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Use the definition of a one-to-one function to determine if the function is one-to-one. \(g(x)=x^{3}+8\)

Short Answer

Expert verified
The function \(g(x) = x^3 + 8\) is one-to-one.

Step by step solution

01

Understand the Definition

A function is one-to-one if and only if different inputs map to different outputs. Mathematically, if for all pairs of elements \(a\) and \(b\) in the domain of the function, \(g(a) = g(b)\) implies \(a = b\), then the function is one-to-one.
02

Set Up the Equation

Assume \(g(a) = g(b)\). Substitute the function definition: \[ a^3 + 8 = b^3 + 8 \]
03

Simplify the Equation

Subtract 8 from both sides to simplify: \[ a^3 = b^3 \]
04

Solving for a and b

Take the cube root of both sides: \[ a = b \] Thus, if \(g(a) = g(b)\), this implies \(a = b\).
05

Conclusion

Since \(g(a) = g(b)\) implies \(a = b\), the function \(g(x) = x^3 + 8\) is one-to-one according to the definition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Function Definition
A function is a relationship between a set of inputs and a set of outputs such that each input is related to exactly one output. In other words, for every input value, there is one and only one output value. For example, if you have a function, let’s call it \(f(x)\), then an input \(x\) will produce exactly one output \(f(x)\). This function can be represented as a mapping or a rule that assigns each input to a precise output. For instance, in the function \(g(x) = x^3 + 8\), for any given value of \(x\), the function gives a unique output calculating \(x^3 + 8\).
Keep in mind that different functions have different rules, and their behaviors can vary widely depending on their equations. Some functions can be linear, while others may be polynomial, trigonometric, or even exponential.
Determining Whether a Function is One-to-One
A function is considered one-to-one (injective) if it never assigns the same output value to two different input values. To determine if a function is one-to-one, you can use the following approach:
- Assume that \(g(a) = g(b)\).
- Show that this implies \(a = b\).
For the function \(g(x) = x^3 + 8\), assume \(g(a) = g(b)\).
Substituting the function: \(a^3 + 8 = b^3 + 8\).
Simplify by subtracting 8 from both sides: \(a^3 = b^3\).
Take the cube root of both sides to get \(a = b\).
Hence, whenever \(g(a) = g(b)\), it must be the case that \(a = b\). Therefore, the function \(g(x) = x^3 + 8\) is one-to-one. This means that no two different input values will produce the same output value.
Simplifying with Cube Root
When dealing with polynomial functions, such as cubics, simplifying the equation can be very helpful. In the case of the function \(g(x) = x^3 + 8\), we encounter cube roots during simplification. Suppose we have the equation \(a^3 = b^3\). To solve for \(a\) and \(b\), we take the cube root of both sides:
\[-a^3 = b^3 \]
By taking the cube root of both sides: \[-a = b \]
The cube root function is the inverse of the cube function (raising to the power of three). Therefore, taking the cube root undoes the cubing action, simplifying our equation to its basis elements, \(a\) and \(b\). This step is key in verifying that \(a = b\) whenever \(g(a) = g(b)\), solidifying our confirmation that the function is indeed one-to-one.
Exploring Function Properties
Functions have various properties that define their behavior. Some of these important properties that you might explore include:
- **Domain and Range**: The domain is the set of all possible input values (\(x\)-values) for the function, while the range is the set of all possible output values (\(y\)-values).
- **Injectivity (One-to-One)**: A function is one-to-one if each output is produced by exactly one input.
- **Surjectivity (Onto)**: A function is onto if every possible output is covered by the function.
- **Bijectivity**: A function is bijective if it is both one-to-one and onto. Such functions have an inverse function.
- **Continuity**: A function is continuous if there are no breaks or gaps in its graph.
Understanding these properties helps us analyze functions more effectively. In the case of our function \(g(x) = x^3 + 8\), it is essential first to establish that it is one-to-one. From there, we can delve into other properties like its continuity (it is continuous for all real numbers as it’s a cubic function). Having a solid grasp of these concepts will enhance your ability to work with various functions confidently.

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Most popular questions from this chapter

After a new product is launched the cumulative sales \(S(t)\) (in \(\$ 1000) t\) weeks after launch is given by: $$S(t)=\frac{72}{1+9 e^{-0.36 t}}$$ a. Determine the cumulative amount in sales 3 weeks after launch. Round to the nearest thousand. b. Determine the amount of time required for the cumulative sales to reach \(\$ 70,000\). c. What is the limiting value in sales?

A function of the form \(P(t)=a b^{t}\) represents the population of the given country \(t\) years after January 1,2000 . a. Write an equivalent function using base \(e\); that is, write a function of the form \(P(t)=P_{0} e^{k t} .\) Also, determine the population of each country for the year 2000 . $$\begin{array}{|l|c|c|c|} \hline \text { Country } & P(t)=a b^{t} & P(t)=P_{0} e^{k t} & \begin{array}{c} \text { Population } \\ \text { in } 2000 \end{array} \\ \hline \text { Haiti } & P(t)=8.5(1.0158)^{t} & & \\ \hline \text { Sweden } & P(t)=9.0(1.0048)^{t} & & \\ \hline \end{array}$$ b. The population of the two given countries is very close for the year 2000 , but their growth rates are different. Determine the year during which the population of each country will reach 10.5 million. c. Haiti had fewer people in the year 2000 than Sweden. Why did Haiti reach a population of 10.5 million sooner?

(See Example 8 ) a. Estimate the value of the logarithm between two consecutive integers. For example, \(\log _{2} 7\) is between 2 and 3 because \(2^{2}<7<2^{3}\). b. Use the change-of-base formula and a calculator to approximate the logarithm to 4 decimal places. c. Check the result by using the related exponential form. $$ \log _{3} 15 $$

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