Chapter 4: Problem 47
Simplify the expression. $$ \ln \left(\frac{1}{e^{3}}\right) $$
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Chapter 4: Problem 47
Simplify the expression. $$ \ln \left(\frac{1}{e^{3}}\right) $$
These are the key concepts you need to understand to accurately answer the question.
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A table of data is given. a. Graph the points and from visual inspection, select the model that would best fit the data. Choose from $$\begin{array}{ll} y=m x+b \text { (linear) } & y=a b^{x} \text { (exponential) } \\ y=a+b \ln x \text { (logarithmic) } & y=\frac{c}{1+a e^{-b x}} \text { (logistic) } \end{array}$$ b. Use a graphing utility to find a function that fits the data. $$ \begin{array}{|c|c|} \hline x & y \\ \hline 0 & 2.3 \\ \hline 4 & 3.6 \\ \hline 8 & 5.7 \\ \hline 12 & 9.1 \\ \hline 16 & 14 \\ \hline 20 & 22 \\ \hline \end{array} $$
Two million \(E\). coli bacteria are present in a laboratory culture. An antibacterial agent is introduced and the population of bacteria \(P(t)\) decreases by half every \(6 \mathrm{hr}\). The population can be represented by \(P(t)=2,000,000\left(\frac{1}{2}\right)^{t / 6}\) a. Convert this to an exponential function using base \(e\). b. Verify that the original function and the result from part (a) yield the same result for \(P(0), P(6), P(12)\), and \(P(60) .\) (Note: There may be round- off error.)
The population of Canada \(P(t)\) (in millions) since January \(1,1900,\) can be approximated by $$P(t)=\frac{55.1}{1+9.6 e^{-0.02515 t}}$$ where \(t\) is the number of years since January 1,1900 . a. Evaluate \(P(0)\) and interpret its meaning in the context of this problem. b. Use the function to predict the Canadian population on January \(1,2015 .\) Round to the nearest million. c. Use the function to predict the Canadian population on January 1,2040 . d. Determine the year during which the Canadian population will reach 45 million. e. What value will the term \(\frac{9.6}{e^{0.02515 t}}\) approach as \(t \rightarrow \infty\) ? f. Determine the limiting value of \(P(t)\).
Write \(10^{2 x-4}=80,600\) in logarithmic form.
Solve the equation. Write the solution set with the exact values given in terms of common or natural logarithms. Also give approximate solutions to 4 decimal places. \(1024=19^{x}+4\)
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