Chapter 3: Problem 79
Find the value of \(b\) or \(c\) that gives the function the given minimum or maximum value. $$ f(x)=-x^{2}+b x+4 ; \text { maximum value } 8 $$
Short Answer
Expert verified
The value of \( b \) is \( 4 \) or \( -4 \).
Step by step solution
01
Recognize the Form of the Quadratic Function
The given quadratic function is in the form: \[ f(x) = -x^2 + bx + 4 \]It is a parabola opening downwards (because the coefficient of \(x^2\) is negative).
02
Determine the Vertex Form
For any quadratic function in the form \( ax^2 + bx + c \), the maximum or minimum value occurs at \( x = -\frac{b}{2a} \). Here, \( a = -1 \) and \( b = b \). Therefore,\[ x = -\frac{b}{2(-1)} = \frac{b}{2} \]
03
Substitute \( x = \frac{b}{2} \) in the Function
Substitute \( x = \frac{b}{2} \) back into the function to find the maximum value:\[ f\left( \frac{b}{2} \right) = -\left( \frac{b}{2} \right)^2 + b \left( \frac{b}{2} \right) + 4 \]
04
Simplify the Expression
Simplify the expression:\[ f\left( \frac{b}{2} \right) = -\left( \frac{b^2}{4} \right) + \left( \frac{b^2}{2} \right) + 4 \]Combine like terms:\[ -\frac{b^2}{4} + \frac{2b^2}{4} + 4 = \frac{b^2}{4} + 4 \]
05
Set Maximum Value and Solve for \( b \)
Set the simplified expression equal to the maximum value given in the problem (8):\[ \frac{b^2}{4} + 4 = 8 \]Solve for \( b \):\[ \frac{b^2}{4} = 4 \]Multiply both sides by 4:\[ b^2 = 16 \]Take the square root of both sides:\[ b = \pm 4 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
vertex form of a quadratic function
Understanding the vertex form of a quadratic function is essential for solving problems related to maximum and minimum values. The vertex form of a quadratic function can be written as: \[ f(x) = a(x-h)^2 + k \]where \( (h, k) \) is the vertex of the parabola.
- If \( a \) is positive, the parabola opens upwards.
- If \( a \) is negative, the parabola opens downwards.
solving quadratic equations
Solving quadratic equations involves finding the values of \( x \) that satisfy the equation \( ax^2 + bx + c = 0 \). There are several methods to solve them, including:
- Factoring: Expressing the quadratic as a product of linear factors, if possible.
- Completing the Square: Rewriting the quadratic in the form \( (x-h)^2 = k \).
- Quadratic Formula: Using \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to find the roots.
parabola properties
The properties of a parabola are crucial in understanding its shape, direction, and extreme values (maximum or minimum). Some key properties include:
- Direction: As mentioned earlier, the sign of \( a \) in \( ax^2 + bx + c \) determines if the parabola opens upwards (\( a > 0 \)) or downwards (\( a < 0 \)).
- Vertex: The highest or lowest point on the parabola, depending on the direction.
- Axis of Symmetry: The vertical line that passes through the vertex, dividing the parabola into two symmetrical halves. It is given by \( x = -\frac{b}{2a} \) in the standard form.
- Intercepts: Points where the parabola crosses the x-axis (roots) and y-axis. These intercepts help in graphing and understanding the parabola's behavior.
vertex of a parabola
The vertex of a parabola is a critical point providing essential information about the function's extreme values. For a given quadratic function \( ax^2 + bx + c \), the vertex can be found using: \[ x = -\frac{b}{2a} \]This formula tells us the x-coordinate of the vertex. To find the y-coordinate (the actual maximum or minimum value), substitute this x back into the original function: \[ f\left(-\frac{b}{2a}\right) \]For our problem, following these steps gave us the correct value of \( b \) that maximized the function. Understanding the vertex helps in graphing the parabola accurately and in solving optimization problems, as seen in our exercise.