\) to clear the fraction: \[ x(y + 2) = y - 4 \] Distribute \(x\): \[ xy + 2x = y - 4 \] Move all terms involving \(y\) to one side: \[ xy - y = -4 - 2x \] Factor out \(y\) on the left side: \[ y(x - 1) = -4 - 2x \] Finally, isolate \(y\): \[ y = \frac{-4 - 2x}{x - 1} \]
05

Write the inverse function

Replace \(y\) with \(t^{-1}(x)\): \[ t^{-1}(x) = \frac{-4 - 2x}{x - 1} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-to-One Function
For a function to have an inverse, it must be a one-to-one function. This means that for every output value, there is exactly one corresponding input value.
A function passes the Horizontal Line Test if no horizontal line intersects its graph more than once. This is a quick way to check if a function is one-to-one.
For example, the given function is \( t(x) = \frac{x - 4}{x + 2} \), and to determine if it's one-to-one:
- If we pick different values for \( x \), they must yield different values of \( t(x) \).
- Conversely, for \( t(x) \) to be the same, the values of \( x \) must be the same as well.
Algebraic Manipulation
Algebraic manipulation involves rearranging equations to isolate a specific variable. This skill is essential for finding inverse functions.
Here’s how we manipulate the given function:
1. Start with the function \( t(x) = \frac{x - 4}{x + 2} \).
2. Replace \( t(x) \) with \( y \), giving us \( y = \frac{x - 4}{x + 2} \).
3. Swap \( x \) and \( y \) to solve for the inverse: \( x = \frac{y - 4}{y + 2} \).
4. Multiply both sides by \( y + 2 \) to clear the denominator: \( x(y + 2) = y - 4 \).
5. Distribute \( x \): \( xy + 2x = y - 4 \).
6. Combine like terms to get: \( xy - y = -4 - 2x \).
7. Factor out \( y \): \( y(x - 1) = -4 - 2x \).
8. Finally, isolate \( y \): \( y = \frac{-4 - 2x}{x - 1} \).
Function Notation
Function notation is a way to represent functions and their inverses concisely.
In function notation, the original function is written as \( t(x) \), where \( t \) represents the function, and \( x \) is the input variable.
For our specific problem, the function \( t(x) \) represents the formula \( \frac{x - 4}{x + 2} \).
When finding the inverse of a function, we use \( t^{-1}(x) \) notation for the inverse.
The inverse function \( t^{-1}(x) \) essentially reverses the effect of \( t(x) \). Hence, if \( t(x) = y \), then \( t^{-1}(y)\) will return \( x \).
Using function notation helps us understand the relationship between inputs and outputs clearly. It also allows us to conduct algebraic manipulations more systematically and confirm our final equation for the inverse function: \( t^{-1}(x) = \frac{-4 - 2x}{x - 1} \).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A function of the form \(P(t)=a b^{t}\) represents the population of the given country \(t\) years after January 1,2000 . a. Write an equivalent function using base \(e\); that is, write a function of the form \(P(t)=P_{0} e^{k t} .\) Also, determine the population of each country for the year 2000 . $$\begin{array}{|l|c|c|c|} \hline \text { Country } & P(t)=a b^{t} & P(t)=P_{0} e^{k t} & \begin{array}{c} \text { Population } \\ \text { in } 2000 \end{array} \\ \hline \text { Haiti } & P(t)=8.5(1.0158)^{t} & & \\ \hline \text { Sweden } & P(t)=9.0(1.0048)^{t} & & \\ \hline \end{array}$$ b. The population of the two given countries is very close for the year 2000 , but their growth rates are different. Determine the year during which the population of each country will reach 10.5 million. c. Haiti had fewer people in the year 2000 than Sweden. Why did Haiti reach a population of 10.5 million sooner?

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(\log _{3} y+\log _{3}(y+6)=3\)

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(\log _{4}(5 x-13)=1+\log _{4}(x-2)\)

Determine if the statement is true or false. For each false statement, provide a counterexample. For example, \(\log (x+y) \neq \log x+\log y\) because \(\log (2+8) \neq \log 2+\log 8\) (the left side is 1 and the right side is approximately 1.204 ). $$ \log (x y)=(\log x)(\log y) $$

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(\log _{7}(12-t)=\log _{7}(t+6)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.