/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 130 Compare the graphs of the functi... [FREE SOLUTION] | 91Ó°ÊÓ

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Compare the graphs of the functions. $$ \mathrm{Y}_{1}=\ln \left(\frac{x}{2}\right) \quad \text { and } \quad \mathrm{Y}_{2}=\ln x-\ln 2 $$

Short Answer

Expert verified
The graphs of \(\text{Y}_1\) and \(\text{Y}_2\) are identical.

Step by step solution

01

Rewrite \(\text{Y}_2\)

Rewrite the given function \(\text{Y}_2\) using the property of logarithms, \(\text{ln} a - \text{ln} b = \text{ln} \frac{a}{b}\). Thus, \(\text{Y}_2 = \text{ln} x - \text{ln} 2\) becomes \(\text{Y}_2 = \text{ln} \frac{x}{2}\).
02

Compare \(\text{Y}_1\) and \(\text{Y}_2\)

Observe that after rewriting \(\text{Y}_2\), it becomes identical to \(\text{Y}_1\). So, \(\text{Y}_1 = \text{ln} \frac{x}{2}\) and \(\text{Y}_2 = \text{ln} \frac{x}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithmic properties
Logarithmic properties are rules that make it easier to work with logarithmic functions. They help simplify complex expressions and solve exponential equations. There are three main properties to focus on:
  • Product Property: \(\text{ln}(ab) = \text{ln}(a) + \text{ln}(b)\)
  • Quotient Property: \(\text{ln} \frac{a}{b} = \text{ln}(a) - \text{ln}(b)\)
  • Power Property: \(\text{ln}(a^b) = b \text{ln}(a)\)
In this exercise, we specifically use the quotient property to rewrite the logarithmic function. This property states that the logarithm of a quotient is the difference of the logarithms. For \(Y_2 = \text{ln} x - \text{ln} 2\), we use the quotient property to transform it into \(Y_2 = \text{ln}\frac{x}{2}\). Understanding these properties is crucial for working with logarithmic functions efficiently.
logarithmic functions
Logarithmic functions are the inverse of exponential functions. They are of the form \(y = \text{ln}(x)\), where \(y\) is the logarithm of \(x\) to the base \(e\) (Euler's number). This means if \(y = \text{ln}(x)\), then \(e^y = x\). Here are some key points about logarithmic functions:
  • The domain is \(x>0\).
  • The range is all real numbers.
  • The graph passes through (1, 0) because \( \text{ln}(1) = 0 \).
In the exercise, \(Y_1\) and \(Y_2\) are both logarithmic functions, where \(Y_1 = \text{ln} \frac{x}{2}\) and \(Y_2 = \text{ln} x - \text{ln} 2\). The properties of logarithms make them easier to compare and simplify.
graphing functions
Graphing logarithmic functions involves plotting points that satisfy the equation. Here's how to proceed:
1. Create a table of values for \(x\) and compute corresponding \(y\) values.
2. Plot these points on a coordinate plane.
3. Connect the points with a smooth curve.
For \(Y_1 = \text{ln} \frac{x}{2}\), you might choose values for \(x\) like 1, 2, 4, etc., and then calculate \(y\).
Graphing \(Y_2 = \text{ln} x - \text{ln} 2\) will produce the same graph because, given logarithmic properties, \(Y_2 = \text{ln} \frac{x}{2}\). Therefore, \(Y_1\) and \(Y_2\) are identical functions with identical graphs. Their graph is a smooth curve that increases slowly as \(x\) increases and passes through the point (1, -\text{ln}(2)).
algebraic manipulation
Algebraic manipulation involves using mathematical techniques to simplify expressions or solve equations. For logarithmic functions, it includes applying logarithmic properties to rewrite and simplify expressions. In the exercise, we manipulated \(Y_2 = \text{ln} x - \text{ln} 2\) using:
  • The quotient property: \( \text{ln} \frac{a}{b} = \text{ln} a - \text{ln} b \)
This simplification allows us to directly compare \(Y_2\) to \(Y_1\). Identifying and utilizing these properties can make complex logarithmic expressions more approachable. It helps with solving equations and comparing functions, as seen with \(Y_1\) and \(Y_2\) yielding the same function.

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Most popular questions from this chapter

(See Example 8 ) a. Estimate the value of the logarithm between two consecutive integers. For example, \(\log _{2} 7\) is between 2 and 3 because \(2^{2}<7<2^{3}\). b. Use the change-of-base formula and a calculator to approximate the logarithm to 4 decimal places. c. Check the result by using the related exponential form. $$ \log _{2} 15 $$

The isotope of plutonium \({ }^{238} \mathrm{Pu}\) is used to make thermoelectric power sources for spacecraft. Suppose that a space probe is launched in 2012 with \(2.0 \mathrm{~kg}\) of \({ }^{238} \mathrm{Pu}\) a. If the half-life of \({ }^{238} \mathrm{Pu}\) is \(87.7 \mathrm{yr}\), write a function of the form \(Q(t)=Q_{0} e^{-k t}\) to model the quantity \(Q(t)\) of \({ }^{238} \mathrm{Pu}\) left after \(t\) years. b. If \(1.6 \mathrm{~kg}\) of \({ }^{238} \mathrm{Pu}\) is required to power the spacecraft's data transmitter, for how long will scientists be able to receive data? Round to the nearest year.

After a new product is launched the cumulative sales \(S(t)\) (in \(\$ 1000) t\) weeks after launch is given by: $$S(t)=\frac{72}{1+9 e^{-0.36 t}}$$ a. Determine the cumulative amount in sales 3 weeks after launch. Round to the nearest thousand. b. Determine the amount of time required for the cumulative sales to reach \(\$ 70,000\). c. What is the limiting value in sales?

Solve for the indicated variable. \(A=P(1+r)^{t}\) for \(t\) (used in finance)

9\. The population of the United States \(P(t)\) (in millions) since January 1,1900 , can be approximated by $$P(t)=\frac{725}{1+8.295 e^{-0.0165 t}}$$ where \(t\) is the number of years since January \(1,1900 .\) (See Example 6\()\) a. Evaluate \(P(0)\) and interpret its meaning in the context of this problem. b. Use the function to predict the U.S. population on January \(1,2020 .\) Round to the nearest million. c. Use the function to predict the U.S. population on January 1,2050 . d. Determine the year during which the U.S. population will reach 500 million. e. What value will the term \(\frac{8.295}{e^{0.0165 t}}\) approach as \(t \rightarrow \infty\) ? f. Determine the limiting value of \(P(t)\).

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