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Simplify the expression. $$ \log _{1 / 4} 16 $$

Short Answer

Expert verified
\text{log}_{\frac{1}{4}} 16 = -2

Step by step solution

01

Understanding the Logarithm Basics

Rewrite the expression \(\text{log}_{\frac{1}{4}} 16\) in terms of logarithms. Here, we need to find the exponent to which \(\frac{1}{4}\) must be raised to get 16.
02

Change the Base

Convert \(\frac{1}{4}\) into a power of 4. \(\frac{1}{4} = 4^{-1}\).
03

Set Up the Equation

Now the expression becomes \(\text{log}_{4^{-1}} 16\).
04

Simplify the Logarithm

Recall the change of base formula for logarithms: \(\text{log}_{a^b} c = \frac{1}{b} \text{log}_a c\). Applying this here: \(\text{log}_{4^{-1}} 16 = \frac{1}{-1} \text{log}_4 16\).
05

Evaluate the Simplified Logarithm

Recognize that \(16 = 4^2\). Thus, \(\text{log}_4 16 = \text{log}_4 (4^2)\).
06

Use the Power Rule

Using the power rule of logarithms: \(\text{log}_a (a^b) = b\). Therefore, \(\text{log}_4 (4^2) = 2\).
07

Final Simplification

Substitute back into \(\frac{1}{-1} \text{log}_4 16\). Now we have \(\frac{1}{-1} \times 2 = -2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change of Base Formula
The change of base formula is essential when working with logarithms. It allows you to convert a logarithm of any base into a logarithm of another base. This can make solving logarithmic equations much simpler. The formula is:
\[ \text{log}_a b = \frac{\text{log}_c b}{\text{log}_c a} \]
Here, 'a' is the original base, 'b' is the number, and 'c' is the new base you are changing to. In our exercise, we used it to simplify the expression from \[ \text{log}_{4^{-1}} 16 \] to \[ \frac{1}{-1} \text{log}_4 16. \]Remember, you can choose any convenient base 'c', often base 10 or the natural logarithm base 'e' is used. This formula is particularly useful when the original base is not simple to work with.
Logarithm Power Rule
The logarithm power rule simplifies logarithms involving exponents. According to this rule: \[ \text{log}_a (b^c) = c \text{log}_a b. \]In simple terms, you can move the exponent in front of the logarithm. In our step-by-step solution, we applied this rule to \[ \text{log}_4 (4^2). \]We simplified it to \[ 2 \text{log}_4 4. \]Because \[ \text{log}_4 4 = 1, \] the expression simplified to 2.
This rule is powerful when dealing with complex logarithmic expressions involving exponents. It helps break down the expression into simpler components, making it easier to solve.
Properties of Logarithms
Properties of logarithms are a set of rules that help simplify logarithmic expressions. Some of the most important properties include:
  • Product Rule: \[ \text{log}_a (bc) = \text{log}_a b + \text{log}_a c \]
  • Quotient Rule: \[ \text{log}_a \frac{b}{c} = \text{log}_a b - \text{log}_a c \]
  • Power Rule: \[ \text{log}_a (b^c) = c \text{log}_a b \]
  • Change of Base Formula: \[ \text{log}_a b = \frac{\text{log}_c b}{\text{log}_c a} \]
We used some of these properties in the exercise solution. For instance, the power rule and change of base formula made it easier to simplify the given logarithmic expression. Understanding these properties helps you quickly rewrite and solve various logarithmic expressions.
Exponent Rules
Exponent rules play a key role when working with logarithms since logarithms are inherently related to exponents. Some essential exponent rules are:
  • Product of Powers: \[ a^m \times a^n = a^{m+n} \]
  • Quotient of Powers: \[ \frac{a^m}{a^n} = a^{m-n} \]
  • Power of a Power: \[ (a^m)^n = a^{mn} \]
  • Negative Exponent: \[ a^{-n} = \frac{1}{a^n} \]
In our exercise, rules like converting \[ \frac{1}{4} \] to \[ 4^{-1} \] and recognizing that 16 can be written as \[ 4^2 \] are key exponential concepts. Mastering these rules helps in converting between different forms and simplifying logarithmic expressions effectively.

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Most popular questions from this chapter

A table of data is given. a. Graph the points and from visual inspection, select the model that would best fit the data. Choose from $$\begin{array}{ll} y=m x+b \text { (linear) } & y=a b^{x} \text { (exponential) } \\ y=a+b \ln x \text { (logarithmic) } & y=\frac{c}{1+a e^{-b x}} \text { (logistic) } \end{array}$$ b. Use a graphing utility to find a function that fits the data. $$ \begin{array}{|c|c|} \hline x & y \\ \hline 3 & 2.7 \\ \hline 7 & 12.2 \\ \hline 13 & 25.7 \\ \hline 15 & 30 \\ \hline 17 & 34 \\ \hline 21 & 44.4 \\ \hline \end{array} $$

Determine if the statement is true or false. For each false statement, provide a counterexample. For example, \(\log (x+y) \neq \log x+\log y\) because \(\log (2+8) \neq \log 2+\log 8\) (the left side is 1 and the right side is approximately 1.204 ). $$ \ln 10=\frac{1}{\log e} $$

Refer to the model \(Q(t)=Q_{0} e^{-0.000121 t}\) used in Example 5 for radiocarbon dating. At the "Marmes Man" archeological site in southeastern Washington State, scientist uncovered the oldest human remains yet to be found in Washington State. A sample from a human bone taken from the site showed that \(29.4 \%\) of the carbon-14 still remained. How old is the sample? Round to the nearest year.

a. Graph \(f(x)=\ln x\) and \(g(x)=(x-1)-\frac{(x-1)^{2}}{2}+\frac{(x-1)^{3}}{3}-\frac{(x-1)^{4}}{4}\) on the viewing window [-2,4,1] by [-5,2,1] . How do the graphs compare on the interval (0,2) ? b. Use function \(g\) to approximate \(\ln 1.5\). Round to 4 decimal places.

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(\log _{4}(5 x-13)=1+\log _{4}(x-2)\)

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