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A relation in \(x\) and \(y\) is given. Determine if the relation defines \(y\) as a one-to-one function of \(x\). $$\\{(-14,1),(-2,3),(7,4),(-9,-2)\\}$$

Short Answer

Expert verified
Yes, the relation is one-to-one.

Step by step solution

01

Understand the Definition of a One-to-One Function

A function is one-to-one if each value of the dependent variable (output) is paired with exactly one unique value of the independent variable (input). This means that no two different inputs should map to the same output.
02

Identify the Pairs in the Given Relation

List out the given pairs: \[(-14, 1), (-2, 3), (7, 4), (-9, -2)\]
03

Check for Repeated Outputs

Examine the output (or y-values) of each pair to see if any value occurs more than once. The outputs in the given relation are: 1, 3, 4, and -2.
04

Determine if the Relation is One-to-One

Since each output value (1, 3, 4, -2) is unique and paired with a unique input, the relation is one-to-one.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relation in Mathematics
In mathematics, a **relation** is a set of ordered pairs \((x, y)\). Each pair represents a connection between two elements, where the first element is from one set (often called the domain) and the second element is from another set (often called the range). Relations describe how elements from these sets are associated with each other.

For example, let's say we have a relation given by the pairs \((-14,1), (-2,3), (7,4), (-9,-2)\). Each pair links an \(x\) value with a \(y\) value. The first element in each pair is from the domain (independent variable), and the second element is from the range (dependent variable).

Relations can be visualized using graphs or mapping diagrams, making it easier to see how each element is connected. Understanding relations is crucial as they lay the foundation for more complex concepts like functions and mappings.
Dependent and Independent Variables
Variables in mathematics can be categorized as either **dependent** or **independent**. The **independent variable** (often represented by \(x\)) is the variable that we change or control, and the **dependent variable** (often represented by \(y\)) is the variable that depends on the independent variable.

In the context of a relation \((x, y)\), \((x\) is the independent variable and \((y\) is the dependent variable. This means that the value of \((y\) depends on the value of \((x\).

For the given relation \((-14, 1), (-2, 3), (7, 4), (-9, -2)\), we can see that changing \((x\) will affect \(y\). Each unique \((x\) value corresponds to a particular \(y\) value, illustrating the dependent relationship. Understanding the roles of these variables helps in analyzing and interpreting mathematical relations and functions effectively.
Unique Values in Functions
A function is a special type of relation where every input (independent variable \(x\)) is associated with a unique output (dependent variable \(y\)). This means that in a function, no two different inputs map to the same output.

When we talk about **unique values in functions**, we refer to the property that each \((x\) value has exactly one corresponding \((y\) value. This property is crucial in determining whether a relation is a function and whether it is **one-to-one**.

For the given relation \((-14, 1), (-2, 3), (7, 4), (-9, -2)\), each \((y\) value (1, 3, 4, -2) is unique and corresponds to a unique \((x\) value. This demonstrates that the relation is not only a function but a one-to-one function because there are no repeated outputs. Identifying unique values in functions ensures that we understand the relationship between inputs and outputs thoroughly.

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Most popular questions from this chapter

Determine if the statement is true or false. For each false statement, provide a counterexample. For example, \(\log (x+y) \neq \log x+\log y\) because \(\log (2+8) \neq \log 2+\log 8\) (the left side is 1 and the right side is approximately 1.204 ). $$ \ln 10=\frac{1}{\log e} $$

a. The populations of two countries are given for January 1,2000 , and for January 1,2010 . Write a function of the form \(P(t)=P_{0} e^{k t}\) to model each population \(P(t)\) (in millions) \(t\) years after January 1, 2000.$$ \begin{array}{|l|c|c|c|} \hline & \begin{array}{c} \text { Population } \\ \text { in 2000 } \\ \text { (millions) } \end{array} & \begin{array}{c} \text { Population } \\ \text { in 2010 } \\ \text { (millions) } \end{array} & \boldsymbol{P}(t)=\boldsymbol{P}_{0} e^{k t} \\ \hline \text { Switzerland } & 7.3 & 7.8 & \\ \hline \text { Israel } & 6.7 & 7.7 & \\ \hline \end{array}$$ b. Use the models from part (a) to predict the population on January \(1,2020,\) for each country. Round to the nearest hundred thousand. c. Israel had fewer people than Switzerland in the year 2000 , yet from the result of part (b), Israel will have more people in the year \(2020 ?\) Why? d. Use the models from part (a) to predict the year during which each population will reach 10 million if this trend continues.

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(2 \ln (4-3 t)+1=7\)

Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. \(\log (p+17)=4.1\)

Use the model \(A=P e^{r t} .\) The variable \(A\) represents the future value of \(P\) dollars invested at an interest rate \(r\) compounded continuously for \(t\) years. If \(\$ 10,000\) is invested in an account earning \(5.5 \%\) interest compounded continuously, determine how long it will take the money to triple. Round to the nearest year.

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